Excel and programming notes
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📈 Telegram 频道 Excel and programming notes 的分析概览
频道 Excel and programming notes (@programmingindia1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 34 608 名订阅者,在 教育 类别中位列第 5 460,并在 印度 地区排名第 11 684 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 34 608 名订阅者。
根据 25 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -440,过去 24 小时变化为 -15,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 10.26%。内容发布后 24 小时内通常能获得 N/A% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 0 次浏览,首日通常累积 0 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 0。
- 主题关注点: 内容集中在 analyst, excel, visualization, analytic, database 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 26 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
34 608
订阅者
-1524 小时
-907 天
-44030 天
帖子存档
# importing the tkinter module
from tkinter import *
# importing the pyperclip module to use it to copy our generated
# password to clipboard
import pyperclip
# random module will be used in generating the random password
import random
# initializing the tkinter
root = Tk()
# setting the width and height of the gui
root.geometry("400x400") # x is small case here
# declaring a variable of string type and this variable will be
# used to store the password generated
passstr = StringVar()
# declaring a variable of integer type which will be used to
# store the length of the password entered by the user
passlen = IntVar()
# setting the length of the password to zero initially
passlen.set(0)
# function to generate the password
def generate():
# storing the keys in a list which will be used to generate
# the password
pass1 = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't',
'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D',
'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N',
'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X',
'Y', 'Z', '1', '2', '3', '4', '5', '6', '7', '8',
'9', '0', ' ', '!', '@', '#', '$', '%', '^', '&',
'*', '(', ')']
# declaring the empty string
password = ""
# loop to generate the random password of the length entered
# by the user
for x in range(passlen.get()):
password = password + random.choice(pass1)
# setting the password to the entry widget
passstr.set(password)
# function to copy the password to the clipboard
def copytoclipboard():
random_password = passstr.get()
pyperclip.copy(random_password)
# Creating a text label widget
Label(root, text="Password Generator Application", font="calibri 20 bold").pack()
# Creating a text label widget
Label(root, text="Enter password length").pack(pady=3)
# Creating a entry widget to take password length entered by the
# user
Entry(root, textvariable=passlen).pack(pady=3)
# button to call the generate function
Button(root, text="Generate Password", command=generate).pack(pady=7)
# entry widget to show the generated password
Entry(root, textvariable=passstr).pack(pady=3)
# button to call the copytoclipboard function
Button(root, text="Copy to clipboard", command=copytoclipboard).pack()
# mainloop() is an infinite loop used to run the application when
# it's in ready state
root.mainloop()
import turtle
turtle.bgcolor('#ffc233')
turtle.title("Radhe Krishna")
screen= turtle.Screen()
screen.setup(650,580)
t1 = turtle.Turtle()
t1.speed(4)
t1.right(90)
t1.pu()
t1.forward(180)
t1.left(90)
t1.pd()
#Here we have dipped our turtle brush in a shade of blue color
t1.fillcolor("#ff99d1")
t1.begin_fill()
t1.forward(400)
t1.right(90)
t1.forward(100)
t1.right(90)
t1.forward(800)
t1.right(90)
t1.forward(100)
t1.right(90)
t1.forward(400)
t1.end_fill()
#Now, we have drawn the base which is rectangular in shape
#end_fill will fill blue color (selected above), in the shape formed by turtle
#Now, we will start to draw moon,I have selected a very light shade of blue to color moon
t1.fillcolor("#CDEEF1")
t1.begin_fill()
t1.forward(160)
t1.left(40)
#this method will draw the moon's border
t1.circle(250,280)
t1.left(40)
t1.forward(160)
t1.end_fill()
#Now, we have drawn the moon as well as filled color in it
#Now, we will start drawing Radha Krishna
#We will draw Radha on our right side and Krishna on left side
#We will start with Radha
t1.fillcolor("#012427")
t1.begin_fill()
#We will start with the duppata
t1.forward(160)
t1.left(130)
t1.circle(-300,30)
t1.forward(95)
#This will draw the shoulder
t1.circle(50,40)
t1.right(40)\
t1.forward(43)
t1.circle(80,25)
t1.circle(50,30)
t1.left(10)
t1.circle(35,28)
t1.right(160)
t1.circle(10,100)
t1.right(100)
t1.circle(10,80)
t1.forward(20)
t1.left(80)
t1.circle(100,15)
t1.right(90)
t1.forward(6)
t1.left(65)
t1.circle(60,55)
t1.right(160)
t1.circle(20,100)
t1.forward(10)
t1.circle(-20,25)
t1.left(170)
t1.circle(-20,40)
t1.forward(10)
t1.circle(20,80)
t1.right(135)
t1.circle(60,15)
t1.left(70)
t1.forward(6)
t1.right(110)
t1.forward(9)
t1.left(80)
t1.circle(70,24)
t1.right(60)
t1.circle(65,30)
t1.circle(-5,110)
t1.circle(5,120)
t1.right(90)
t1.circle(5,60)
t1.forward(10)
t1.circle(10,5)
t1.right(80)
t1.forward(15)
t1.circle(-5,160)
t1.forward(6)
t1.circle(2,180)
t1.forward(6)
t1.circle(20,30)
t1.right(140)
t1.circle(3,150)
t1.right(110)
t1.circle(4,80)
t1.forward(2)
t1.right(100)
t1.forward(6)
t1.right(60)
t1.forward(9)
t1.circle(2,180)
t1.forward(10)
t1.left(30)
t1.forward(15)
t1.right(85)
t1.forward(40)
t1.right(60)
t1.circle(5,310)
t1.right(80)
t1.forward(3)
t1.right(90)
t1.forward(42)
t1.right(30)
t1.forward(10)
t1.left(90)
t1.circle(20,60)
t1.left(95)
t1.forward(12)
t1.right(29)
t1.forward(42)
t1.right(90)
t1.forward(34)
t1.right(85)
t1.forward(2)
t1.circle(60,25)
t1.right(80)
t1.circle(10,40)
t1.forward(45)
t1.left(10)
t1.forward(130)
t1.left(90)
t1.forward(20)
t1.right(90)
t1.forward(10)
t1.left(90)
t1.forward(10)
t1.right(90)
t1.forward(5)
t1.left(90)
t1.forward(25)
t1.left(100)
t1.forward(120)
t1.right(175)
t1.circle(50,50)
t1.right(80)
t1.circle(110,15)
t1.forward(75)
#The turtle will now reach to the rectangular base we had drawn in the beginning
t1.left(97)
t1.forward(260)
t1.end_fill()
t1.pu()
t1.right(90)
t1.forward(100)
t1.right(90)
t1.forward(420)
t1.color("#00a606")
t1.write("Radhe Krishna....", font=("Script",45, "bold"))
t1.hideturtle()
turtle.done()
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
