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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

رفتن به کانال در Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 تحلیل کانال تلگرام ACCENTURE EXAM SOLUTIONS

کانال ACCENTURE EXAM SOLUTIONS (@coding_are) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 14 136 مشترک است و جایگاه 14 101 را در دسته آموزش و رتبه 28 086 را در منطقه الهند دارد.

📊 شاخص‌های مخاطب و پویایی

از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 14 136 مشترک جذب کرده است.

بر اساس آخرین داده‌ها در تاریخ 23 سپتامبر, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر -122 و در ۲۴ ساعت گذشته برابر -2 بوده و همچنان دسترسی گسترده‌ای حفظ شده است.

  • وضعیت تأیید: تأیید نشده
  • نرخ تعامل (ER): میانگین تعامل مخاطب 4.10% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 1.53% واکنش نسبت به کل مشترکان کسب می‌کند.
  • دسترسی پست‌ها: هر پست به طور میانگین 580 بازدید دریافت می‌کند. در اولین روز معمولاً 217 بازدید جمع‌آوری می‌شود.
  • واکنش‌ها و تعامل: مخاطبان به‌طور فعال حمایت می‌کنند؛ میانگین واکنش به هر پست 1 است.
  • علایق موضوعی: محتوا بر موضوعات کلیدی مانند placement, gaurntee, suree, capgemini, infosy تمرکز دارد.

📝 توضیح و سیاست محتوایی

نویسنده این فضا را محل بیان دیدگاه‌های شخصی توصیف می‌کند:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

به لطف به‌روزرسانی‌های پرتکرار (آخرین داده در تاریخ 24 سپتامبر, 2026)، کانال همواره به‌روز و دارای دسترسی بالاست. تحلیل‌ها نشان می‌دهد مخاطبان به‌طور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته آموزش تبدیل کرده‌اند.

14 140
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#include using namespace std; // simple primality check for x ≤ 100 bool is_prime(int x) { if (x < 2) return false; for (i
#include <bits/stdc++.h> using namespace std; // simple primality check for x ≤ 100 bool is_prime(int x) { if (x < 2) return false; for (int d = 2; d * d <= x; ++d) if (x % d == 0) return false; return true; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); long long N; cin >> N; int sum = 0; while (N > 0) { sum += N % 10; N /= 10; } if (is_prime(sum)) cout << "GOOGLY\n"; else cout << "NOT GOOGLY\n"; return 0; } Npci ✅

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