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KPIT EXAM SOLUTIONS

KPIT EXAM SOLUTIONS

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📈 Análisis del canal de Telegram KPIT EXAM SOLUTIONS

El canal KPIT EXAM SOLUTIONS (@coding_are) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 14 156 suscriptores, ocupando la posición 14 030 en la categoría Educación y el puesto 28 046 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 14 156 suscriptores.

Según los últimos datos del 17 septiembre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -126, y en las últimas 24 horas de -13, conservando un alto alcance.

  • Estado de verificación: No verificado
  • Tasa de interacción (ER): El promedio de interacción de la audiencia es 4.44%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 1.62% de reacciones respecto al total de suscriptores.
  • Alcance de las publicaciones: Cada publicación recibe en promedio 629 visualizaciones. En el primer día suele acumular 229 visualizaciones.
  • Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 1.
  • Intereses temáticos: El contenido se centra en temas clave como placement, gaurntee, suree, capgemini, infosy.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 18 septiembre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.

14 156
Suscriptores
-1324 horas
-117 días
-12630 días
Archivo de publicaciones
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maintenance_risk_solution (1).pdf0.04 KB

def total_amount(x, y): total = 0 for n in range(x, y + 1): s = 0 mx = 0 t = n while t > 0: d = t % 10 s += d if d > mx: mx = d t //= 10 if s - mx == mx: total += n return total def main(): x, y = map(int, input().split()) print(total_amount(x, y)) if name == "main": main()

SELECT c.course_id, c.course_name, c.domain, COUNT(DISTINCT e.student_id) AS number_of_students_completed, ROUND( COUNT(DISTI
SELECT c.course_id, c.course_name, c.domain, COUNT(DISTINCT e.student_id) AS number_of_students_completed, ROUND( COUNT(DISTINCT CASE WHEN o.offer_status = 'ACCEPTED' THEN e.student_id END) * 100.0 / COUNT(DISTINCT e.student_id), 2) AS placement_rate_among_completers FROM courses c JOIN enrollments e ON e.course_id = c.course_id AND e.completion_status = 'COMPLETED' LEFT JOIN interviews i ON i.student_id = e.student_id LEFT JOIN offers o ON o.interview_id = i.interview_id AND o.offer_status = 'ACCEPTED' GROUP BY c.course_id, c.course_name, c.domain HAVING COUNT(DISTINCT e.student_id) >= 20 ORDER BY placement_rate_among_completers DESC, number_of_students_completed DESC, c.course_name ASC, c.course_id ASC;

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