IBM EXAM SOLUTION

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static int sum_of_differences(int arr[], int N) { // Stores the sum int sum = 0; int i, j, flag; // Traverse the array for(i = 0; i < N - 1; i++) { if (arr[i] < arr[i + 1]) { flag = 0; for(j = i + 1; j < N - 1; j++) { // increasing sub-array is found if (arr[j] >= arr[j + 1]) { sum += (arr[j] - arr[i]); i = j; flag = 1; break; } } if (flag == 0 && arr[i] < arr[N - 1]) { // Update sum sum += (arr[N - 1] - arr[i]); break; } } } return sum; } Family Piggy In C ++ ❤️❤️100% working https://t.me/offcampusjobs_0

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input1 = str(input1) n = len(input1) ans = 0 for i in range(0, n) : v = ans * 10 + (int)(input1[i]) ans = v % 11 return ans Remainder mod 11 Bob and Numbers n = int(input()) a = list(map(int,input().split())) c = 0 for i in range(n-1): for j in range(i+1:n): s1 = sum(list(map(int,bin(i)[2:].split()))) s2 = sum(list(map(int,bin(j)[2:].split()))) if s1 == s2: c += 1 print(c) Apple Orchard n = int(input()) l = list(map(int,input().split())) res = min(l)*n print(res) for(int i=0;i<n;i++) { a[i]=Integer.parseInt(k.nextLine()); } for(int i=0;i<n;i++) { b[i]=Integer.parseInt(k.nextLine()); }int sum=0; for(int i=0;i<n;i++) { for(int j=i+1;j<n-1;j++) { if(b[i]==b[j]) { int c=Math.max(a[i],a[j]); sum=sum+c; } else sum=sum+a[i]; } } return (sum); Harold and his homework Code Telegram -https://t.me/Coding_solution_0

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