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Action: Warn (1/3) ❕Repost from Coding Solutions Group
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@placement_0
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Last yr there were 3 rounds dude... This time its just 2...they will be calling from just 1 round and they will just call from rank 1 to rank of there choice...
n=int(input())
t=[]
p=[]
r=1
for i in range(n):
t.append(int(input()))
for i in range(n):
p.append(int(input()))
f,s=0,0
for i in range(n):
s=0
f=0
for j in range(i+1):
if(f==1):
s+=p[j]*2
else:
s+=p[j]
if(t[j]==1):
f=1
r*=s
print(r)
