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8 173
1) Answer: e)
Downstream speed of boat A= 135/9= 15 km/hr
Let the speed of boat A be x
So,
x +2= 15
x= 13kmph
Upstream distance travelled by boat A= 135*2/5= 54km
Upstream speed of boat A= 13-2= 11km/hr
Time taken to travel upstream= 54/11= 4(10/11) hour
2) Answer: b)
Upstream speed of boat C= 12 – 4= 8km/hr
Distance travelled upstream= 8*8= 64km
Downstream distance travelled by boat C= 64*7/4= 112km
Speed downstream= 12+4= 16km/hr
Time taken to travel downstream= 112/16= 7 hours
3) Answer: c)
Speed of boat F downstream= 18+4= 22 km/hr
Speed upstream= 18 – 4= 14 km/hr
Now,
x/ 14 = (x+20) / 22
22x= 14x+280
8x= 280
x = 35km
4) Answer: e)
Let the speed of boat B and E be x
Upstream speed of boat B= x-6
Upstream speed of boat E= x-3
So,
8(x-6) + 8(x-3) = 120
8x – 48 + 8x – 24= 120
16x–72= 120
16x= 192
x = 12km/hr
So,
Downstream speed of boat E= 12+3= 15km/hr
Time taken to travel downstream 165km= 165/15= 11 hours.
5) Answer: d)
Let the speed of the current for boat D be x
Upstream speed= 14-x
Downstream speed= 14+x
So,
(14 – x) / (14+x) = 2/5
70-5x = 28+2x
42 = 7x
x = 6km/hr
Upstream distance travelled by boat D= 64*5/8= 40km
Upstream speed of boat D= 14-6= 8km/hr
Time taken= 40/8= 5 hours.
8 173
1) If boat A travelled 135 km downstream in 9 hours, then find how much time boat A will take to travel the upstream distance?
यदि नाव A ने 9 घंटे में धारा के अनुकूल 135 किमी की यात्रा की, तो ज्ञात कीजिए कि नाव A को धारा के प्रतिकूल दूरी तय करने में कितना समय लगेगा?
a) 24
b) 18
c) 16(1/7)
d) 4(8/9)
e) 4(10/11)
2) If the speed of boat C is 12 km/hr and the time taken to travel upstream distance is 8 hours then find time taken by boat C to travel downstream distance?
यदि नाव C की गति 12 किमी/घंटा है और धारा के प्रतिकूल दूरी तय करने में लगने वाला समय 8 घंटे है, तो नाव C द्वारा अनुप्रवाह दूरी तय करने में लिया गया समय ज्ञात कीजिए?
a) 2
b) 7
c) 6
d) 8
e) 4
3) If the upstream distance travelled by boat F is ‘x’ while the downstream distance travelled by boat F is ‘x+20’ and the time taken to travel downstream and upstream is equal then find the value of x?
यदि नाव F द्वारा तय की गई धारा के प्रतिकूल दूरी 'x' है, जबकि नाव F द्वारा तय की गई धारा के अनुकूल दूरी 'x+20' है और धारा के अनुकूल और धारा के प्रतिकूल यात्रा करने में लिया गया समय समान है, तो x का मान ज्ञात कीजिए?
a) 24
b) 18
c) 35
d) 48
e) 40
4) If the total upstream distance travelled by boat B and E in 8 hours is equal to 120 km while the speed of these boats is equal then find time taken by boat E to travel downstream distance of 165 km?
यदि 8 घंटे में नाव B और E द्वारा तय की गई कुल धारा के प्रतिकूल दूरी 120 किमी के बराबर है, जबकि इन नावों की गति समान है, तो नाव E द्वारा धारा के अनुकूल 165 किमी की दूरी तय करने में लिया गया समय ज्ञात कीजिए?
a) 4
b) 10
c) 6
d) 8
e) 11
5) If the ratio between the upstream and downstream speed of boat D is 2:5 and the downstream distance travelled by boat D is 64km then find the time taken by boat D to travel upstream distance?
