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import heapq def maxClusterQuality(speeds, reliabilities, max_size):     machines = sorted(zip(reliabilities, speeds), reverse=True)     max_quality = 0     current_sum = 0     min_heap = []         for reliability, speed in machines:         heapq.heappush(min_heap, speed)         current_sum += speed                 if len(min_heap) > max_size:             current_sum -= heapq.heappop(min_heap)                 if len(min_heap) <= max_size:             max_quality = max(max_quality, current_sum * reliability)         return max_quality In python3

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Christmas Eve code in java : public class Example2 { // this will be the solution static int solutionCount = 0; public static void canCollect(int remainingAmount, int remainingHouses, int previousAmount) { if (remainingHouses == 0) return; if (remainingAmount < 0) return; if (remainingAmount == 0) { solutionCount++; return; } for (int i = 1; i < previousAmount; i++) { //deduct amount collected from this house-visit (i), deduct 1 from remaining houses, and set previousAmount to what you are collecting here canCollect(remainingAmount - i, remainingHouses - 1, i); } } // This is your solution function, although you'll need to change it enough to satisfy test-cases. public static int solutionFunction(int x, int y) { for (int i = 0; i <= x; i++) { canCollect(x - i, y-1, i); } return solutionCount; } //main is just to execute it here. Omit it in your submission public static void main(String args[]) { System.out.println(solutionFunction(5,5)); //3 } } Java Christmas Eve

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LCS With Vowels str1 = input() str2 = input () vowels = 'aeiou' c1 = c2 = 0 for ch in str1: if ch in vowels: c1 += 1 for ch in str2: if ch in vowels: c2 += 1 //allcoding1 print(min(c1,c2)) input2[-1] +=1 ans = input2[::-1] i=0 while i<= input1: if ans[i]>=9: ans[i+1]+=1 i+=1 else: print(input1-i) break

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