Computer Map™

前往频道在 Telegram

Abhyas Point Powered By Computer Map टेलीग्राम चैनल में आपका स्वागत है यह सभी प्रतियोगी परीक्षाओं के लिए कंप्यूटर विषय के लिए एक निःशुल्क टेलीग्राम चैनल है #ACP #BPSCTRE #Anudeshak #UPLTGrade #Computer_Anudeshak_BCI #DSSSB_PGT_TGT, #EMRS_PGT_TGT

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印度28 061 教育13 501...

📈 Telegram 频道 Computer Map™ 的分析概览

频道 Computer Map™ (@computermap29) 印地语 语言赛道中的是活跃参与者。目前社区聚集了 14 919 名订阅者，在教育类别中位列第 13 501，并在印度地区排名第 28 061 位。

📊 受众指标与增长动态

自 невідомо 创建以来，项目保持高速增长，吸引了 14 919 名订阅者。

根据 04 七月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 72，过去 24 小时变化为 3，整体触达仍然可观。

认证状态： 未认证
互动率 (ER)： 平均受众互动率为 14.72%。内容发布后 24 小时内通常能获得 8.73% 的反应，占订阅者总量。
帖子覆盖： 每篇帖子平均可获得 2 197 次浏览，首日通常累积 1 302 次浏览。
互动与反馈： 受众积极参与，单帖平均反应数为 4。
主题关注点： 内容集中在 pyq, कम्प्यूटर, map, questions, टेस्ट 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台：
“Abhyas Point Powered By Computer Map टेलीग्राम चैनल में आपका स्वागत है यह सभी प्रतियोगी परीक्षाओं के लिए कंप्यूटर विषय के लिए एक निःशुल्क टेलीग्राम चैनल है #ACP #BPSCTRE #Anudeshak #UPLTGrade #Computer_Anudeshak_BCI #DSSSB_PGT_TGT, #EMRS_PGT_TGT”

凭借高频更新（最新数据采集于 05 七月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为教育类别中的关键影响点。

14 919

订阅者

+324 小时

+77 天

+7230 天

2 197

帖子浏览量

~ 1 30224 小时

~ 1 48648 小时

14.72%

参与率

~ 6

每日帖子数

Ads index

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帖子存档

14 915

🔰Dynamic routing protocol enable routers to: ISRO CS 2016

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🔰The following device is used to join different kinds of networks at data link layer: RPSC VPITI 2018 CS

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Telegram @ComputerMap29

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Telegram @ComputerMap29

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Telegram @ComputerMap29

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Telegram @ComputerMap29

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🔰The amount of data transmitted in a fixed amount of time is called MPPSC State Forest Service 2014

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🔰...............is a device that combines transmission from various I/O devices into one line MPPSC State Forest Service 2014

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🔰...............is a device that combines transmission from various I/O devices into one line MPPSC State Forest Service 2014

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🔰In a computer network, which of the following is a connecting device? MPPSC State Forest Service 2014

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🔰If a computer network cable is broken whole network goes down in...........topology MPPSC State Forest Service 2014

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Consider a source computer (S) transmitting a file of size 10 bits bits to a destination computer (D) over a network of two routers (R, and R₂) and three links (LL and L3). L connects S to R₁; L connect R, to R2; and La connects R₂ to D. Let each link be of length 100 km. Assume signals travel over each link at a speed of 10 meters per second. Assume that the link bandwidth on each link is 1 Mbps. Let the file be broken down into 1000 packets each of size 1000 bits. Find the total sum of transmission and propagation delays in transmitting the file from S to D? GATE CS 2012

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An IP machine Q has a path to another IP machine H via three IP routers R1, R2, and R3.

Q—R1—R2—R3—H

H acts as an HTTP server, and Q connects to H via HTTP and downloads a file. Session layer encryption is used, with DES as the shared key encryption protocol. Consider the following four pieces of information:

[I1] The URL of the file downloaded by Q [I2] The TCP port numbers at Q and H [I3] The IP addresses of Q and H [I4] The link layer addresses of Q and H

Which of I1, I2, I3, and I4 can an intruder learn through sniffing at R2 alone?

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🔰Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? GATE-CS-2015

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Suppose that everyone in a group of N people wants to communicate secretly with the N–1 others using symmetric key cryptographic system. The communication between any two persons should not be decodable by the others in the group. The number of keys required in the system as a whole to satisfy the confidentiality requirement is GATE-CS-2015