ACCENTURE | COGNIZANT | IBM | CAPGEMINI

GOT JOINING DATE FOR THE IBM 🥳🥳🥳✅✅ Offer letter proofs : https://t.me/python_java_Coding/8472 100% clearance for any interview and exam ✅✅ Contact: @MLCODER2

One more GOT selected for capgemini 🥳🥳 ✅✅ 100% clearance for your interview and exam help ✅ Contact: @MLCODER2

Capgemini interview cleared & got LOI mail 🥳🥳🥳 100% clearance for any interview ✅ Contact: @MLCODER2

Dun&Bradstreet done & dusted✅✅✅ SQL + JAVA + BASH SCRIPT WITH DOCKER✅ Contact : @MLCODER2

CTS HELP AVAILABLE👇👇 COMMUNICATION✅ APTITUDE✅ TECHNICAL✅ INTERVEIW✅ Contact : @MLCODER2

company : TechMahindra batch : 2024 & 2025 https://docs.google.com/forms/d/e/1FAIpQLSe9mRwvpMY8M5-ve5yG-OkQJAbfI72uj0wL26N_LhTOXgoHnQ/viewform

Amazon ✅✅✅ Contact : @MLCODER2

IBM exam✅✅✅ Contact : @MLCODER2

Most Significant word✅✅ Contact : @MLCODER2

pattern Generation✅✅ Contact : @MLCODER2

kingdom✅✅ Contact : @MLCODER2

Amazon exam ✅✅✅ Contact : @MLCODER2

Amazon✅✅✅ contact : @mlcoder2

CTS 7PM ✅✅✅ Contact : @MLCODER2

CTS ✅✅ Contact : @MLCODER2

public class Main { public static int[] countGreaterAdjacent(int input1, int[] input2) { int N=input1; int[] A=input2; int[] result = new int[N]; for (int i = 0; i < N; i++) { int count = 0; if (i == 0) { if (A[1] > A[0]) count++; if (A[N - 1] > A[0]) count++; } else if (i == N - 1) { if (A[0] > A[N - 1]) count++; if (A[N - 2] > A[N - 1]) count++; } else { if (A[i - 1] > A[i]) count++; if (A[i + 1] > A[i]) count++; } result[i] = count; } return result; }

CTS 4PM ✅✅✅ Contact : @MLCODER2

Book your 4PM & 7PM CTS SLOTS 👇 https://esb-2dur.onrender.com/ Note: GOLDSMAN SACHS SLOTS ARE OPENED ✅ Contact : @MLCODER2

CTS 1PM✅✅✅ contact : @MLCODER2

CTS ✅✅ contact : @MLCODER2