यदि नाव D की धारा के प्रतिकूल और धारा के अनुकूल गति का अनुपात 2:5 है और नाव D द्वारा तय की गई अनुप्रवाह दूरी 64 किमी है, तो नाव D द्वारा धारा के प्रतिकूल दूरी तय करने में लिया गया समय ज्ञात कीजिए?
a) 4
b) 8
c) 6
d) 5
e) 7
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8 173
The following table shows the data related to speed of different boats and speed of current. Some values are missing here.
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8 173
Ratio of type A to type B milk in mixture P = 0.75: 1 = 3: 4
Ratio of type A to type B milk in mixture Q = 2: 1
Ratio of type A to type B milk in mixture R = 1.5: 1 = 3: 2
Ratio of type A to type B milk in mixture S = 0.40: 1 = 2: 5
Ratio of type A to type B milk in mixture T = 0.5: 1 = 1: 2
1) Answer: a)
Mixture P:
Type C milk = 25 litres
Type B milk = 25 – 5 = 20 litres
Type A milk = 20 * (3/4) = 15 litres
Part of type A milk = 15/(25 + 20 + 15) = 1/4
Mixture Q:
Type C milk = 15 litres
Type A milk = 15 * (4/3) = 20 litres
Type B milk = 20 * (1/2) = 10 litres
Part of type A milk = 20/(15 + 20 + 10) = 4/9
By the rule of allegation:
[(4/9) – M]: [M – (1/4)] = 4: 3
(4/3) – 3M = 4M – 1
7M = 7/3
M = 1/3
Required per cent = (1/3) * 100 = 33(1/3)%
2) Answer: d)
Mixture Q:
Type C milk = 15 litres
Type A milk = (30 – 15) * (2/3) = 10 litres
Type B milk = (30 – 15) * (1/3) = 5 litres
Part of type A milk = 10/(15 + 10 + 5) = 1/3
Part of type B milk = 5/(15 + 10 + 5) = 1/6
Mixture R:
Type C milk = 25 litres
Type A milk = (50 – 25) * (3/5) = 15 litres
Type B milk = (50 – 25) * (2/5) = 10 litres
Part of type A milk = 15/(25 + 15 + 10) = 3/10
Part of type B milk = 10/(25 + 15 + 10) = 1/5
By the rule of alligation:
[(3/10) – X]: [X – (1/3)] = 6: 5
(3/2) – 5X = 6X – 2
11X = 7/2
X = 7/22
By the rule of alligation:
[(1/5) – Y]: [Y – (1/6)] = 6: 5
1 – 5Y = 6Y – 1
11Y = 2
Y = 2/11 = 4/22
Required ratio = 7: 4: (22 – 7 – 4) = 7: 4: 11
3) Answer: e)
Let amount of type A and type B milk in mixture P is 3p and 4p respectively.
Type B milk in mixture R = 30 litres
Type A milk in mixture R = 30 * (3/2) = 45 litres
Total quantity of mixture R = 45 + 30 + 25 = 100 litres
Amount of type A milk in mixture Z = (3p + 45)
Amount of type C milk in mixture Z = 25 + 25 = 50 litres
According to the question:
(3p + 45): 50 = 9: 5
15p + 225 = 450
15p = 225
p = 15
Hence, required difference = 3p ~ 45 = 45 – 45 = 0 litres
4) Answer: c)
Let type A milk in mixture R and S is 6x each.
