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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Análisis del canal de Telegram ACCENTURE EXAM SOLUTIONS

El canal ACCENTURE EXAM SOLUTIONS (@coding_are) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 14 140 suscriptores, ocupando la posición 14 101 en la categoría Educación y el puesto 28 086 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 14 140 suscriptores.

Según los últimos datos del 23 septiembre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -122, y en las últimas 24 horas de -2, conservando un alto alcance.

  • Estado de verificación: No verificado
  • Tasa de interacción (ER): El promedio de interacción de la audiencia es 4.10%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 1.53% de reacciones respecto al total de suscriptores.
  • Alcance de las publicaciones: Cada publicación recibe en promedio 580 visualizaciones. En el primer día suele acumular 217 visualizaciones.
  • Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 1.
  • Intereses temáticos: El contenido se centra en temas clave como placement, gaurntee, suree, capgemini, infosy.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 24 septiembre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.

14 140
Suscriptores
-224 horas
-377 días
-12230 días
Archivo de publicaciones
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#include <iostream> #include <vector> using namespace std; int main() { int n; cin >> n; vector<int> arr(n); for (int i = 0; i < n; ++i) { cin >> arr[i]; } int k; cin >> k; bool all_positive = true; for (int x : arr) { if (x < 0) { all_positive = false; break; } } if (all_positive) { cout << endl; return 0; } vector<int> steps; vector<int> tmp = arr; for (int i = 0; i < n - 1; ++i) { if (tmp[i] < 0) { tmp[i] *= -1; tmp[i + 1] *= -1; steps.push_back(i + 1); // Convert to 1-based index } } if (tmp.back() < 0) { tmp.back() *= -1; steps.push_back(n); } if (steps.size() > k) { cout << -1 << endl; } else { for (size_t i = 0; i < steps.size(); ++i) { if (i > 0) cout << " "; cout << steps[i]; } cout << endl; } return 0; }

network antenna

#include <iostream> #include <vector> using namespace std; int main() { int sender_size, receiver_size; cin >> sender_size; vector<int> senders(sender_size); for (int i = 0; i < sender_size; ++i) { cin >> senders[i]; } // Read receiver antennas cin >> receiver_size; vector<int> receivers(receiver_size); for (int i = 0; i < receiver_size; ++i) { cin >> receivers[i]; } int n = sender_size; int m = receiver_size; vector<vector<int>> dp(n + 1, vector<int>(m + 1, 0)); for (int i = 1; i <= n; ++i) { for (int j = 1; j <= m; ++j) { if (senders[i-1] == receivers[j-1]) { dp[i][j] = dp[i-1][j-1] + 1; } else { dp[i][j] = max(dp[i-1][j], dp[i][j-1]); } } } cout << dp[n][m] << endl; return 0; }