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anyone want geeks for geeks free course
course content is:
(i) Data Structure Algorithm
(ii) Aptitude and Reasoning
(iii) Operating System
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Problem Description
Given an integer array X with size A. Initially, all the elements of this array are 0.
Given another integer array Y with the same size A, all the elements in it are
also 0.
You have to handle three types of operations/queries on the given arrays:
1 L R - Flip all the elements from 0 to 1 and 1 to 0 in the range L to R in the
array X.
2 P - For every element i ∈ [1, A], Y[i] = Y[i] + X[i] * P
3 J - Find Y[J].
Given a 2D array B that represents the queries.
Query Type 1 - B[i][0] = 1, B[i][1] = L, B[i][2] = R.
Query Type 2 - B[i][0] = 2, B[i][1] = P, B[i][2] = 0.
Query Type 3 - B[i][0] = 3, B[i][1] = J, B[i][2] = 0.
Problem Constraints
1 <= A <= 10
1 <= L <= R <= A
1 <= J <= A
1 <= P <= 10
1 <= Number of Queries <= 5 * 10
Input Format
The first argument is a single integer A.
The second argument is a 2D integer array B.
Output Format
Return an integer array that represents the output of query type 3 in the input
order.
Example Input
They are still waited us in queue.. while saying you are next in queue from 30 mins
def rev_sentence(sentence):
words = sentence.split(' ')
reverse_sentence = ' '.join(reversed(words))
return reverse_sentence
if name == "__main__":
input = 'metty to welcome'
print (rev_sentence(input))