Type B milk in mixture R = 6x * (2/3) = 4x
Type B milk in mixture S = 6x * (5/2) = 15x
Part of type C milk in mixture R = 25/(10x + 25)
Part of type C milk in mixture S = 5/(21x + 5)
By the rule of alligation:
[{5/(21x + 5)} – (6/37)]: [(6/37) – {25/(10x + 25)}] = 15: 22
[110/(21x + 5)] – (132/37) = (90/37) – [375/(10x + 25)]
[110/(21x + 5)] + [375/(10x + 25] = 6
110(10x + 25) + 375(21x + 5) = 6(10x + 25)(21x + 5)
1100x + 2750 + 7875x + 1875 = 1260x2 + 3450x + 750
1260x2 – 5525x – 3875 = 0
252x2 – 1105x – 775 = 0
x = 5 and -155/252 (Not valid)
Amount of type A milk in mixture Z = 6x + 6x = 12x = 60
Amount of type B milk in mixture Z = 4x + 15x = 19x = 95
Amount of type C milk in mixture Z = 25 + 5 = 30
Cost price of mixture Z = (60 * 3) + (95 * 2) + (30 * 1) = 400
Selling price of mixture Z = (60 + 95 + 30) * 3 = 555
Required profit per cent = [(555 – 400)/400] * 100 = 38.75%
5) Answer: a)
In 180 litres of mixture M:
Amount of mixture R = 180 * (4/9) = 80 litres
Ratio of type A, type B and type C milk in mixture R = 2: 5: 1
Amount of mixture S = 180 * (5/9) = 100 litres
Ratio of type A, type B and type C milk in mixture S = 1: 2: 2
Type B milk in mixture M = [80 * (5/8)] + [100 * (2/5)] = 50 + 40 = 90 litres
Type C milk in mixture M = [80 * (1/8)] + [100 * (2/5)] = 10 + 40 = 50 litres
Required difference = 90 – 50 = 40 litres
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1)If in mixture P, type C milk is 5 litres more than type B milk and ratio of type A to type C milk in the mixture Q is 4: 3. If mixture P and Q are mixed in the ratio 4: 3 to form mixture M, then out of total amount of mixture M, what per cent are type A milk?
यदि मिश्रण P में, प्रकार C का दूध, B प्रकार के दूध से 5 लीटर अधिक है और मिश्रण Q में प्रकार A से प्रकार C के दूध का अनुपात 4:3 है। यदि मिश्रण P और Q को 4:3 के अनुपात में मिलाकर मिश्रण बनाया जाता है। M, तो मिश्रण M की कुल मात्रा में से, A प्रकार के दूध कितने प्रतिशत हैं?
a) 33(1/3)%
b) 25%
c) 26(2/3)%
d) 40%
e) None of these
2) If total quantity of mixture Q and R is 30 litres and 50 litres respectively. If these two mixtures are mixed in the ratio 6: 5 respectively to form mixture N, then what is the ratio of type A, type B and type C milk respectively in mixture N?
यदि मिश्रण Q और R की कुल मात्रा क्रमशः 30 लीटर और 50 लीटर है। यदि इन दोनों मिश्रणों को मिश्रण N बनाने के लिए क्रमशः 6:5 के अनुपात में मिलाया जाता है, तो मिश्रण N में क्रमशः A प्रकार, B प्रकार और C प्रकार के दूध का अनुपात क्या है?
a) 8: 5: 9
b) 9: 3: 10
c) 6: 9: 7
d) 7: 4: 11
e) None of these
3) Mixture P and R are mixed completely to form mixture Z. Now, ratio of type A, type B and type C milk in the mixture Z becomes 9: 9: 5, then what is the difference between the amount of type A milk in mixture P and mixture R if amount of type B milk in mixture R is 30 litres?
मिश्रण Z बनाने के लिए मिश्रण P और R को पूरी तरह मिला दिया जाता है। अब, मिश्रण Z में प्रकार A, प्रकार B और प्रकार C के दूध का अनुपात 9:9:5 हो जाता है, तो मिश्रण में A प्रकार के दूध की मात्रा के बीच का अंतर कितना है? P और मिश्रण R, यदि मिश्रण R में B प्रकार के दूध की मात्रा 30 लीटर है?
a) 24 litres
b) 12 litres
c) 21 litres
d) 25 litres
e) None of these
4) Amount of type A milk in mixtures R and S are same and these two mixtures are mixed in the ratio 15: 22 to form mixture Z and amount of type C milk in mixture Z becomes (6/37). If the ratio of cost price of type A, type B and type C milk is 3: 2: 1 respectively and mixture Z is sold at the cost of type A milk, then what is the profit per cent earned?
