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allcoding1_official

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📈 Análisis del canal de Telegram allcoding1_official

El canal allcoding1_official (@allcoding1_official) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 82 254 suscriptores, ocupando la posición 1 512 en la categoría Tecnologías y Aplicaciones y el puesto 3 707 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 82 254 suscriptores.

Según los últimos datos del 25 agosto, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -1 572, y en las últimas 24 horas de -40, conservando un alto alcance.

  • Estado de verificación: No verificado
  • Tasa de interacción (ER): El promedio de interacción de la audiencia es 3.02%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 0.71% de reacciones respecto al total de suscriptores.
  • Alcance de las publicaciones: Cada publicación recibe en promedio 2 481 visualizaciones. En el primer día suele acumular 588 visualizaciones.
  • Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 0.
  • Intereses temáticos: El contenido se centra en temas clave como dsa, stack, namaste, javascript, dev.

📝 Descripción y política de contenido

No se ha proporcionado la descripción del canal.

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 26 agosto, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.

82 254
Suscriptores
-4024 horas
-2997 días
-1 57230 días
Archivo de publicaciones
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import java.util.*; class Main { public static int solve(int N, String colors, int[] neededTime) { long answer = 0; int i = 0; while (i < N) { int j = i; while (j + 1 < N && colors.charAt(j + 1) == colors.charAt(i)) j++; int len = j - i + 1; if (len >= 2) { long keep = 0; long diffuse = neededTime[i]; for (int k = i + 1; k <= j; k++) { long newKeep = diffuse; long newDiffuse = Math.min(keep, diffuse) + neededTime[k]; keep = newKeep; diffuse = newDiffuse; } answer += Math.min(keep, diffuse); } i = j + 1; } return (int) answer; }

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import java.util.*; class Main { public static int solve(String word1, String word2) { int n = word1.length(); int m = word2.length(); final int INF = 1_000_000; int[][][] dp = new int[n + 1][m + 1][2]; for (int i = 0; i <= n; i++) { for (int j = 0; j <= m; j++) { dp[i][j][0] = INF; dp[i][j][1] = INF; } } dp[n][m][0] = 0; dp[n][m][1] = 0; for (int i = n; i >= 0; i--) { for (int j = m; j >= 0; j--) { for (int p = 0; p < 2; p++) { if (i == n && j == m) continue; int ans = INF; if (i < n) { ans = Math.min(ans, 1 + dp[i + 1][j][p ^ 1]); } if (j < m) { ans = Math.min(ans, 1 + dp[i][j + 1][p ^ 1]); } if (i < n && j < m) { char c = word1.charAt(i); if (p == 1) { c = (char) ('a' + (c - 'a' + 13) % 26); } if (c == word2.charAt(j)) ans = Math.min(ans, dp[i + 1][j + 1][p]); else ans = Math.min(ans, 1 + dp[i + 1][j + 1][p]); } dp[i][j][p] = ans; } } } return dp[0][0][0]; }

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def solve(N: int, nums: list) -&gt; int: def max_product(arr): mx = mn = ans = arr[0] for x in arr[1:]: if x &lt; 0: mx, mn =
def solve(N: int, nums: list) -> int: def max_product(arr): mx = mn = ans = arr[0] for x in arr[1:]: if x < 0: mx, mn = mn, mx mx = max(x, mx * x) mn = min(x, mn * x) ans = max(ans, mx) return ans res = -10**18 i = 0 while i < N: j = i while j + 1 < N and abs(nums[j]) < abs(nums[j + 1]): j += 1 res = max(res, max_product(nums[i:j + 1])) i = j + 1 return res

def is_vowel(ch): return ch in 'AEIOU' def solve(): data = sys.stdin.read().strip() if not data: return 0 s = data.split()[0]
def is_vowel(ch): return ch in 'AEIOU' def solve(): data = sys.stdin.read().strip() if not data: return 0 s = data.split()[0] n = len(s) dp_vowel = [0] * (n + 1) dp_consonant = [0] * (n + 1) dp_consonant[0] = 1 for i in range(1, n + 1): if s[i-1] != '0': digit = int(s[i-1]) letter = chr(ord('A') + digit - 1) if is_vowel(letter): dp_vowel[i] = (dp_vowel[i] + dp_consonant[i-1]) % MOD else: dp_consonant[i] = (dp_consonant[i] + dp_consonant[i-1] + dp_vowel[i-1]) % MOD if i >= 2 and s[i-2] != '0': two_digit = int(s[i-2:i]) if 10 <= two_digit <= 26: letter = chr(ord('A') + two_digit - 1) if is_vowel(letter): dp_vowel[i] = (dp_vowel[i] + dp_consonant[i-2]) % MOD else: dp_consonant[i] = (dp_consonant[i] + dp_consonant[i-2] +dp_vowel[i-2]) % MOD

int solve(int N, int fee, vector&amp; prices) { int max_cash = 0; int bought_even_stock = -1e9; int bought_odd_stock = -1e9;
int solve(int N, int fee, vector& prices) { int max_cash = 0; int bought_even_stock = -1e9; int bought_odd_stock = -1e9; for (int idx = 0; idx < N; idx++) { int current_price = prices[idx]; int updated_cash = max_cash; int updated_even_stock = bought_even_stock; int updated_odd_stock = bought_odd_stock; if (current_price % 2 == 0) { updated_even_stock = max(bought_even_stock, max_cash - current_price); if (bought_odd_stock != -1e9) { updated_cash = max(updated_cash, bought_odd_stock + current_price - fee); } } else { updated_odd_stock = max(bought_odd_stock, max_cash - current_price); if (bought_even_stock != -1e9) { updated_cash = max(updated_cash, bought_even_stock + current_price - fee); } } max_cash = updated_cash; bought_even_stock = updated_odd_stock; } return max_cash; }

Car code int solve(int T, int capacity, vector>& trips) { map passenger_diffs; for (int idx = 0; idx < T; idx++) { int count = trips[idx][0]; int start_loc = trips[idx][1]; int end_loc = trips[idx][2]; passenger_diffs[start_loc] += count; passenger_diffs[end_loc] -= count; } long long accumulated_standing_cost = 0; long long active_riders = 0; int last_point = -1; for (auto& entry : passenger_diffs) { int curr_point = entry.first; if (last_point != -1 && curr_point > last_point) { long long dist = curr_point - last_point; if (active_riders > capacity) { accumulated_standing_cost += (active_riders - capacity) * dist; } } active_riders += entry.second; last_point = curr_point; } return accumulated_standing_cost; }