QUANTessential👑
Ir al canal en Telegram
🙏 ଜୟ ଜଗନ୍ନାଥ 🙏 Daily CA pdfs @Banking_encyclopedia_by_Nihar Maths :- @quant_fever Reasoning @reasoning_champions English @english_toppers Ca Quizzes @GA_quizzes 2nd channel @Banking_encyclopedia_by_Nihar1
Mostrar más![Gk +imp sub pdfs [ɴɪʜᴀʀ]❤️](https://cdn.tlmtr.io/_next/image?url=https%3A%2F%2Fimg.tlmtr.io%2Fc%2F1CoE2V%2F6077874367817166978%3Fty%3Dx&w=32&q=75){kind=small}
Red:2 918
Suscriptores
Sin datos24 horas
-77 días
-3630 días
Archivo de publicaciones
2 918
#Day_17_Target_SBI_PO_Clerk_mains_Gk_imp_sub_pdfs_Nihar
6) Time taken by train A to cross a platform is 9
seconds and that taken by train B to cross the
same platform is ___ seconds. Ratio of speeds of
train A to train B is 3: 2 and length of train B is 50
m more than that of train A. Length of the
platform is 80% of length of train A and train A
will cross train B in 7 seconds while running in
opposite direction.
What value will be filled in the blank?
a) 12 seconds
b) 20 seconds
c) 15 seconds
d) 18 seconds
e) 16 seconds
7) Two inlet pipes A and B and one outlet pipe
C are connected to a tank. Pipes A and C
together can fill a tank in 22.5 minutes, while
pipes B and C together can fill the same tank in
90 minutes and ratio of efficiency of pipe A to B
is 2: 1 respectively. If pipes A and B works with
125% and 83(1/3) % of their efficiencies
respectively, then in what time pipes A and B
together will fill the tank?
a) 12 minutes
b) 6 minutes
c) 15 minutes
d) 9 minutes
e) 18 minutes
sиαρσnє🌱
8) Ratio of A’s present age to B’s present age is
5: 6. Ratio of A’s age after 2 years to B’s age
after 4 years will be 4: 5. A and B entered into a
partnership and B invested Rs.2000 more than
A. If A withdraws his capital when he gets 35
years old and B withdraws his capital when he
gets 40 years old and ratio of A’s share to B’s
share is 9: 8, then find the investment of B?
a) Rs.16000
b) Rs.20000
c) Rs.14000
d) Rs.24000
e) Rs.18000
9) There are two series given below series I
and II each having a wrong term. If wrong term of
series I and series II are mentioned as A and B
respectively, then which of the following is
TRUE?
Series I: 15, 40, 76, 125, 190, 270
Series II: 18, 35, 69, 139, 273, 545
a) A = B – 51
b) 2A < B
c) A < B
d) A = B
e) A > B
sиαρσnє🌱
10) Below given as two series I and II, each
having a missing term. Which of the following
regarding missing term(s) is/are TRUE?
Series I: 100, 123, 152, 183, ?, 261
Series II: 20, 28, ?, 119, 244, 460
I: Missing term of series I is divisible by 13.
II: Missing term of series II is divisible by 11.
III: Missing term of series I ÷ Missing term of
series II = 0.25
a) All I, II, and II
b) Both I and II
c) Only II
d) None
e) Only III
2 918
#Day_17_Target_SBI_PO_Clerk_mains_Gk_imp_sub_pdfs_Nihar
In an Industry a spherical shaped iron ball was
melted and reconstructed as a certain number of
cylindrical, conical and cuboid shapes.
Diameter of the spherical iron ball is 84 cm and
the ratio between the number of cylindrical,
conical and cuboid shapes is 32:29:24.
Diameter and the lateral surface area of the
cylindrical shape is 10 cm and 330 cm^2.
Height of the conical shape is 133(1/3) % more
than its radius and the base perimeter of the
conical shape is 37(5/7) cm^2.
Height of the cuboid is 3 more than its length and
breadth is 2 more than the 25% of the height and
the total surface area of the cuboid is 356.5 cm^2.
sиαρσnє🌱
1) Find the number of conical shapes made by
using the spherical iron ball?
a) 116
b) 203
c) 145
d) 174
e) 192
2) What is the lateral surface area of a conical
shape?
a) 287.22 cm2
b) 253.34 cm2
c) 297.32 cm^2
d) 264.22 cm^2
e) 283.46 cm^2
3) The industry is decided to coating every
conical shape with silver and the coating cost @
Rs. 5 per cm^2. What is the total cost for coating
all of the conical shapes?
a) Rs. 2,43,254
b) Rs. 3,54,323
c) Rs. 3,48,322
d) Rs. 2,49,841
e) Rs. 2,53,453
4) What is the total volume of all cylindrical
shapes are made by the spherical iron ball?
a) 153500 cm^3
b) 144400 cm^3
c) 138620 cm^3
d) 158400 cm^3
e) 154300 cm^3
5) What is the total curved surface area of all
cuboid shapes made by the spherical iron ball?
a) 41920 cm^2
b) 48234 cm^2
c) 49230 cm^2
d) 40392 cm^2
e) 32392 cm^2
2 918
Detailed Solution:
1.
