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965
Assalomu aleykum Xurmatli dasturchilar. PROGRAMMERS kanalimizda savol - javob viktorinasini olib borayapmiz. Viktorinamizda berilayotgan savollar va javobllar yuqorida qolib ketganligini hisobga olgan holatda, viktorinamizdagi savol javoblarni @programmersQuiz_bot botiga joylab borayapmiz. Botga a'zo bo'ling. Hali savollar oldida ...
Botdagi Java bobiga yangi Boolean bo'limini qo'shdik.
Viktorina bot
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965
#javob
#gita_14
Java dasturlash tilida
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("n = ");
int n = scanner.nextInt();
int a = scanner.nextInt();
int min = a, max = a;
int mini = 1, maxi = 1;
for (int i = 2; i <= n; i++) {
a = scanner.nextInt();
if (min > a) {
min = a;
mini = i;
}
if (max < a) {
max = a;
maxi = i;
}
}
if (mini < maxi) System.out.print(min + " " + mini);
else System.out.println(max + " " + maxi);
}
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965
#javob_kotlin_boolean_34
fun main() {
print("x = ")
val x = readLine()!!.toInt()
print("y = ")
val y = readLine()!!.toInt()
println((x + y) % 2 == 1)
}
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965
#javob_kotlin_boolean_33
fun main() {
print("a = ")
val a = readLine()!!.toInt()
print("b = ")
val b = readLine()!!.toInt()
print("c = ")
val c = readLine()!!.toInt()
println((a + b > c) && (a + c > b) && (b + c > a))
}
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965
#include <iostream>
/// a va b sonlari uchun EKUB(a, b) ni toping.
using namespace std;
int EKUB(int a, int b)
{
while (a != b)
{
if (a > b)
{
a = a - b;
}
if (b > a)
{
b = b - a;
}
}
return a;
}
int main()
{
int a, b;
cout << "a = "; cin >> a;
cout << "b = "; cin >> b;
cout << "EKUB(a, b) = " << EKUB(a, b) << endl;
return 0;
}
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965
#javob_kotlin_boolean_32
fun main() {
print("a = ")
val a = readLine()!!.toInt()
print("b = ")
val b = readLine()!!.toInt()
print("c = ")
val c = readLine()!!.toInt()
println((a * a + b * b == c * c) or (a * a + c * c == b * b) or (b * b + c * c == a * a))
}
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965
#javob_kotlin_boolean_31
fun main() {
print("a = ")
val a = readLine()!!.toInt()
print("b = ")
val b = readLine()!!.toInt()
print("c = ")
val c = readLine()!!.toInt()
println((a == b && b != c) or (a == c && a != b) or (b == c && b != a))
}
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965
Binar darax tuzing va uni ma’lumot bilan to’ldiring. Daraxt ma’lumotlarini ekranga chiqaring.
Source code:
#include<iostream>
using namespace std;
struct daraxt
{
int info;
daraxt* Left = NULL;
daraxt* Right = NULL;
};
void Add(daraxt* &a,int x)
{
if(!a)
{
daraxt* t = new daraxt;
t->info = x;
a = t;
return;
}
if(a->info<x)
{
Add(a->Right,x);
}
else
{
Add(a->Left,x);
}
}
void Show(daraxt* &a)
{
if(a==NULL) return;
if(a->Left) Show(a->Left);
cout«a->info«" ";
if(a->Right) Show(a->Right);
}
int main()
{
daraxt* a = NULL;
int x;
while(cin»x)
{
Add(a,x);
}
cout«"Daraxt: "«a->info«endl;
Show(a);
return 0;
}
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965
#javob_kotlin_boolean_30
fun main() {
print("a = ")
val a = readLine()!!.toInt()
print("b = ")
val b = readLine()!!.toInt()
print("c = ")
val c = readLine()!!.toInt()
println(a == b && b == c)
}
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اکنون در دسترس! پژوهش تلگرام ۲۰۲۵ — مهمترین بینشهای سال 
