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Data Analytics

Data Analytics

رفتن به کانال در Telegram

Perfect channel to learn Data Analytics Learn SQL, Python, Alteryx, Tableau, Power BI and many more For Promotions: @coderfun @love_data

نمایش بیشتر

📈 تحلیل کانال تلگرام Data Analytics

کانال Data Analytics (@sqlspecialist) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 109 631 مشترک است و جایگاه 1 124 را در دسته فناوری و برنامه‌ها و رتبه 2 395 را در منطقه الهند دارد.

📊 شاخص‌های مخاطب و پویایی

از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 109 631 مشترک جذب کرده است.

بر اساس آخرین داده‌ها در تاریخ 17 ژوئن, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر 689 و در ۲۴ ساعت گذشته برابر -19 بوده و همچنان دسترسی گسترده‌ای حفظ شده است.

  • وضعیت تأیید: تأیید نشده
  • نرخ تعامل (ER): میانگین تعامل مخاطب 3.31% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 1.51% واکنش نسبت به کل مشترکان کسب می‌کند.
  • دسترسی پست‌ها: هر پست به طور میانگین 3 624 بازدید دریافت می‌کند. در اولین روز معمولاً 1 658 بازدید جمع‌آوری می‌شود.
  • واکنش‌ها و تعامل: مخاطبان به‌طور فعال حمایت می‌کنند؛ میانگین واکنش به هر پست 7 است.
  • علایق موضوعی: محتوا بر موضوعات کلیدی مانند row, sql, analytic, analyst, visualization تمرکز دارد.

📝 توضیح و سیاست محتوایی

نویسنده این فضا را محل بیان دیدگاه‌های شخصی توصیف می‌کند:
Perfect channel to learn Data Analytics Learn SQL, Python, Alteryx, Tableau, Power BI and many more For Promotions: @coderfun @love_data

به لطف به‌روزرسانی‌های پرتکرار (آخرین داده در تاریخ 18 ژوئن, 2026)، کانال همواره به‌روز و دارای دسترسی بالاست. تحلیل‌ها نشان می‌دهد مخاطبان به‌طور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته فناوری و برنامه‌ها تبدیل کرده‌اند.

109 631
مشترکین
-1924 ساعت
+2267 روز
+68930 روز
آرشیو پست ها
🔥 Now, let’s move to the next topic of SQL RoadmapSubqueries (Nested Queries) 🧠 1. What is a Subquery? A subquery is a query inside another query 👉 Think like this: “First get some data → then use that result in another query” 📊 Basic Example 👉 Find employees earning above average salary SELECT FROM employees WHERE salary > ( SELECT AVG(salary) FROM employees ); 👉 Inner query → gives average salary 👉 Outer query → filters employees ⚡ 2. Types of Subqueries 🔹 Single Row Subquery Returns only one value SELECT FROM employees WHERE salary > (SELECT AVG(salary) FROM employees); 🔹 Multiple Row Subquery Returns multiple values SELECT FROM employees WHERE dept_id IN ( SELECT dept_id FROM departments ); 🎯 3. Subquery with IN SELECT name FROM employees WHERE dept_id IN ( SELECT dept_id FROM departments WHERE dept_name = 'IT' ); ✔ Finds employees in IT department ⚡ 4. Subquery with EXISTS SELECT name FROM employees e WHERE EXISTS ( SELECT 1 FROM departments d WHERE e.dept_id = d.dept_id ); ✔ Checks if matching record exists 🚨 5. Important Difference IN -> Compares values & Slower with large data EXISTS -> Checks existence & Faster with large data 🎯 6. Practice Tasks 1. Find employees with salary > average salary 2. Find employees in IT department using subquery 3. Get departments that have employees 4. Find employees with max salary 5. Get employees not in HR department 🔥 Here are the solutions for Subqueries practice tasks ✅ 1. Find employees with salary > average salary SELECT FROM employees WHERE salary > ( SELECT AVG(salary) FROM employees ); ✅ 2. Find employees in IT department using subquery SELECT FROM employees WHERE dept_id IN ( SELECT dept_id FROM departments WHERE dept_name = 'IT' ); ✅ 3. Get departments that have employees SELECT FROM departments WHERE dept_id IN ( SELECT dept_id FROM employees ); 👉 Alternative (using EXISTS): SELECT FROM departments d WHERE EXISTS ( SELECT 1 FROM employees e WHERE d.dept_id = e.dept_id ); ✅ 4. Find employees with max salary SELECT FROM employees WHERE salary = ( SELECT MAX(salary) FROM employees ); ✅ 5. Get employees not in HR department SELECT FROM employees WHERE dept_id NOT IN ( SELECT dept_id FROM departments WHERE dept_name = 'HR' ); ⚡ Mini Challenge 🔥 👉 Find employees earning second highest salary using subquery ⚡ Mini Challenge Solution 🔥 SELECT FROM employees WHERE salary = ( SELECT MAX(salary) FROM employees WHERE salary < ( SELECT MAX(salary) FROM employees ) ); 🔥 Pro Tip: If question says: 👉 “above average”, “max”, “second highest” → Think Subquery instantly 💯 Double Tap ❤️ For More