Post-graduate in Accounts is=160×60/100=96
Graduate in accounts is=160-96=64
Graduate in IT is=200×60/100=120
Postgraduate in IT is=200-120=80
Required ratio = (64+80): (96+120) =2:3 (C)
2.
According to the question,
280x-180(x-2000) =2760000
Or, 100x=240000
Or, x=24000
Total salary of the IT department of D
is=26000×90=2340000 (D)
sиαρσnє🌱
3.
Male in Marketing department is
=140×110/100=154
Female in marketing department
is=280×90/100=252
So, the total number of employees
is=154+252=406 (B)
4.
44.44% of number employees in IT department
of B is =180×44.44/100=80
Now try option A,
50% of account department employees
is=160×50/100=80
So, it satisfies. (A)
5.
Employee in Accounts department of F is=
[160+140]/2=150
Employee in IT department of F is=
[120+90]/2=105
Required difference=150-105=45 (A)
2 918
Detailed Solution:
Let the number of employees in the accounts
department of organization A is 4x and In the IT
department, it is 5x.
The number of employees in the accounts
department of organization B is 7x.
number of employees in the IT department of
organization B is =7x-100
9x=360
x=40
Number of employees in the Accounts
department of A = 40×4=160
Number of employees in the IT department of
A=5×40=200
Number of employees in the IT department of B
=7×40-100=180
Number of employees in the IT department of C
is=300-180=120
Number of employees in the IT department of D
is=120×3/4=90
Number of employees in the Accounts
department of C is=90+50=140
Number of employees in the Accounts
department of D is=215-90=125
Number of employees in the Accounts
department of E is= 125×4/5=100
Number of employees in the IT department of E
is=125+125=250
sиαρσnє🌱
2 918
#Day_16_Target_SBI_PO_Clerk_mains_Gk_imp_sub_pdfs_Nihar
There are five Organizations. [A, B, C, D, &E].
Each one has two departments: Account and IT.
Ratio of the number of employees in Accounts
and IT department of A is 4:5. Ratio of the
number of employees in the Account of
organization A and B is 4:7. Number of
employees in the IT department of B is 100 less
than the number of employees in Accounts of the
same organizations. Ratio of the number of
employees in the IT department of organization
C and D is 4:3. Number of employees in the
accounts department of C is 50 more than the
number of employees in the IT department of D.
Total number of employees in A is 360 and the
Total number of employees in the IT department
of B and C together is 300.Number of employees
in the Account department of E is 80% of the
number of employees in Account department of
D. Number of employees in the IT department of
E is 125 more than the number of employees in
the Accounts department of D. Total number of
employees in D is 215.
sиαρσnє🌱
1) In organization A, 40% of employees in the
accounts department are postgraduates and the
rest are only graduates. In the IT department,
60% of employees are only graduates. Find the
ratio between the total number of Postgraduate
employees in organizations A to the total number
of only graduate employees in A.
a) 2:7
b) 3:2
c) 2:3
d) 2:5
e) 6:7
2) Salary of each employee of Account
department B is x and the salary of each
employee of the IT department is x-2000. If the
difference of total salary of all employees of
these two departments is 2760000 then find the
total salary of all employees of IT department of
D where each employee’s salary in IT
department of D is x+2000.
a) 2230000
b) 2360000
c) 2540000
d) 2340000
e) 2250000
3) Organization C wants to open a new
department i.e., Marketing. Number of males in
the marketing department of C is 10% more than
the employee of the Accounts department of C.
Number of females in the Marketing department
is 10% less than the total number of employees
in Account department of B. Find the total
number of employees in the Marketing
department.
a) 420
b) 406
c) 252
d) 258
e) None of these
4) __% employee of ___ department of
organization___ is 44.44% of the employee of IT
department of Organization B.
