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GeeksForGeeks - POTD | GFG POTD Answer

GeeksForGeeks - POTD | GFG POTD Answer

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19th July : C++ Solution ☝🏼

class Solution{ public: int longestPalinSubseq(string A) { int n=A.length(); string B=A; reverse(B.begin(),B.end()); vector prev(n+1,0),curr(n+1,0); for(int i=1; i<=n; i++){ for(int j=1; j<=n; j++){ if(A[i-1]==B[j-1]) curr[j]=1+prev[j-1]; else curr[j]=max(curr[j-1],prev[j]); } prev=curr; } return curr[n]; } };

18th July : C++ Solution ☝🏼

class Solution { public: int LongestRepeatingSubsequence(string str){ vector>v(str.length()+1,vector(str.length()+1,0)); for(int i=1;i<=str.length();i++) { for(int j=1;j<=str.length();j++) { if(str[i-1]==str[j-1] && i!=j) { v[i][j]=1+v[i-1][j-1]; } else{ v[i][j]=max(v[i-1][j],v[i][j-1]); } } } return v[str.length()][str.length()]; } };

15th July : C++ Solution ☝🏼

class Solution { public: //Function to delete middle element of a stack. void deleteMid(stack<int>&s, int sizeOfStack) { helper(s, sizeOfStack, 0); } void helper(std::stack<int>& s, int n, int idx) { if (idx == n/2) { s.pop(); return; } int x = s.top(); s.pop(); idx++; helper(s, n, idx); s.push(x); } };

14th July : C++ Solution ☝🏼

class twoStacks { int *arr; int size; int top1, top2; public: twoStacks(int n=100) { size = n; arr = new int[n]; top1 = -1; top2 = size; } //Function to push an integer into the stack1. void push1(int x) { top1++; if(top1<(top2-1)) arr[top1]=x; } //Function to push an integer into the stack2. void push2(int x) { top2--; if((top2-1)>top1) arr[top2]=x; } //Function to remove an element from top of the stack1. int pop1() { if(top1==-1)return -1; top1--; return arr[top1+1]; } //Function to remove an element from top of the stack2. int pop2() { if(top2==size)return -1; top2++; return arr[top2-1]; } };

13th July : C++ Solution ☝🏼

class Solution { public: bool isFrequencyUnique(int n, int arr[]) { unordered_map mp; for(int i=0;i st; for(auto it:mp) st.insert(it.second); return mp.size()==st.size()?true:false; } };

12th July : C++ Solution ☝🏼

class Solution { public: long long power(int N, int R) { // Calculate the power of N raised to R modulo 1e9 + 7 long long pow = N; long long ans = 1; int mod = 1e9 + 7; while (R > 0) { if (R & 1) { ans = (ans * pow) % mod; } pow = (pow * pow) % mod; R = R >> 1; } return ans; } };

11th July : C++ Solution ☝🏼

class Solution { public: int findK(int a[MAX][MAX],int n,int m,int k) { int sr = 0, er = n-1, sc = 0, ec = m-1; while(sr <= er || sc <= ec) { if(sr <= er) { int dif = max((ec-sc+1),0); if(dif < k) { k -= dif; } else { return a[sr][sc + k - 1]; } sr++; } if(sc <= ec) { int dif = max(0,er-sr+1); if(dif < k) { k -= dif; } else { return a[sr+k-1][ec]; } ec--; } if(sr <= er) { int dif = max(0, ec-sc+1); if(dif < k) { k -= dif; } else { return a[er][ec-k+1]; } er--; } if(sc <= ec) { int dif = max(0, er-sr+1); if(dif < k) { k -= dif; } else { return a[er - k + 1][sc]; } sc++; } } return -1; } };

10th July : C++ Solution ☝🏼

class Solution { public: //Function to find transpose of a matrix. void transpose(vector >& matrix, int n) { int ans[n][n]; for(int i=0;i

9th July : C++ Solution ☝🏼

class Solution { public: // Function to find the smallest positive number missing from the array. int missingNumber(int arr[], int n) { // Segregate positive and non-positive elements int i = 0; for (int j = 0; j < n; j++) { if (arr[j] <= 0) { swap(arr[i], arr[j]); i++; } } // Consider only positive elements from index i onwards int size = n - i; for (int j = i; j < n; j++) { int num = abs(arr[j]); if (num <= size) { arr[i + num - 1] = -abs(arr[i + num - 1]); } } // Find the first positive element for (int j = i; j < n; j++) { if (arr[j] > 0) { return j - i + 1; } } // If all positive elements are present, return n - i + 1 return size + 1; } };

8th July : C++ Solution ☝🏼

class Solution{ public: //Function to find triplets with zero sum. bool findTriplets(int arr[], int n) { mapmp; for(int i=0;i=1)break; } return count; } };