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Algebra Quint

Algebra Quint

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(4+7)²+4*7=149

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2x+2√(x-4)(x+7)=22 √(x-4)(x+7)=(11-x) (x²+3x-28)=121+x²-22x 25x=121+28=149✓

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By putting value... Put A= 45°.. p = 1+1/√2 q = 1–1/√2 Now... By option... √16pq = p² - q² 4*1/√2 = 4*1/√2 2√2 = 2√2 L=R🫠

cotA + cosA = p cotA - cosA = q (cotA + cosA) (cotA - cosA) = pq (cotA)² - (cosA)² = pq cot²A - cos²A = pq cos²A/sin²A - cos²A = pq cos²A (1/sin²A - 1) = pq cos²A (cosec²A - 1) = pq cos²A * cot²A = pq cot²A * cos²A = pq (cotA + cosA)² - (cotA - cosA)² = p² - q² √(16 cot²A cos²A) = p² - q² √16pq = p² - q²

P²-Q²=4cotcos PQ=cot²-cos² =Cos²(cosec²-1) =Cos²cot² √PQ=Coscot So √16PQ=P²-Q² C option

Soln
Soln

a⁵ = a + 4d = 108 a²⁸ = a + 27d = 250 (a + 27d)- (a+4d)= 250-108 d= 142/23 a= 1916/23 Sum= n/2[2a+(n-1)d] 16[3832/23+4402/23] 5728

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