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What will this query return? SELECT e.name, d.dept_name FROM employees e LEFT JOIN departments d ON e.dept_id = d.dept_id WHERE d.dept_name = 'IT';
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What will this query return? SELECT COUNT(*) FROM employees e LEFT JOIN departments d ON e.dept_id = d.dept_id;
Anonymous voting

What is the difference? -- Query 1 SELECT COUNT(*) FROM employees e INNER JOIN departments d ON e.dept_id = d.dept_id; -- Query 2 SELECT COUNT(*) FROM employees e LEFT JOIN departments d ON e.dept_id = d.dept_id;
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Find departments with NO employees — which is correct?
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How to find records with NO match in JOIN?
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What will LEFT JOIN return?
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What does INNER JOIN return?
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🔥Now, let’s move to the most important SQL topic — JOINS 💯🔥 🧠 1. What is a JOIN? JOIN is used to combine data from multiple tables 👉 If data is stored in different tables → JOIN helps you connect them 📊 Example Tables 👨‍💼 employees emp_id name dept_id 1 Amit 101 2 Neha 102 3 Ravi 101 🏢 departments dept_id dept_name 101 IT 102 HR 🔗 2. INNER JOIN (Most Used 🔥) 👉 Returns only matching records SELECT e.name, d.dept_name FROM employees e INNER JOIN departments d ON e.dept_id = d.dept_id; ✔ Only employees with valid department ⬅️ 3. LEFT JOIN 👉 Returns all records from left table + matched from right SELECT e.name, d.dept_name FROM employees e LEFT JOIN departments d ON e.dept_id = d.dept_id; ✔ Even if department is missing → employee will still show ➡️ 4. RIGHT JOIN 👉 Returns all records from right table + matched from left SELECT e.name, d.dept_name FROM employees e RIGHT JOIN departments d ON e.dept_id = d.dept_id; 🔄 5. FULL JOIN 👉 Returns all records from both tables SELECT e.name, d.dept_name FROM employees e FULL JOIN departments d ON e.dept_id = d.dept_id; (Note: Not supported in MySQL directly — use UNION instead) ⚡ 6. Quick Summary • INNER -> Only matching rows • LEFT -> All left + matched right • RIGHT -> All right + matched left • FULL -> Everything 🎯 7. Practice Tasks 1. Get employee name with department name 2. Show all employees even if no department 3. Show all departments even if no employees 4. Find employees without department 5. Count employees per department (using JOIN) 🔥 Practice Task Solutions 👇 ✅ 1. Get employee name with department name (INNER JOIN) SELECT e.name, d.dept_name FROM employees e INNER JOIN departments d ON e.dept_id = d.dept_id; ✅ 2. Show all employees even if no department (LEFT JOIN) SELECT e.name, d.dept_name FROM employees e LEFT JOIN departments d ON e.dept_id = d.dept_id; ✅ 3. Show all departments even if no employees (RIGHT JOIN) SELECT e.name, d.dept_name FROM employees e RIGHT JOIN departments d ON e.dept_id = d.dept_id; 👉 (Alternative using LEFT JOIN — interview friendly) SELECT e.name, d.dept_name FROM departments d LEFT JOIN employees e ON e.dept_id = d.dept_id; ✅ 4. Find employees without department SELECT e.name FROM employees e LEFT JOIN departments d ON e.dept_id = d.dept_id WHERE d.dept_id IS NULL; ✅ 5. Count employees per department (using JOIN) SELECT d.dept_name, COUNT(e.emp_id) AS total_emp FROM departments d LEFT JOIN employees e ON d.dept_id = e.dept_id GROUP BY d.dept_name; ⚡ Mini Challenge 🔥 👉 Find departments with no employees ⚡ Mini Challenge Solution 🔥 👉 Find departments with no employees SELECT d.dept_name FROM departments d LEFT JOIN employees e ON d.dept_id = e.dept_id WHERE e.emp_id IS NULL; Double Tap ❤️ For More