Find which combination of values satisfies the
blank in the same sequence.
a) 50, Accounts, A
b) 50, IT, A
c) 30, Accounts, C
d) 40, Accounts, D
e) None of these
5) Another organization F, employees in the
Accounts department are the average number of
employees in the accounting department of A
and C together and employee in the IT
department is the average number of employees
in the IT department in C and D together. Find
the difference between employees in Accounts
and the IT department of F.
a) 45
b) 40
c) 30
d) 35
e) None of these
2 918
Detailed Solution: (6 to 10)
Total number of vacancies in both the
Companies together = 14,400
Number of vacancies in company X = 14,400 ×
5/12 = 6000
Number of vacancies in company Y = 14,400 ×
7/12 = 8400
Vacancies for male in company X = 6000 ×
70/100 = 4200
Vacancies for female in company X = 6000 –
4200 = 1800
Vacancies for male in department P in company
X = 4200 × 3/5 = 2520
Vacancies for male in department Q in company
X = 1/8 × (4200 – 2520) = 210
Vacancies for male in department R in company
X = 7/8 × (4200 – 2420) = 1470
Vacancies for female in department Q in
company X = 1800 × 24/100 = 432
Vacancies for female in department P in
company X = 5/8 × (1800 – 432) = 855
Vacancies for female in department R in
company X = 1800 – 432 – 855 = 513
Vacancies for male in company Y = 8400 ×
80/100 = 6720
Vacancies for female in company Y = 8400 –
6720 = 1680
Vacancies for male in department P in company
Y = 6720 × 65/100 = 4368
Vacancies for male in department R in company
Y = 1470 × 12/10 = 1764
Vacancies for male in department Q in company
Y = 6720 – 4368 – 1764 = 588
Vacancies for female in department P in
company Y = 4368 × 25/100 = 1092
Vacancies for female in department Q in
company Y = 1/4 × (1680 – 1092) = 147
Vacancies for female in department R in
company Y = 3/4 × (1680 – 1092) = 441
sиαρσnє🌱
6.
The total number of female vacancies in the
department P in both the Company X and Y
together = 855 + 1092 = 1947
Hence, the required answer = 1947 (B)
7.
Vacancies for male in department R in company
X = 1470
Vacancies for male in company X = 4200
So, the required percentage = 1470/4200 × 100
= 35%
Hence, the required answer = 35% (D)
8.
Total of male and female vacancies in
department Q = 588 + 147 = 735
Total of male and female vacancies in
department R = 1764 + 441 = 2205
Hence, the required ratio between them =
735:2205 = 1:3
Hence, the required answer = 1:3 (C)
9.
Average number of female vacancies in
department R in both companies together = (513
+ 441)/2 = 477
Average number of male vacancies in
department Q in both companies together =
(210 + 588)/2 = 399
Thus, the required difference between them =
477 – 399 = 78
Hence, the required answer = 78 (B)
10.
Vacancies for female in department Q in
company Y = 147
Total vacancies for female in company Y = 1680
So, the required percentage = 147/1680 × 100 =
8.75%
Hence, the required answer = 8.75% (B)
2 918
Detailed Solution: (4 to 5)
4.
Total cost of decorating 3M/2 sheets buys by P
is 181.25% more than that of 0.6M sheets buys
by Q.
So, Ratio of total cost of decorating 3M/2 sheets
buys by P is 181.25% more than that of 0.6M
sheets buys by Q = 45/16
Total area decorated by P = 3M/2 x (K + 2) x (K
+ 2)
Total area decorated by Q = 0.6M x (K – 2) x (K
– 2) x 2 [both sides]
Now,
[3M/2 x (K + 2) x (K + 2)] / [0.6M x (K – 2) x (K –
2) x 2] = 45/16
(K + 2)^2 / (K – 2)^2 = 9/4
(K + 2) / (K – 2) = 3/2
2K + 4 = 3K – 6
Value of K = 10 (B)
sиαρσnє🌱
5.
According to question,
2 x (M – 6) x (10 + 2) x (10 + 2) x 2.5 = 2880
M – 6 = 4
Value of M = 10
Now,
18 x N x 12 x (10 – 4) = 20736
Value of N = 16 (D)
2 918
Detailed Solution: (1 to 3)
Let radius of circle drawn on longest side of
triangle = r cm
Circumference of semi-circle = πr + 2r
Now,
3 x r + 2r = 85/2
Value of r = 17/2 cm
So, longest side of the triangle = 2r = 2 x 17/2 =
17 cm
Each side of triangle is a natural number, so
there is one possible triplet that includes 17 as
largest number is (8, 15, 17).
