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# Leap year program in Python using if else
year = int(input("Enter a year: "))
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
print(year, "is a leap year")
else:
print(year, "is not a leap year")
else:
print(year, "is a leap year")
else:
print(year, "is not a leap year")
Enter the starting number: 1
Enter the ending number: 100
Armstrong numbers between 1 and 100:
1
2
3
4
5
6
7
8
9
# Armstrong numbers between two intervals in Python using for loop
def is_armstrong_number(number):
num_str = str(number)
num_digits = len(num_str)
sum_of_digits = sum(int(digit) ** num_digits for digit in num_str)
if sum_of_digits == number:
return True
else:
return False
# Example usage
start = int(input("Enter the starting number: "))
end = int(input("Enter the ending number: "))
print(f"Armstrong numbers between {start} and {end}:")
for number in range(start, end + 1):
if is_armstrong_number(number):
print(number)
Output 👉
Armstrong numbers between 1 and 10,000:
1
2
3
45
6
7
8
9
153
370
371
407
1634
8208
9474
➡️Types -02
# Python program to print all Armstrong numbers between 1 and 10,000
def is_armstrong_number(number):
num_str = str(number)
num_digits = len(num_str)
sum_of_digits = sum(int(digit) ** num_digits for digit in num_str)
if sum_of_digits == number:
return True
else:
return False
print("Armstrong numbers between 1 and 10,000:")
for number in range(1, 10001):
if is_armstrong_number(number):
print(number)
👉Output
Enter the starting number: 100
Enter the ending number: 500
Armstrong numbers between 100 and 500:
153
370
371
407
THE EXAMS..!!:
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