AI Coding & CSE Fundamentals
🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.
Mostrar más📈 Análisis del canal de Telegram AI Coding & CSE Fundamentals
El canal AI Coding & CSE Fundamentals (@aicoding_csefundamentals) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 12 324 suscriptores, ocupando la posición 10 232 en la categoría Tecnologías y Aplicaciones y el puesto 31 271 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 12 324 suscriptores.
Según los últimos datos del 12 noviembre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -238, y en las últimas 24 horas de -8, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 10.45%. Durante las primeras 24 horas tras publicar, el contenido suele obtener N/A% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 1 288 visualizaciones. En el primer día suele acumular 0 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 11.
- Intereses temáticos: El contenido se centra en temas clave como input, string, scanf("%d, array, element.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“🚀 Explore AI, Coding & Computer Science Fundamentals.
💻 Programming • DSA • DBMS • OS • Networks
🤖 AI & Emerging Technologies
🛠️ Projects • Tutorials • Learning Resources
📚 Your freedom to gain knowledge for free.”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 13 noviembre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
#include <stdio.h>
int main() {
int num1, num2, sum;
printf("Enter the first integer: ");
scanf("%d", &num1);
printf("Enter the second integer: ");
scanf("%d", &num2);
sum = num1 + num2;
printf("Sum: %dn", sum);
return 0;
}num1, num2, and sum. num1 and num2 will store the input numbers, and sum will store their sum.
Step 2: Prompt the user to enter the first integer.
Step 3: Read the first integer from the user and store it in the num1 variable using scanf.
Step 4: Prompt the user to enter the second integer.
Step 5: Read the second integer from the user and store it in the num2 variable using scanf.
Step 6: Calculate the sum of num1 and num2 and store the result in the sum variable.
Step 7: Print the value of sum to the console, displaying the sum of the two integers.
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❤️ Understood | 👎 Not Understoodnum1, num2, and sum. num1 and num2 will store the input numbers, and sum will hold their sum.
Step 2: Prompt the user to enter the first integer using printf.
Step 3: Read the first integer from the user and store it in the num1 variable using scanf.
Step 4: Prompt the user to enter the second integer using printf.
Step 5: Read the second integer from the user and store it in the num2 variable using scanf.
Step 6: Calculate the sum of num1 and num2 and store the result in the sum variable: sum = num1 + num2;
Step 7: Display the calculated sum to the user using printf.
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❤️ Understood | 👎 Not Understood#include <stdio.h>
int main() {
float userInput;
printf("Enter a float number: ");
scanf("%f", &userInput);
printf("You entered: %fn", userInput);
return 0;
}printf and scanf).
Step 2: Declare a float variable to store the user's input. (This variable will hold the float value).
Step 3: Prompt the user to enter a float number using printf. (This tells the user what to do).
Step 4: Read the float input from the user using scanf and store it in the declared float variable. (Use the correct format specifier %f for float).
Step 5: Display the stored float value back to the user using printf. (Again, use the correct format specifier %f for float).
Step 6: Return 0 from the main function. (Indicates successful program execution).
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❤️ Understood | 👎 Not Understood#include <stdio.h>
int main() {
int userInput;
printf("Enter an integer: ");
scanf("%d", &userInput);
printf("You entered: %dn", userInput);
return 0;
}printf (for output) and scanf (for input).
Step 2: Declare an integer variable: This variable will store the integer value entered by the user.
Step 3: Prompt the user for input: Display a message on the screen asking the user to enter an integer.
Step 4: Read the integer input using scanf: Use scanf to read the integer entered by the user and store it in the declared integer variable.
Step 5: Display the entered integer using printf: Use printf to display the value stored in the integer variable back to the user, confirming their input.
Step 6: Return 0 from the main function: This indicates successful execution of the program.
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❤️ Understood | 👎 Not Understood#include <stdio.h>
int main() {
printf("Your Name: John Doen");
printf("Street Address: 123 Main Streetn");
printf("City: Anytownn");
printf("State: CAn");
printf("Zip Code: 91234n");
return 0;
}printf that we will use to print to the console.
Step 2: Create the main function. This is the entry point of your C program.
Step 3: Use printf statements to display your name and address. Each piece of information (name, street, city, etc.) can be on a new line for readability.
Step 4: Return 0 from the main function to indicate successful execution of the program.
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❤️ Understood | 👎 Not Understood#include <stdio.h>
int main() {
printf("Hello, World!n");
return 0;
}#include <stdio.h>.
Step 2: Define the main function: The main function is the entry point of every C program. It's where the program begins execution. Start it with int main() {.
Step 3: Print "Hello, World!" to the console: Use the printf function to display the text. printf("Hello, World!\n"); will print the message, and \n adds a newline character to move the cursor to the next line.
Step 4: Return 0 from the main function: This indicates that the program executed successfully. Add return 0; before closing the main function.
Step 5: Close the main function: Add a closing curly brace } to end the main function.
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❤️ Understood | 👎 Not Understoodprintf.#include <stdio.h>
int main() {
printf("Hello, World!n");
return 0;
}