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Reasoning .1) C is third to the left of l 2) Ahl 3) 42 4)18 5) 2 6)1,3 7)arman 8)a 9)2 10)433:927 12)d 13)only Argument 1 14) 3,1 15) 780 17) 3 18) BKDHCL 19) either 20) YCFE 21) Blue 22) 5,4,2,1,3 23)a 24) 27:810 25) Father in law 26)d ✅Telegram- https://t.me/coding_solution_0

Verbal 1) EBACD 2) a-ii b-i c-iv b-i 3) the incidents 4.a 5.b 6.a-3 ✅Telegram- https://t.me/coding_solution_0 7)b Giving 9)a rpqs 10)c when a road

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R=int(input()) C=int(input()) N=int(input()) matrix=[] for i in range(R): a =[] for j in range(C): a.append(int(input())) matrix.append(a) i=0 j=0 flag=0 for i in range(0,R): for j in range(0,C): if matrix[i][j]==N: flag=1 break if flag==1: break print(str(i)+","+str(j)) Python 3 Cab rental code Telegram - https://t.me/coding_solution_0

TCS Numerical: 27th Feb Slot:10:00AM 1)2.17 2)5:8 3)48 4)117% 5)b 6)k+20 7)c -18 8)d- 7.235 9) a -250 10)c 11.5% 12.495 13.july2 14.10240 15.50days ✅Telegram- https://t.me/coding_solution_0

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X=input() Y=input() If y in x: Print ("Yes") Else: Print ("No") https://t.me/Coding_solution_0 https://t.me/Coding_solution_0 https://t.me/Coding_solution_0

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Anyone have this unix code

PYTHON ======== 1.Robotics 2.True 3.all of the above 4. Value 5. Inexpensive 6. 13 4 7. option B 8. A&b 9. Prioritize..... 10. Interest level of the users 11. D 12. A 13. B 14.C 15.c 16.b 17. Inner 18. B 19.c 20.B 21.A 22. B 23. B 24. D 25. B 26. A 27. B 28. apple 29. A 30. C 31. A 32. B 33. A 34. C 35. B 36. Error 37. n 38. A 39. A 40. A 41. 5 42. [('123', 'Ayansh'), ('125', 'Aadil'), ('126', 'Barkha')] 43. HELLO 44. [76,54,99] 45. Error 46. {3,a} 47. b 48. a 49. 1 50. 3210. https://t.me/Coding_solution_0

int main() { char s[100]; int i; printf("\nEnter a string : "); gets(s); for (i = 0; s[i]!='\0'; i++) { if(s[i] >= 'a' && s[i] <= 'z') { s[i] = s[i] - 32; } } printf("\nString in Upper Case = %s", s); return 0; } Warehouse Code Wipro Solution Available Here🚀🚀 https://t.me/Coding_solution_0 https://t.me/Coding_solution_0

num = 6172975 reversed_num = 0 while num != 0: digit = num % 10 reversed_num = reversed_num * 10 + digit num //= 10 print("Reversed Number: " + str(reversed_num)) Wipro Solution Available Here🚀🚀 https://t.me/Coding_solution_0 https://t.me/Coding_solution_0