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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

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1 250
مشترکین
+224 ساعت
+147 روز
+2930 روز
آرشیو پست ها
GFG | Problem of the day :

class Solution { public: int rec(int i,string &s,int n,vector&dp) { if(i==n) { return 1; } if(dp[i]!=-1) return dp[i]; if(s[i]=='0') return 0; int cnt=0; //taking one digit if(s[i]!='0') cnt+=rec(i+1,s,n,dp); //taking 2 digits along with conditions if(idp(n+1,-1); int ans=rec(0,s,n,dp); return ans; } };

LeetCode | Daily challenge :

class Solution { public: //Function for finding determinant of matrix. int determinantOfMatrix(vector > matrix, int n) { if(n == 1) return matrix[0][0]; if(n == 2) return matrix[0][0] * matrix[1][1] - matrix[1][0] * matrix[0][1]; int det = 0; for(int i = 0, sign = 1; i < n; i++, sign = -sign){ vector> small_matrix(n-1, vector(n-1)); int a = 0; for(int j = 0; j < n; j++){ if(j == i) continue; for(int k = 1; k < n; k++) small_matrix[k-1][a] = matrix[k][j]; a++; } det += sign * matrix[0][i] * determinantOfMatrix(small_matrix, n-1); } return det; } };

GFG | Problem of the day :

class Solution { public: int minOperations(string s) { int count0= 0; int count1= 0; for(int i= 0; i< s.length(); i++){ if(i%2== 0 && s[i]== '0'){ count1++; }else if(i%2== 1 && s[i]== '1'){ count1++; } } for(int i= 0; i< s.length(); i++){ if(i%2== 0 && s[i]== '1'){ count0++; }else if(i%2== 1 && s[i]== '0'){ count0++; } } return min(count1, count0); } };

LeetCode | Daily challenge :

class Solution { public: int buyMaximumProducts(int n, int k, int price[]){ vector> v; int cnt=0, tmp; for(int i=0; i=0){ if(k

GFG | Problem of the day :

class Solution { public: bool isPathCrossing(string path) { unordered_set visited; visited.insert("0,0"); int x = 0, y = 0; for (char direction : path) { if (direction == 'N') y++; else if (direction == 'S') y--; else if (direction == 'E') x++; else if (direction == 'W') x--; string currentPosition = to_string(x) + "," + to_string(y); if (visited.find(currentPosition) != visited.end()) { return true; } visited.insert(currentPosition); } return false; } };

LeetCode | Daily challenge :

class Solution { public: //Function to find all elements in array that appear more than n/k times. int countOccurence(int arr[], int n, int k) { int count=0; unordered_mapmp; for(int i=0;in/k){ count++; } } return count; } };

GFG | Problem of the day :

class Solution { public: int maxScore(string s) { int ans = INT_MIN; for(int i=0; i

LeetCode | Daily challenge :

class Solution{ public: static bool cmp(vector& a,vector& b) { if(a[1]!=b[1]) return a[1] maxMeetings(int N,vector &S,vector &F){ vector> v; for(int i=0;i ans; ans.push_back(v[0][2]); int pre=v[0][1]; for(int i=1;ipre) { ans.push_back(v[i][2]); pre=v[i][1]; } } sort(ans.begin(),ans.end()); return ans; } };

GFG | Problem of the day :

class Solution { public: int maxWidthOfVerticalArea(vector>& points) { int n=points.size(); sort(points.begin(),points.end()); int res=0; for(int i=0;i

LeetCode | Daily challenge :

class Solution { public: int minCandy(int N, vector &ratings) { vector candy(N,1); for(int i = 1; iratings[i-1]) candy[i] = candy[i-1] + 1; else{ int j = i; while(j>0 && candy[j]>=candy[j-1] && ratings[j]

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