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Codeforces|Leetcode|Codechef free solutions

Codeforces|Leetcode|Codechef free solutions

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Free codeforces, Codechef, Leetcode solutions are available 😍😍😍😍😍😍 Helped More than 200+ students to crack coding round in 2022 and helped placed them in Good companies. 🥳🥳🥳🤩🤩🤩 Dm @Cpsoln if you want help in coding round.

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Leetcode B

class Solution { public:     bool isPrime(int num) {     if (num < 2)         return false;     for (int i = 2; i * i <= num; i++) {         if (num % i == 0)             return false;     }     return true; }     vector> findPrimePairs(int n) {          vector> primePairs;     for (int x = 2; x <= n / 2; x++) {         int y = n - x;         if (isPrime(x) && isPrime(y)) {             primePairs.push_back({x, y});         }     }     return primePairs;     } };

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Leetcode C 🥳🥳🥳

#include <deque> #include <vector> class Solution { public:     int continuousSubarrays(std::vector<int>& nums) {         std::deque<int> maxQ;         std::deque<int> minQ;         int left = 0;         int res = 0;         for (int right = 0; right < nums.size(); right++) {             while (!maxQ.empty() && nums[maxQ.back()] < nums[right]) {                 maxQ.pop_back();             }             maxQ.push_back(right);             while (!minQ.empty() && nums[minQ.back()] > nums[right]) {                 minQ.pop_back();             }             minQ.push_back(right);             while (nums[maxQ.front()] - nums[minQ.front()] > 2) {                 if (maxQ.front() < minQ.front()) {                     left = maxQ.front() + 1;                     maxQ.pop_front();                 } else {                     left = minQ.front() + 1;                     minQ.pop_front();                 }             }             res += right - left + 1;         }         return res;     } };

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