QUANTessential👑

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Solution😶‍🌫

Caselete DI ⏺ A shop sells Samosa , kachori and vada paav on saturday and sunday.The avg number of samosa sold per day is 100 and the number of samosa sold on saturday is 75. Ratio of number of samosa to that of vada paav sold on saturday is 5:6, respectively. Sum of number of kachori and vada paav solf on saturday is 144. Sum of number samosa sold on saturday and kachori sold on sunday is same as the number of samosa sold on sunday. Number of vada paav sold on sunday is 22 less than that sold on saturday. #ibpspo #sbi2022

I know sab ko aata hoga (Yeh) But mera main focus 1st and 3rd method hai Aksar log confused hote so🤯🤯 (Writing ke liye khed hai, eyes ka focal length chnge kre apne aap 😅) 💥Join : @Banking_encyclopedia_by_Nihar @Quant_Genius #CI

SOLUTION

A B C 24000 × 6 : 18000 × 12 : 30000 × 6 = 4 : 6 : 5 Given 5x – 4x = 4000 ⇒ x = 4000 Ans = 6 × 4000 = Rs. 24000

For A B=x L= x+5 For B L=13 B=x+5 A/Q 13(x+5) - x(x+5)=80 13x+65-x^2-5x=80 x^2-8x+ 15=0 x= 5,🕹 3❌ For A Perimeter = 2[ x+ (x+5)]= 4x+10 30

2D/12 + D/4 = 7.5 D= 18

2πrh = 1056 ⇒ 2 × × 7x × 6x = 1056 ⇒ x^2 = 4 ⇒ x = 2 TSA= total surface area = 2πr(h + r) Ans = 2288cm^2

IBPS PO | SBI PO / CLERK 2022 🎲 The curved surface area of a cylinder is 1056 cm2. The ratio of height to radius is 6 : 7 . What is the totalsurface area of the cylinder? 🕹 A boat goes 2D km downstream and D km upstream in 7.5 hours. If the downstream and upstream speeds of the boat are 12 km/hr and 4 km/hr, then what is the value of D? 🎋 Length of rectangle A is equal to the breadth of rectangle B . Breadth of the rectangle A is 5 less than the length of the rectangle A . Area of rectangle B is 80 cm2 more than that of rectangle A . If length of rectangle B is 13 cm, and breadth of rectangle A is more than 3 cm then what is the perimeter of rectangle. ↙️ A person spend 20% of his monthly salary in paying EMI. He spends 15% of his remaining salary in house rent and then 25% of the remaining salary is spend in paying car insurance. If he is left with Rs. 1530, find his monthly salary. ⏺ Two friends A and B started a business with investments of Rs. 24000 and Rs. 18000 respectively. After 6 months C joined the business with Rs. 30000 and at the same time Jaya left the business. At the end of 1 year, profit share of Sonali was Rs. 4000 more than the profit share of Jaya. Find the profit share of Rupali. Join : @Quant_Genius

5) 14 + 6 = 20 20 + 8 = 28 28 + 11 = 39 39 + 15 = 54 Here, 6 + 2 = 8 8 + 3 = 11 11 + 4 = 15 Hence, the missing number is 54.

4) 6 × 2 = 12 12 × 2.5 = 30 30 × 3.5 = 105 105 × 5 = 525 Here, 2 + 0.5 = 2.5 2.5 + 1 = 3.5 3.5 + 1.5 = 5 Hence, the missing number is 525.

3) 9 × 2 + 1 = 19 19 × 2 + 1 = 39 39 × 2 + 1 = 79 79 × 2 + 1 = 159

2) 81 – 32= 72 72 + 43= 136 136 – 52= 111 111 + 63= 327 Hence, the missing number is 327

1) 580 – 23 = 557 557 – 29 = 528 528 – 31 = 497 497 – 37 = 460 Here, 23, 29, 31 and 37 are consecutive prime numbers.

🙆‍♂ Number Series 🌐 580, 557, 528, 497, ? A. 412 B. 452 C. 431 D. 460 E. 428 🎯 81, 72, 136, 111, ? A. 319 B. 327 C. 341 D. 264 E. 275 ♦️ 9, 19, 39, 79, ? A. 193 B. 167 C. 159 D. 145 E. 141 ♥️ 6, 12, 30, 105, ? A. 525 B. 584 C. 495 D. 446 E. 502 🤯 14, 20, 28, 39, ? A. 97 B. 61 C. 54 D. 49 E. 44

Method 1 20%= 1/5 30%= 3/10 Cp Sp 5 6 10 13 5x-20/6x -20= 10/13 65x-260= 60x-200 x=12 Initia CP = 5×12=60 Method 2 Cp Sp 5 : 6 10 : 13 -------------- -20 : -20 (10×6-13×5)p = (-20×10 +20×13) 5p = -200+260 p=12 Initial CP = 5×12=60 Method 3 20% 30% \ / \(20×30/100=6) +10% 》》 20-20+6 10% 》》 6 So 100%= 60 📌

25%=1/4 30%= 3/10 Cp Sp 4 5 》》 /1 Diff cross× 10 13 》》 \3 Diff Cp sp 12 15 10 13 2P= 1400 P=700 Cp = 12 ×700 =8400 ans

30%=3/10 20% = -1/5 Original cp sp 10 13 ×2 5 4 ×5 ---------------------------- 25 20 26 Ans = (26-25)/25= 4%