So, other two sides are 8 cm and 15 cm
If (b – 2) = 8
Value of b = 10
Then (a + 3) = 15
Value of a = 12
But area of square = 3 x [b – a], so b > a
So, (a + 3) = 8
Value of a = 5
And, (b – 2) = 15
Value of b = 17
So, area of square = 3 x (17 – 5) = 36 cm^2
Value of c = (36)^(1/2) = 6 cm
So, length of rectangular sheet = (3 x 6 + d) =
(18 + d) cm
Breadth of rectangular sheet = (d + 4) cm
Volume of rectangular box = 432 cm^3
So,
(18 + d – 12) x (d + 4 – 12) x 6 = 432
(d + 6) x (d – 8) = 72
d^2 – 2d – 120 = 0
d^2 – 12d + 10d – 120 = 0
(d – 12) (d + 10) = 0
So, possible value of d = 12
So, length of rectangular box = (18 + 12) = 30
cm
Breadth of rectangle = (12 + 4) = 16 cm
sиαρσnє🌱
1.
According to question,
Area of cylinder to be painted = 2 x area of
rectangular sheet [both sides] = 2 x (30 x 16)
Required cost = 4.5 x 2 x (30 x 16) = Rs. 4320 (B)
2.
Required value of c = 6 cm (A)
3.
Let the length of perpendicular drawn on
hypotenuse = K cm
Now,
1/2 x 15 x 8 = 1/2 x K x 17
Value of K = (15 x 8)/17
Required value = 17/4 x (15 x 8)/17 = 30 cm (C)
2 918
#Day_14_15_Target_SBI_PO_Clerk_mains_Gk_imp_sub_pdfs_Nihar
The data is given about the total number of
vacancies in the department P, Q and R of
Companies X and Y. The total number of
vacancies in both the companies together is
14,400. The respective ratio of number of
vacancies in Companies Y and X is 7: 5. Each
vacancy is splitted into three departments P,Q,R
of the respective companies.
In company X, 70% of the total vacancies are for
males. 3/5th of the total number of male
vacancies are in department P. Out of the
remaining male vacancies 1/8th is in department
Q. Out of the total female vacancies, 24% are in
department Q and 5/8th of the remaining female
vacancies is in department P.
In company Y, 80% of the total vacancies are for
males. 65% of the total male vacancies are in
department P. Number of male vacancies in
department R in company Y is 20% more than
the male vacancies in department R in company
X. Number of female vacancies in department P
in company Y are less than the number of male
vacancies in department P in the same company
by 75%. Out of the remaining female vacancies,
1/4th is in department Q.
sиαρσnє🌱
6) What is the total number of female vacancies
in the department P in both the Companies X
and Y together?
a) 1893
b) 1947
c) 2021
d) 2385
e) None of these
7) Find what percentage of the total number of
male vacancies in company X are in the
department R?
a) 46%
b) 21%
c) 19%
d) 35%
e) None of these
8) In Company Y, what is the respective ratio
between the total number of vacancies both male
and female in the department Q together to that
of total number of vacancies both male and
female in the department R together in the same
company?
a) 3:2
b) 4:5
c) 1:3
d) 7:5
e) None of these
9) Find what is the difference between the
average number of male vacancies in the
department Q in both the companies together
and the average number of female vacancies in
the department R in both the companies
together.
a) 103
b) 78
c) 121
d) 85
e) None of these
10) What percentage of the total number of female
vacancies in the Company Y are in the
department Q?
a) 6.35%
b) 8.75%
c) 7.25%
d) 9.55%
e) None of these
2 918
#Day_14_15_Target_SBI_PO_Clerk_mains_Gk_imp_sub_pdfs_Nihar
P buys M square sheets, side is (K + 2) cm, and
12 rectangular sheets of dimension (18 cm x N
cm). Q buys 0.6M square sheet, side (K – 2) cm.
Cost of decorating (one surface) of 3M/2 square
sheets buy by P is 181.25% more than that of all
sheets buys by Q (from both sides).
sиαρσnє🌱
4) Find the value of K?
a) 12
b) 10
c) 8
d) 6
e) Can’t be determined
5) If cost of decorating the (M – 6) square
sheets buys by P (both sides) is Rs. 2880 at 2.5
per cm^2. Find the value of N if cost of 12
rectangular sheets (one side) of dimension (18 x
N) at Rs. (M – 4) per cm^2 is Rs. 20736.
a) 18
b) 24
c) 12
d) 16
e) None of these
2 918
#Day_14_15_Target_SBI_PO_Clerk_mains_Gk_imp_sub_pdfs_Nihar
A semicircle whose circumference is 85/2 cm is
drawn on longest side of a right-angle triangle
have diameter same as length of longest side.
