అర్థమేటిక్ & రీజనింగ్ గ్రూప్

1+9/4 times bro

Otolagi

Solve this problem? Any one ?

Give me solution for 8th ...??

The answer is (1) 250. The sum of the first n odd positive integers is given by O = 1 + 3 + 5 + ... + (2n - 1) = n^2 The sum of the first n even positive integers is given by E = 2 + 4 + 6 + ... + 2n = n(n + 1) Therefore, E100 - O100 = 100^2 - 100^2 = 250. Here is the explanation of the problem: The first n odd positive integers are 1, 3, 5, ..., 2n - 1. The sum of these odd numbers is equal to n^2. The first n even positive integers are 2, 4, 6, ..., 2n. The sum of these even numbers is equal to n(n + 1). Therefore, the difference between the sum of the first n even positive integers and the sum of the first n odd positive integers is equal to n(n + 1) - n^2 = 2n. When n = 100, the difference is equal to 2 * 100 = 200. Therefore, the answer is (1) 250.

3

9+B+8 9+13+8=30 B=13,. 8 problem lo icchadu

K bro

48

ఆన్సర్ plz

Photo from D P

8*3 =24 but iam write 8*2=16

If present son : mother ages = 5:30 Diff b/w sond nd mother 25 yrs .. If son becomes mother age (5+25=30) Mother's age 30+25=55 Father: mother = 65: 55 Then father present age 65-25=40 yrs

Akada rectangles unay anukunta

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