es
Feedback

¡No caigas en manos de tramposos! Telemetrio encuentra y marca estos canales 👉 Si quieres ver la etiqueta, suscríbete

Coding Solutions Group

Coding Solutions Group

Ir al canal en Telegram

Mostrar más
IndiaLa categoría no está especificada
2 051
Suscriptores
Sin datos24 horas
Sin datos7 días
Sin datos30 días
Archivo de publicaciones
def Check_Vow(string, vowels): final = [each for each in string if each in vowels] print(len(final)) string=input() vowels = "AaEeIiOoUu" Check_Vow(string, vowels); Telegram - https://t.me/Coding_solution_0

Any company Non coding Genuine Assistance available lets help each other.

Hi Jahnavi , Welcome to this Community for 2022 Batch Daily Off Campus Jobs Updates join this channel ✅ 👇👇 @offcampusjobs_0 @offcampusjobs_0

Anyone

Any need assistance in COGNIZANT, Infosys, TCS, IBM, Virtusa, Accenture, Capgemini, Mindtree, Mountblue, Tech Mahendra, Deloitte,Atos, etc.

Yes

Hi Shantanu Welcome to this Community. Join Our Channel for daily Off-Campus Job Updates ❤️ 👇👇 @offcampusjobs_0 @offcampusjobs_0

/startsendingpython

Okay

Me too

/startsendingpython

Hi Alekya , Welcome to this Community for 2022 Batch Daily Off Campus Jobs Updates join this channel ✅ 👇👇 @offcampusjobs_0 @offcampusjobs_0

Galat hai ye

Photo from Vishnu

Photo from Rajesh

You will be given a string S. You have to find two different sub-sequences of S such that The two sub-sequences don't cross each other. In other words, all indices of the first sub-sequence are strictly less than all indices of the second sub- sequence. • The length of the first sub-sequence multiplied by the the length of the second subsequence is maximum possible. • Both sub-sequences are palindromes Given a string S, find the required two sub-sequences, and print the multiplication value of their lengths. Input Format The first line contains a string, S, denoting the described string Constraints 1 <= len(S) <= 3000

Please give the answer of following

Anyone want paid infytq solution then message me

Hi Bhargavi , Welcome to this Community for 2022 Batch Daily Off Campus Jobs Updates join this channel ✅ 👇👇 @offcampusjobs_0 @offcampusjobs_0