मिश्रण R और S में A प्रकार के दूध की मात्रा समान है और इन दोनों मिश्रणों को मिश्रण Z बनाने के लिए 15:22 के अनुपात में मिलाया जाता है और मिश्रण Z में C प्रकार के दूध की मात्रा (6/37) हो जाती है। यदि प्रकार A, प्रकार B और प्रकार C के दूध के क्रय मूल्य का अनुपात क्रमशः 3: 2: 1 है और मिश्रण Z को A प्रकार के दूध की कीमत पर बेचा जाता है, तो अर्जित लाभ प्रतिशत क्या है?
a) 41.25%
b) 36.25%
c) 38.75%
d) 47.75%
e) None of these
5) Ratio of type B to type C milk in mixture S and T is 5: 1 and 1: 1 respectively. If these two mixtures are mixed in the ratio 4: 5 to form mixture M, what is the difference between type B and type C milk in 180 litres of mixture M?
मिश्रण S और T में प्रकार B का C के दूध से अनुपात क्रमशः 5: 1 और 1: 1 है। यदि इन दोनों मिश्रणों को मिश्रण M बनाने के लिए 4:5 के अनुपात में मिलाया जाता है, तो 180 लीटर मिश्रण M में प्रकार B और प्रकार C के दूध में क्या अंतर है?
a) 40 litres
b) 25 litres
c) 50 litres
d) 30 litres
e) None of these
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8 173
Pie chart shows the distribution (degree) of type C milk in those five mixture and sum of the pie chart is 80 litres.
पाई चार्ट उन पांच मिश्रणों में सी प्रकार के दूध का वितरण (डिग्री) दिखाता है और पाई चार्ट का योग 80 लीटर है।
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8 173
There are five different mixture of milk of three types A, B and C. Bar graph given below shows the ratio of type A milk to type B milk in those five different mixtures.
पाई चार्ट उन पांच मिश्रणों में सी प्रकार के दूध का वितरण (डिग्री) दिखाता है और पाई चार्ट का योग 80 लीटर है।
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8 173
6) Answer: a)
The unsold bikes of company A in the year 2012, 2013 and 2014 together
= > (132 – 130) + (130 – 129) + (136 – 133)
= > 2 + 1 + 3 = 6 lakhs
The unsold bikes of company C in the year 2011, 2013 and 2015 together
= > (136 – 134) + (142 – 140) + (154 – 151)
= > 2 + 2 + 3 = 7 lakhs
Required difference = 7 – 6 = 1 lakh
7) Answer: d)
Total production of all the given companies together in the year 2012
= > 132 + 138 + 140 = 410 lakhs
Total production of all the given companies together in the year 2015
= > 144 + 156 + 154 = 454 lakhs
Required % = (410/454)*100 = 90.308 % = 90 %
8) Answer: b)
The average sales of company A in all the given years together
= > (124 + 130 + 129 + 133 + 142)/5 = 658/5
The average sales of company B in all the given years together
= > (132 + 137 + 142 + 148 + 154)/5 = 713/5
Required difference = (713/5) – (658/5) = 55/5 = 11 lakhs
9) Answer: d)
The unsold bikes in the year 2013 in all the given companies together
= > (130 – 129) + (146 – 142) + (142 – 140)
= > 1 + 4 + 2 = 7 lakhs
The unsold bikes in the year 2015 in all the given companies together
= > (144 – 142) + (156 – 154) + (154 – 151)
= > 2 + 2 + 3 = 7 lakhs
Required ratio = 7 : 7 = 1 : 1
10) Answer: c)
The average production of bikes of company A in all the given years together
= > (128 + 132 + 130 + 136 + 144)/5
= > 670/5 = 134 lakhs
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6) Find the difference between the unsold bikes of company A in the year 2012, 2013 and 2014 together to that of company C in the year 2011, 2013 and 2015 together?
