CODING SOLUTION - Placement Jobs & Materials
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کانال CODING SOLUTION - Placement Jobs & Materials (@codingsolution_it) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 129 376 مشترک است و جایگاه 152 را در دسته حرفه و رتبه 1 684 را در منطقه الهند دارد.
📊 شاخص‌های مخاطب و پویایی
از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 129 376 مشترک جذب کرده است.
بر اساس آخرین داده‌ها در تاریخ 24 اکتبر, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر -889 و در ۲۴ ساعت گذشته برابر -37 بوده و همچنان دسترسی گسترده‌ای حفظ شده است.
- وضعیت تأیید: تأیید نشده
- نرخ تعامل (ER): میانگین تعامل مخاطب 1.39% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 0.44% واکنش نسبت به کل مشترکان کسب می‌کند.
- دسترسی پست‌ها: هر پست به طور میانگین 1 793 بازدید دریافت می‌کند. در اولین روز معمولاً 565 بازدید جمع‌آوری می‌شود.
- واکنش‌ها و تعامل: مخاطبان به‌طور فعال حمایت می‌کنند؛ میانگین واکنش به هر پست 0 است.
- علایق موضوعی: محتوا بر موضوعات کلیدی مانند t.me/codingsolution_it, vector, codevita, string, graduate تمرکز دارد.
📝 توضیح و سیاست محتوایی
نویسنده این فضا را محل بیان دیدگاه‌های شخصی توصیف می‌کند:
“🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “
Contact Admin:
Mail me for collab
offcampusjobsindiaadmin@gmail.com
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به لطف به‌روزرسانی‌های پرتکرار (آخرین داده در تاریخ 25 اکتبر, 2026)، کانال همواره به‌روز و دارای دسترسی بالاست. تحلیل‌ها نشان می‌دهد مخاطبان به‌طور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته حرفه تبدیل کرده‌اند.
129 376
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#include <bits/stdc++.h>
using namespace std;
struct St {
long long s;
int c;
bool operator<(const St& o) const {
if (s != o.s) return s < o.s;
return c < o.c;
}
};
St mx(St a, St b) {
return a < b ? b : a;
}
St get_mx(const vector<int>& a, long long lam) {
int n = a.size();
St d0 = {0, 0};
St d1 = {-(long long)a[0] - lam, 1};
for (int i = 1; i < n; ++i) {
St n0 = mx(d0, d1);
long long v = -(long long)a[i];
St n1_ext = {d1.s + v, d1.c};
St n1_str = {d0.s + v - lam, d0.c + 1};
St n1 = mx(n1_ext, n1_str);
d0 = n0;
d1 = n1;
}
return mx(d0, d1);
}
long long solve(int n, int k, vector<int>& a) {
long long base = 0;
for (int i = 0; i < n; ++i) {
base += a[i];
}
St r0 = get_mx(a, 0);
long long best = 0;
if (r0.c <= k) {
best = r0.s;
} else {
long long l = 0, r = 2e14;
while (l <= r) {
long long mid = l + (r - l) / 2;
St cur = get_mx(a, mid);
if (cur.c >= k) {
best = cur.s + mid * k;
l = mid + 1;
} else {
r = mid - 1;
}
}
}
return base + 2 * best;
}
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