OSSSC / OSSC MATH AND REASONING
前往频道在 Telegram
𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH
显示更多📈 Telegram 频道 OSSSC / OSSC MATH AND REASONING 的分析概览
频道 OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 11 491 名订阅者,在 教育 类别中位列第 17 127,并在 印度 地区排名第 33 653 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 11 491 名订阅者。
根据 14 九月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 221,过去 24 小时变化为 -2,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 11.68%。内容发布后 24 小时内通常能获得 5.33% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 342 次浏览,首日通常累积 612 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 1。
- 主题关注点: 内容集中在 ʜᴇʀᴇ, cgle, cgl, mcqs, mcq 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS
Join our YouTube Channel: https://shorturl.at/Ulwjw
🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY
🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”
凭借高频更新(最新数据采集于 15 九月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
11 491
订阅者
-224 小时
+547 天
+22130 天
帖子存档
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Sonu saves 15% of her income.
If her income increases by
20% and she still saves the same amount as before, then what is the percentage increase in her expenditure? (correct to one decimal place)
If the difference between 62%
and 80% of a number is 198,
then the difference between 92% and 56% of the number will be:
The price of cooking oil
increased by 25%. Find by how
much percentage a family must reduce its consumption in order to maintain the same budget?
Ravi scores 72% marks in
examinations. If these are 360
marks, then the maximum marks are:
By what number must the
given number be multiplied to
increase the number by 25%.
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📱 𝐄𝐯𝐞𝐫𝐲𝐓𝐡𝐢𝐧𝐠 𝐈𝐧 𝐎𝐕𝐋 📱
. 🤷♂️ 𝐖𝐡𝐲 𝐀𝐫𝐞 𝐘𝐨𝐮 𝐖𝐚𝐢𝐭𝐢𝐧𝐠 𝐅𝐨𝐫 !!
🎤𝐉𝐮𝐬𝐭 𝐂𝐥𝐢𝐜𝐤 𝐋𝐢𝐧𝐤𝐬 𝐀𝐧𝐝 𝐉𝐨𝐢𝐧.
➡️ 𝐌𝐚𝐢𝐧 𝐆𝐫𝐨𝐮𝐩 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐎𝐝𝐢𝐚 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️𝐄𝐧𝐠𝐥𝐢𝐬𝐡 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
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➡️ 𝐆𝐊 / 𝐆𝐒 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ODISHA GK :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
➡️ 𝐏𝐃𝐅 𝐒𝐭𝐨𝐫𝐞 :- ᴄʟɪᴄᴋ ʜᴇʀᴇ
⚠️ 𝒀𝒐𝒖 𝑴𝒖𝒔𝒕 𝑺𝒕𝒂𝒚 𝑰𝒏 𝑨𝒍𝒍 𝑮𝒓𝒐𝒖𝒑𝒔 ,
𝑶𝒕𝒉𝒆𝒓𝒘𝒊𝒔𝒆 𝑹𝒆𝒎𝒐𝒗𝒆𝒅 𝑩𝒚 𝑩𝒐𝒕𝒔.
If radius of a circle is decreased
by 11%, then the total decrease
in the area of the circle is given as:
