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Any body got 30 min IBM gaming round

Pai d codi ng he lp d m me. Pay after u get your co de #python only

Can anyone help?

/startsendingpython

Any one want help dm me

AWS Cloud, Linux, MySQL, GIT Training Batch 47 *Starts from* 15th sep 2021, 06:30PM IST ✅50 Day's Live Classes. ✅Full practical Oriented. ✅Doubt Classes. ✅What's Group for any question. 🔘 Mentor:- Vinay Sir ( 15 year of teaching Experience in AWS Cloud, MySQL, GIT, DSA, Algorithm ) * For Registration ping me at : https://wa.me/message/VOHSGXEQ66NKB1 Actual fees Rs. 5000 INR Discount 50% Rs. 2500 INR on Actual fees.(For this batch only) And if you Register today itself Price will be 1500 INR(After all discount) 🔰Websites: https://mtnptech.com

Ans plz

Option 2

Support My Friend Recover From road Accident* My name is Narasimha and I am here to raise funds for my friend Abhiram who is 21 years old. Abhiram lives in Tanuku, Andhra Pradesh with us. Abhiram met with accident and his body got injured a few days back . Doctor asked us 3,00000(3 Lakhs) to do an operation. His family is so poor,His father is dead he has only mother. She arranged 1 Lakh and we are trying to raise fund for 2 lakhs. Please help him survive Google pay: smoulinarasimha100@okicici Phone pay: moulisimha@ibl Please 🙏🙏🙏 help my friend for operation. 1rs doesn't matter to you but it will save his life donate as much as you can

Anyone wants help for accenture drive@7pm message me

B

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Ans

#include<bits/stdc++.h> using namespace std; #define ll long long #define MOD 998244353 #define add(x,y) ((x+y)%MOD) #define mul(x,y) ((x*y)%MOD) #define sub(x,y) ((MOD+x-y)%MOD) ll fastpow(ll x, ll y){ ll temp = 1; while(y){ if(y&1) temp = mul(temp, x); x = mul(x, x); y>>=1; } return temp; } ll inv(ll x){ return fastpow(x,MOD-2); } ll frac[200100]; ll C(ll n, ll i){ return mul(frac[n], inv(mul(frac[i], frac[n-i]))); } int main(){ ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); int n,k; cin>>n>>k; if(k>=n){ cout<<0<<endl; return 0; } ll ans = 0; frac[0] = 1; for(int i=1;i<=n;++i){ frac[i] = mul(i, frac[i-1]); } for(int i=0;i<=n-k;++i){ ll temp = mul(C(n-k,i), fastpow(n-k-i,n)); if(i&1) ans = sub(ans, temp); else ans = add(ans,temp); } ans = mul(ans, C(n, n-k)); if(k) ans = mul(ans, 2); cout<<ans<<endl; } CHESS GAME CODE Telegram - https://t.me/Coding_solution_0

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