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OSSSC / OSSC MATH AND REASONING

OSSSC / OSSC MATH AND REASONING

前往频道在 Telegram

𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

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📈 Telegram 频道 OSSSC / OSSC MATH AND REASONING 的分析概览

频道 OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 11 499 名订阅者,在 教育 类别中位列第 17 095,并在 印度 地区排名第 33 552

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 11 499 名订阅者。

根据 20 九月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 202,过去 24 小时变化为 8,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 13.83%。内容发布后 24 小时内通常能获得 5.66% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 590 次浏览,首日通常累积 651 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 1
  • 主题关注点: 内容集中在 ʜᴇʀᴇ, cgle, cgl, mcqs, mcq 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

凭借高频更新(最新数据采集于 21 九月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

11 499
订阅者
+824 小时
+57 天
+20230 天
帖子存档
For join direct contact - @bunnytapas ( NO HI HELLO )
For join direct contact - @bunnytapas ( NO HI HELLO )

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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤIf you randomly choose a day of the week, what is the probability that it is a weekend day (Saturday or Sunday)?
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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤIf the cost price of an article is Rs.30 and the selling price is Rs.40, what is the profit percentage ? (Approximate)
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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA real estate agent sells two sites for Rs.6,000 each. On one he gains 5% and on the other he loses 10%. What is his loss or gain percent ?
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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe ratio of 1.5 hours to 300 seconds is......
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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤSum of the age of Father and Son is 60 years. If the father now is 45 years, how old is the son ?
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𝐎𝐃𝐈𝐒𝐇𝐀 𝐕𝐈𝐑𝐓𝐔𝐀𝐋 𝐋𝐈𝐁𝐑𝐀𝐑𝐘 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe average of 15 numbers is 28. If each number is increased by 3, what will the new average be ?
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Find the number of multiples of 11025. 11025
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