वर्ष 2012, 2013 और 2014 में एक साथ कंपनी A की बिना बिकी बाइक और वर्ष 2011, 2013 और 2015 में मिलाकर कंपनी C की बिना बिकी बाइक के बीच का अंतर ज्ञात कीजिए?
a) 1 lakh
b) 2 lakhs
c) 4 lakhs
d) 3 lakhs
e) None of these
7) Total production of all the given companies together in the year 2012 is approximately what percentage of total production of all the given companies together in the year 2015?
वर्ष 2012 में सभी दी गई कंपनियों का कुल उत्पादन, वर्ष 2015 में दी गई सभी कंपनियों के कुल उत्पादन का लगभग कितना प्रतिशत है?
a) 105 %
b) 75 %
c) 120 %
d) 90 %
e) 140 %
8) Find the difference between the average sales of company A to that of company B in all the given years together?
दिए गए सभी वर्षों में कंपनी A की कंपनी B की औसत बिक्री के बीच का अंतर ज्ञात कीजिए?
a) 15 lakhs
b) 11 lakhs
c) 13 lakhs
d) 16 lakhs
e) None of these
9) Find the ratio between the unsold bikes in the year 2013 to that of 2015 in all the given companies together?
दी गई सभी कंपनियों में मिलाकर वर्ष 2013 में न बिकी बाइक्स से 2015 की बाइकों का अनुपात ज्ञात कीजिए?
a) 2 : 3
b) 1 : 2
c) 4 : 3
d) 1 : 1
e) None of these
10) Find the average production of bikes of company A in all the given years together?
दिए गए सभी वर्षों में कंपनी A की बाइकों का औसत उत्पादन ज्ञात कीजिए?
a) 142 lakhs
b) 146 lakhs
c) 134 lakhs
d) 138 lakhs
e) None of these
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8 173
The following table shows the production and sales of bikes (In lakhs) in different companies in different years.
निम्न तालिका अलग-अलग वर्षों में विभिन्न कंपनियों में बाइक के उत्पादन और बिक्री (लाखों में) को दर्शाती है।
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8 173
Presenting Abhyaas Feb 2022 Magazine PDF by Aashish Arora
Target Exams - All Bank Exams 2022
8 173
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8 173
🔰The Hindu Vocabulary For All Competitive Exams | 19-02-2022🔰
1. DEFALCATION (NOUN): (गबन): default
Synonyms: disaster, failure
Antonyms: accomplishment, achievement
Example Sentence:
Ravi made defalcation in funds.
2. CANDOR (NOUN): (निष्कपटता): frankness
Synonyms: directness, fairness
Antonyms: dishonesty, unfairness
Example Sentence:
She has done her task with complete candor.
3. CESSATION (NOUN): (ठहराव): abeyance
Synonyms: breather, discontinuance
Antonyms: activity, continuity
Example Sentence:
Since the bad weather has caused a temporary building cessation, the office building will not be completed on time.
4. DEVIOUS (ADJECTIVE): (कपटी): deceitful
Synonyms: duplicitous, insidious
Antonyms: honest, forthright
Example Sentence:
He plays a devious character.
5. DISPARATE (ADJECTIVE): (भिन्न): contrasting
Synonyms: discordant, diverse
Antonyms: agreeing, alike
Example Sentence:
Anamika made disparate arguments.
6. DISTRAUGHT (ADJECTIVE): (व्याकुल): very upset
Synonyms: agitated, anxious
Antonyms: balanced, calm
Example Sentence:
She burst into a little peal of laughter as she looked into his distraught face.
7. EXTRICATE (VERB): (अलग करना): get out of a situation
Synonyms: detach, extract
Antonyms: attach, connect
Example Sentence:
Amay was trying to extricate himself from official duties.
8. RIG (VERB): (वस्र पहनना): dress
Synonyms: equip, furnish
Antonyms: disrobe, uncover
Example Sentence:
The children return from Box Hill, and are rigged out for church.
9. ENTANGLE (VERB): (उलझाना): involve
Synonyms: confuse, complicate
Antonyms: clarify, exclude
Example Sentence:
Don’t entangle those people in your project as they are not trustworthy.
