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📊 Dynamic QR Code Generator Bot 🤖
Generate dynamic QR codes instantly with our efficient bot! Whether it's a URL, text, or any other data, our bot will create a QR code for you in no time. Say goodbye to traditional QR code generators and experience the ease and flexibility of our dynamic QR code generator bot.
🤖 Bot Username: @DynamicQRGeneratorBot
✅ Reaction 💫
🔗 Join Our Channel: @DEVSNP
🌟 WELCOME TO DYNAMIC QR CODE GENERATOR BOT! 🌟
🤖 Simply send us your text or URL, and we'll generate a dynamic QR code for you! 💫
🔗 Excited to create a QR code? Share your text or URL now, and get your dynamic QR code instantly! 🎉
🚀 Sit back, relax, and let our bot generate QR codes for you effortlessly! ✨
BOT USERNAME:-@DynamicQRGeneratorBot
✨ MADE WITH ❤️ BY NEPCODER @DEVSNP ✨
📊 Dynamic QR Code Generator Bot 🤖
Generate dynamic QR codes instantly with our efficient bot! Whether it's a URL, text, or any other data, our bot will create a QR code for you in no time. Say goodbye to traditional QR code generators and experience the ease and flexibility of our dynamic QR code generator bot.
🤖 Bot Username: @DynamicQRGeneratorBot
✅ Reaction 💫
🔗 Join Our Channel: @DEVSNP
🌟 WELCOME TO DYNAMIC QR CODE GENERATOR BOT! 🌟
🤖 Simply send us your text or URL, and we'll generate a dynamic QR code for you! 💫
🔗 Excited to create a QR code? Share your text or URL now, and get your dynamic QR code instantly! 🎉
🚀 Sit back, relax, and let our bot generate QR codes for you effortlessly! ✨
BOT USERNAME:-@DynamicQRGeneratorBot
✨ MADE WITH ❤️ BY NEPCODER @DEVSNP ✨
Abusive Word Detector And Kicker In Tpy❤️
Commands:-
*
def check_abusive_language(message):
url = f"https://ttptest.link/checkabuse.php?message={message}"
response = HTTP.get(url)
if response.status_code == 200:
result = response.json()
if result.get("containsabusiveword") == "yes":
return True
return False
def ban_user(chat_id, user_id):
ban_url = f"https://api.telegram.org/bot{Bot.info().token}/kickChatMember?chat_id={chat_id}&user_id={user_id}"
ban_response = HTTP.get(ban_url)
return ban_response.status_code == 200
if check_abusive_language(message.text):
bot.sendChatAction(chat_id=message.chat.id, action="typing")
username = message.from_user.username
user_id = message.from_user.id
if ban_user(message.chat.id, user_id):
notification_text = f"🚫 @{username} used abusive language and has been banned from the chat. 🗑️"
else:
notification_text = "❌ Failed to ban the user. Please try again later."
bot.sendMessage(chat_id=message.chat.id, text=notification_text)
else:
pass
Coded By @Nepcoder❤️
Api:-Kiska he ajau Dunga credit❤️
By @DEVSNP
Share Tpy Code With Credit :-@Devsnp