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What does this query return? SELECT department, AVG(salary) FROM employees GROUP BY department HAVING AVG(salary) > 50000;
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What will this query return? SELECT department, COUNT(*) FROM employees GROUP BY department HAVING COUNT(*) > 2;
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Which clause is used before GROUP BY?
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What is the purpose of HAVING clause?
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Business Intelligence (BI) Acronyms You Should Know 📊💡 BI → Business Intelligence ETL → Extract, Transform, Load ELT → Extract, Load, Transform DWH → Data Warehouse OLAP → Online Analytical Processing OLTP → Online Transaction Processing KPI → Key Performance Indicator SLA → Service Level Agreement SCD → Slowly Changing Dimension CDC → Change Data Capture MDM → Master Data Management EAV → Entity Attribute Value FACT → Fact Table DIM → Dimension Table STAR → Star Schema SNOWFLAKE → Snowflake Schema MTD → Month To Date QTD → Quarter To Date YTD → Year To Date MoM → Month over Month YoY → Year over Year ROI → Return on Investment TAT → Turn Around Time 💡Don’t just expand acronyms — explain where they’re used (ETL in pipelines, KPIs in dashboards, OLAP in analysis). 💬 Tap ❤️ for more!

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Now, let’s move to the next topic of SQL Roadmap: ✅ HAVING Clause 🧠 1. What is HAVING? HAVING is used to filter grouped data 👉 Think like this: - WHERE → filters rows (before grouping) - HAVING → filters groups (after grouping) ⚡ 2. WHERE vs HAVING Works on - WHERE: Rows - HAVING: Groups Used with - WHERE: SELECT - HAVING: GROUP BY Can use aggregates? - WHERE: ❌ No - HAVING: ✅ Yes 💡 3. Basic Syntax SELECT column, AGG_FUNCTION(column) FROM table_name GROUP BY column HAVING condition; 🎯 4. Examples (Very Important) 👉 Example 1: Departments with more than 2 employees SELECT department, COUNT() AS total_emp FROM employees GROUP BY department HAVING COUNT() > 2; 👉 Example 2: Departments with average salary > 50k SELECT department, AVG(salary) AS avg_salary FROM employees GROUP BY department HAVING AVG(salary) > 50000; ⚡ 5. WHERE + HAVING Together SELECT department, COUNT() AS total_emp FROM employees WHERE salary > 30000 GROUP BY department HAVING COUNT() > 2; 👉 Step-by-step: 1. WHERE → filters employees with salary > 30k 2. GROUP BY → groups by department 3. HAVING → keeps only groups with > 2 employees 🎯 6. Practice Tasks 1. Find departments having more than 3 employees 2. Find departments with average salary > 60k 3. Count employees per department where salary > 40k 4. Show departments with total salary > 1,00,000 5. Find departments with minimum salary > 30k ⚡ Mini Challenge 🔥 👉 Find departments having more than 2 employees AND avg salary > 50k Double Tap ❤️ For Practice Task Solution