OSSSC / OSSC MATH AND REASONING
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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH
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网络:📈 Telegram 频道 OSSSC / OSSC MATH AND REASONING 的分析概览
频道 OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 11 492 名订阅者，在 教育 类别中位列第 17 127，并在 印度 地区排名第 33 653 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 11 492 名订阅者。
根据 14 九月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 221，过去 24 小时变化为 -2，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 11.68%。内容发布后 24 小时内通常能获得 5.33% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 1 342 次浏览，首日通常累积 612 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 1。
- 主题关注点： 内容集中在 ʜᴇʀᴇ, cgle, cgl, mcqs, mcq 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS
Join our YouTube Channel: https://shorturl.at/Ulwjw
🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY
🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”
凭借高频更新（最新数据采集于 15 九月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
11 492
订阅者
-224 小时
+547 天
+22130 天
帖子存档
The H.C.F. and L.C.M. of two numbers are 84 and 21 respectively. If the ratio of the two numbers is1: 4, then the larger of the two numbers i
The sum of two numbers is 2000 and their L.C.M. is 21879. The two numbers are
. If H.C.F. of p and q is x and q = xy, then the L.C.M. of p and q is
The H.C.F. and L.C.M. of two numbers are 12 and 336 respectively. If one of the numbers is 84, the other is
The L.C.M. and ratio of four numbers are 630 and 2: 3: 5: 7 respectively. The difference between thegreatest and least numbers is
Three numbers are in the ratio of 3: 4: 5 and theirL.C.M. is 2400. Their H.C.F. is
The ratio of two numbers is 13: 15 and their L.C.M.is 39780. The numbers ar
Three numbers which are co-prime to each other are such that the product of the first two is 551 andthat of the last two is 1073. The sum of the three numbers is
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is
The number of number-pairs lying between 40 and 100 with their H.C.F. as 15 is
The sum of two numbers is 528 and their H.C.F. is 33. The number of pairs of numbers satisfying the above conditions is
📱 𝐄𝐯𝐞𝐫𝐲𝐓𝐡𝐢𝐧𝐠 𝐈𝐧 𝐎𝐕𝐋 📱
. 🤷♂️ 𝐖𝐡𝐲 𝐀𝐫𝐞 𝐘𝐨𝐮 𝐖𝐚𝐢𝐭𝐢𝐧𝐠 𝐅𝐨𝐫 !!
🎤𝐉𝐮𝐬𝐭 𝐂𝐥𝐢𝐜𝐤 𝐋𝐢𝐧𝐤𝐬 𝐀𝐧𝐝 𝐉𝐨𝐢𝐧.
➡️ 𝐌𝐚𝐢𝐧 𝐆𝐫𝐨𝐮𝐩 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐎𝐝𝐢𝐚 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️𝐄𝐧𝐠𝐥𝐢𝐬𝐡 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐃𝐚𝐢𝐥𝐲 𝐂𝐀 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐌𝐚𝐭𝐡 / 𝐑𝐞𝐚 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐆𝐊 / 𝐆𝐒 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐏𝐃𝐅 𝐒𝐭𝐨𝐫𝐞 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
⚠️ 𝒀𝒐𝒖 𝑴𝒖𝒔𝒕 𝑺𝒕𝒂𝒚 𝑰𝒏 𝑨𝒍𝒍 𝑮𝒓𝒐𝒖𝒑𝒔 ,
𝑶𝒕𝒉𝒆𝒓𝒘𝒊𝒔𝒆 𝑹𝒆𝒎𝒐𝒗𝒆𝒅 𝑩𝒚 𝑩𝒐𝒕𝒔.
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📱 𝐄𝐯𝐞𝐫𝐲𝐓𝐡𝐢𝐧𝐠 𝐈𝐧 𝐎𝐕𝐋 📱
. 🤷♂️ 𝐖𝐡𝐲 𝐀𝐫𝐞 𝐘𝐨𝐮 𝐖𝐚𝐢𝐭𝐢𝐧𝐠 𝐅𝐨𝐫 !!
🎤𝐉𝐮𝐬𝐭 𝐂𝐥𝐢𝐜𝐤 𝐋𝐢𝐧𝐤𝐬 𝐀𝐧𝐝 𝐉𝐨𝐢𝐧.
➡️ 𝐌𝐚𝐢𝐧 𝐆𝐫𝐨𝐮𝐩 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐎𝐝𝐢𝐚 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️𝐄𝐧𝐠𝐥𝐢𝐬𝐡 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐃𝐚𝐢𝐥𝐲 𝐂𝐀 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐌𝐚𝐭𝐡 / 𝐑𝐞𝐚 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐆𝐊 / 𝐆𝐒 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐏𝐃𝐅 𝐒𝐭𝐨𝐫𝐞 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
⚠️ 𝒀𝒐𝒖 𝑴𝒖𝒔𝒕 𝑺𝒕𝒂𝒚 𝑰𝒏 𝑨𝒍𝒍 𝑮𝒓𝒐𝒖𝒑𝒔 ,
𝑶𝒕𝒉𝒆𝒓𝒘𝒊𝒔𝒆 𝑹𝒆𝒎𝒐𝒗𝒆𝒅 𝑩𝒚 𝑩𝒐𝒕𝒔.
Let x be the least number which when divided by 15, 18, 20 and 27, the remainder in each case is 10 and x is a multiple of 31. What least number should be added to x to make it a perfect square?
When 12, 16, 18, 20 and 25 divide the least number x, the remainder in each case is 4 but x is divisible by 7. What is the digit at the thousands' place in x ?
What is the smallest integer that is divisible by 3, 7 and 18?
Find the least number which when divided by 12, 18, 24 and 30 leave 4 as remainder in each case, but when divided by 7 leave no remainder?
Find the smallest number such that when it is divided by 5, 6 and 8 it leaves a remainder 3 in each case.
