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Learn Python Coding

Learn Python Coding

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Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho

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📈 Análisis del canal de Telegram Learn Python Coding

El canal Learn Python Coding (@pythonre) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 40 881 suscriptores, ocupando la posición 3 287 en la categoría Tecnologías y Aplicaciones y el puesto 9 164 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 40 881 suscriptores.

Según los últimos datos del 29 octubre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 336, y en las últimas 24 horas de 1, conservando un alto alcance.

  • Estado de verificación: No verificado
  • Tasa de interacción (ER): El promedio de interacción de la audiencia es 5.33%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 1.52% de reacciones respecto al total de suscriptores.
  • Alcance de las publicaciones: Cada publicación recibe en promedio 2 179 visualizaciones. En el primer día suele acumular 622 visualizaciones.
  • Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 3.
  • Intereses temáticos: El contenido se centra en temas clave como math, harvard, oxford, supervision, waybienad.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho”

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 30 octubre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.

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✨ How to Create a Django Project ✨ 📖 Learn how to create a Django project and app in clear, guided steps. Use it as a refere
✨ How to Create a Django Project ✨ 📖 Learn how to create a Django project and app in clear, guided steps. Use it as a reference for any future Django project and tutorial you'll work on. 🏷️ #basics #best-practices #django #web-dev

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Accelerating the Sieve of Eratosthenes 1. Quickly recall the algorithm Classic implementation:
def eratosthenes(n):
    is_prime = [True] * (n + 1)
    is_prime[0] = is_prime[1] = False

    for i in range(2, int(n ** 0.5) + 1):
        if is_prime[i]:
            for j in range(i * i, n + 1, i):
                is_prime[j] = False

    return is_prime
Time — O(N log log N). We're not interested in the asymptotics, but in how much we can speed up the implementation itself. 2. Optimization #1 — don't bother with even numbers The idea is simple: * all even numbers except 2 are composite * if we only work with odd numbers, we reduce the array size and the number of iterations by about half Implementation:
def eratosthenes_odd(n):
    if n < 2:
        return []

    size = (n + 1) // 2
    is_prime = [True] * size
    is_prime[0] = False

    limit = int(n ** 0.5) // 2
    for i in range(1, limit + 1):
        if is_prime[i]:
            p = 2 * i + 1
            start = (p * p) // 2
            for j in range(start, size, p):
                is_prime[j] = False

    return is_prime
3. Optimization #2 — use bytearray instead of list[bool] Thought: * bool in Python is an object * bytearray is a tightly packed buffer * less overhead and better fits into the CPU cache Example:
def eratosthenes_bytearray(n):
    is_prime = bytearray(b"\x01") * (n + 1)
    is_prime[0:2] = b"\x00\x00"

    for i in range(2, int(n ** 0.5) + 1):
        if is_prime[i]:
            for j in range(i * i, n + 1, i):
                is_prime[j] = 0

    return is_prime
4. Optimization #3 — a hybrid of the two approaches
def eratosthenes_fast(n):
    if n < 2:
        return []

    size = (n + 1) // 2
    is_prime = bytearray(b"\x01") * size
    is_prime[0] = 0

    limit = int(n ** 0.5) // 2
    for i in range(1, limit + 1):
        if is_prime[i]:
            p = 2 * i + 1
            start = (p * p) // 2
            is_prime[start::p] = b"\x00" * (((size - start - 1) // p) + 1)

    return is_prime
5. Time comparison Test with n = 10_000_000: >>> eratosthenes.py real  0.634s >>> eratosthenes_odd.py real  0.245s >>> eratosthenes_bytearray.py real  0.801s >>> eratosthenes_fast.py real  0.028s Conclusions: * skipping even numbers (#1) gives ~2.6× speedup * bytearray itself doesn't speed up — it's more about memory * the hybrid (#3) gives ~22.6× speedup Key trick in #3:
is_prime[start::p] = b"\x00" * (((size - start - 1) // p) + 1)
There's no Python loop here — everything is done by a C-level operation on the slice. On such tasks, this makes a huge difference. General idea: in Python, we often speed up not the asymptotics, but the memory model and the number of passes over the data. Loops + memory → the main factors. 👉 @DataScience4

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✨ dataframe | Python Glossary ✨ 📖 A data structure for working with tabular data in Python. 🏷️ #Python

✨ assertion | Python Glossary ✨ 📖 A debugging aid that tests a condition as an internal self-check. 🏷️ #Python

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