Two-side other than hypotenuse are (b - 2) cm
and (a + 3) cm. A square has an area of (c)^2 cm, is
cut from each corner of a rectangular sheet of
length (3c + d) cm and breadth is (d + 4) cm. Left
out rectangular sheet folded to form a
rectangular box has volume 432 cm^2. Area of
square is 3[b – a] cm^2.
Note: Dimensions of Square and triangle are
natural numbers. Use π = 3.
sиαρσnє🌱
1) Find the cost of painting (inside + outside) of
a right circular cylinder which is formed by joining
the shorter sides of a rectangular sheet at Rs.
4.5 cm^2.
a) Rs. 2160
b) Rs. 4320
c) Rs. 3840
d) Rs. 3360
e) None of these
2) Find the value of c.
a) 6 cm
b) 4 cm
c) 8 cm
d) 5 cm
e) None of these
3) Find 17/4 times of length of perpendicular
drawn from point of contact of two sides (other
than hypotenuse) on hypotenuse of right-angled
triangle?
a) 18 cm
b) 15 cm
c) 30 cm
d) 60 cm
e) None of these
2 918
For Q
Let the cost price of article = 4b
Difference between cost price and marked price
= 40Z = 40 x 20 = Rs. 800
So, marked price of article = 4b + 800
Total discount offered = 800 x 75% = Rs. 600
Selling price of article = 5b x (1 – 1/15) = 14b/3
Now,
14b/3 + 600 = 4b + 800
2b/3 = 200
Value of b = 300
So, cost price of article = 300 x 4 = 1200
Marked price of article = 1200 + 800 = Rs. 2000
Selling price of article after first discount = 5 x
300 = 1500
So, (L – 5) = (2000 – 1500)/2000 x 100 = 25
Value of L = 25 + 5 = 30
For R
Total discount offered is Rs. 308 which is Rs. 8
more than that of article R.
Let cost price of article = c
So, marked price of article = 2 x c = 2c
Selling price after first discount = 175% x c =
7c/4
Total discount offered = Rs. 300
Ratio of marked price and selling price after first
discount = 2c:7c/4 = 8:7
So, value of Y% = (8 – 7)/8 x 100 = 12.5%
So, selling price after second discount = 7c/4 x
5/7 = 5c/4
Total discount offered = 2c – 5c/4 = 3c/4
So, 3c/4 = 300
Value of c = Rs. 400
For article S
Let cost price of article = Rs. d
Marked price of article = (d + 600)
Selling price after first discount = 1.52 x d =
1.52d
Selling price after second discount = 1.52d x
(100 – 12.5 x 1.2)/100 = 1.292d
Now,
(d + 600) – 1.292d = 308
0.292d = 292
So, value of d = 1000
So, marked price of article = 1000 + 600 = 1600
Selling price after first discount = 1.52 x 1000 =
1520
So, value of K = (1600 – 1520)/1600 x 100 = 5%
1.
According to question,
Value of Z = 20
Value of Y = 12.5
Required % change = (20 – 12.5)/12.5 x 100 = 60% (B)
2.
% Profit earned on article Q = (1400 –
1200)/1200 x 100 = (50/3) %
% Profit earned on article S = (1292 –
1000)/1000 x 100 = 29.2%
Required value = 15 x 29.2 x 50/3 x 1/100 = 73 (A)
3.
Article R
Selling price of article = Rs. 500
Discount % given = (10 x 5)/3 = 50/3%
So, new marked price of article = 500 x 6/5 =
Rs. 600
Mark up % = 7 x 12.5% = 87.5%
So, new cost price of article = 8/15 x 600 = Rs 320 (D)
4.
Value of C = 1600 – 1200 = 400
Value of D = 2000 – 800 = 1200
Required difference = 1200 – 400 = 800 (E)
5.
Cost price of (R + S) = 400 + 1000 = 1400
Cost price of (P + Q) = 800 + 1200 = 2000
Required % change = (2000 – 1400)/2000 x 100
= 30% (C)
2 918
Detailed Solution:
For P
Let the cost price of article = 100a
Article is marked up by 50%, so its marked price
= 100a x 150% = 150a
Selling price of article after first discount = 100a
x 120% = 120a
Now,
(100 – Z) = 120a/150a x 100
So, value of Z = 20
Total discount offered = Rs. 336
Now,
150a – 150a x 80% x 90% = 336
42a = 336
So, value of a = 336/42 = 8
So, cost price of article = 8 x 100 = Rs. 800
Marked price of article = 800 x 1.5 = Rs. 1200
Selling price of article = 1200 x 80% x 90% = Rs. 864