10. PREMEDITATED (ADJECTIVE): (पूर्वचिन्तित): planned
Synonyms: calculated, deliberate
Antonyms: accidental, casual
Example Sentence:
Had it really been premeditated that he should fall into that camp?
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6) Answer: a)
The total number of sports watches sold by store P
= > [66000*(12/100) – 24000*(14/100)]
= > [7920 – 3360] = 4560
The total number of luxury watches sold by store Q and T together
= > 24000*(38/100) = 9120
Required ratio = 4560 : 9120 = 1: 2
7) Answer: d)
The total number of sports watches sold by store R
= > [66000*(19/100) – 24000*(17/100)]
= > 12540 – 4080 = 8460
The total number of sports watches sold by store U
= > [66000*(17/100) – 24000*(11/100)]
= > 11220 – 2640 = 8580
Required difference = 8580 – 8460 = 120
8) Answer: b)
Total number of watches sold by store R and S together
= > 66000*(40/100) = 26400
Total number of luxury watches sold by store P, S and T together
= > 24000*(56/100) = 13440
Required % = (26400/13440)*100 = 196.42 % = 197 %
9) Answer: c)
The total number of sports watches sold by store R, S and T together
= > [66000*(19/100) – 24000*(17/100)] + [66000*(21/100) – 24000*(20/100)] + [66000*(16/100) – 24000*(22/100)]
= > (12540 – 4080) + (13860 – 4800) + (10560 – 5280)
= > 8460 + 9060 + 5280 = 22800
Required average = 22800/3 = 7600
10) Answer: a)
Total number of sports watches sold by store Q
= > [66000*(15/100) – 24000*(16/100)]
= > (9900 – 3840) = 6060
Total number of luxury watches sold by store R
= > 24000*(17/100) = 4080
Required % = [(6060 – 4080)/4080]*100 = 48.529 % = 50 % more
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6) Find the ratio between the total number of sports watches sold by store P to that of total number of luxury watches sold by store Q and T together?
स्टोर P द्वारा बेची गई स्पोर्ट्स घड़ियों की कुल संख्या और स्टोर Q और T द्वारा मिलाकर बेची गई लग्ज़री घड़ियों की कुल संख्या के बीच का अनुपात ज्ञात कीजिए?
a) 1 : 2
b) 3 : 4
c) 2 : 3
d) 5 : 6
e) None of these
7) Find the difference between the total number of sports watches sold by store R to that of store U?
स्टोर R द्वारा स्टोर U की बेची गई स्पोर्ट्स घड़ियों की कुल संख्या के बीच का अंतर ज्ञात कीजिए?
a) 260
b) 180
c) 340
d) 120
e) None of these
8) Total number of watches sold by store R and S together is approximately what percentage of total number of luxury watches sold by store P, S and T together?
स्टोर R और S द्वारा मिलाकर बेची गई घड़ियों की कुल संख्या, स्टोर P, S और T द्वारा मिलाकर बेची गई लग्ज़री घड़ियों की कुल संख्या का लगभग कितना प्रतिशत है?
a) 182 %
b) 197 %
c) 166 %
d) 145 %
e) 214 %
9) Find the average number of sports watches sold by store R, S and T together?
स्टोर R, S और T द्वारा मिलाकर बेची गई स्पोर्ट्स घड़ियों की औसत संख्या ज्ञात कीजिए?
a) 8000
b) 7250
c) 7600
d) 7850
e) None of these
10) Total number of sports watches sold by store Q is approximately what percentage more/less than the total number of luxury watches sold by store R?
स्टोर Q द्वारा बेची जाने वाली स्पोर्ट्स घड़ियों की कुल संख्या, स्टोर R द्वारा बेची गई लक्जरी घड़ियों की कुल संख्या से लगभग कितने प्रतिशत अधिक/कम है?
a) 50 % more
b) 40 % less
c) 40 % more
d) 30 % more
e) 50 % more
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The pie chart2 shows the total number of luxury watches sold by those 6 stores in the year.
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