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allcoding1

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📈 Telegram 频道 allcoding1 的分析概览

频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 21 531 名订阅者,在 教育 类别中位列第 9 159,并在 印度 地区排名第 19 101

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 21 531 名订阅者。

根据 01 九月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -367,过去 24 小时变化为 -14,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 7.16%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 543 次浏览,首日通常累积 270 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 02 九月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

21 531
订阅者
-1424 小时
-797 天
-36730 天
帖子存档
class Solution { public:      void bfs(vector<vector<int>>&vis,vector<vector<char>>&grid,int i,int j,int n,int m)     {         vis[i][j]=1;         queue<pair<int,int>>q;         q.push({i,j});         while(!q.empty())         {             int row=q.front().first;             int col=q.front().second;             q.pop();             int delrow[4]={1,0,-1,0};             int delcol[4]={0,1,0,-1};                    for(int k=0;k<=3;k++){                     int nrow=row+delrow[k];                     int ncol=col+delcol[k];                     if(nrow>=0 and nrow<n and ncol>=0 and ncol<m and grid[nrow][ncol]=='1' and !vis[nrow][ncol])                     {                         vis[nrow][ncol]=1;                         q.push({nrow,ncol});                     }                 }             }         }     int numIslands(vector<vector<char>>& grid) {     int n=grid.size();         int m=grid[0].size();         vector<vector<int>>vis(n,vector<int>(m,0));         int cnt=0;         for(int i=0;i<n;i++)         {             for(int j=0;j<m;j++)             {                 if(!vis[i][j] and grid[i][j]=='1')                 {                     cnt++;                     bfs(vis,grid,i,j,n,m);                 }             }         }         return cnt;     } }; Zeta ✅ Telegram:- @allcoding1

class Solution { public:      void bfs(vector<vector<int>>&vis,vector<vector<char>>&grid,int i,int j,int n,int m)     {         vis[i][j]=1;         queue<pair<int,int>>q;         q.push({i,j});         while(!q.empty())         {             int row=q.front().first;             int col=q.front().second;             q.pop();             int delrow[4]={1,0,-1,0};             int delcol[4]={0,1,0,-1};                    for(int k=0;k<=3;k++){                     int nrow=row+delrow[k];                     int ncol=col+delcol[k];                     if(nrow>=0 and nrow<n and ncol>=0 and ncol<m and grid[nrow][ncol]=='1' and !vis[nrow][ncol])                     {                         vis[nrow][ncol]=1;                         q.push({nrow,ncol});                     }                 }             }         }     int numIslands(vector<vector<char>>& grid) {     int n=grid.size();         int m=grid[0].size();         vector<vector<int>>vis(n,vector<int>(m,0));         int cnt=0;         for(int i=0;i<n;i++)         {             for(int j=0;j<m;j++)             {                 if(!vis[i][j] and grid[i][j]=='1')                 {                     cnt++;                     bfs(vis,grid,i,j,n,m);                 }             }         }         return cnt;     } }; Zeta ✅ Telegram:- @allcoding1

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SELECT category, title, total_stock FROM ( SELECT p.category, p.title, SUM(w.quantity) AS total_stock FROM products p JOIN wa
SELECT   category,   title,   total_stock FROM (   SELECT     p.category,     p.title,     SUM(w.quantity) AS total_stock   FROM     products p   JOIN     warehouse w ON p.product_id = w.product_id   GROUP BY     p.category, p.title   HAVING     total_stock > 10 ) AS filtered_data ORDER BY   category ASC, title ASC, total_stock DESC; IBM✅ Telegram:- @allcoding1

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+1
IBM✅ SQL Telegram:- @allcoding1

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return min(e-b+1, numChapters) Python 3✅ IBM Telegram:- @allcoding1
+1
return min(e-b+1, numChapters) Python 3✅ IBM Telegram:- @allcoding1

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+1
#scammer Please report 👇 @offical1allcoding , Vds , @Allcodingoffical The changing names Guys ♥️ be careful don't pay money

Guys ♥️ @allcoding, @Allcodingoffical1, @offical1allcoding @Allcodingoffical, @codingoffical and @Allcodingofficalmain it's n
Guys ♥️ @allcoding, @Allcodingoffical1, @offical1allcoding @Allcodingoffical, @codingoffical and @Allcodingofficalmain it's not me don't lose your money #scammer Please report Please share with your friends and telegram Group's

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int solve(vector&gt; arr) { &nbsp;&nbsp;&nbsp; int n = arr.size(); &nbsp;&nbsp;&nbsp; vector&gt; dp(n, vector(n)); &nbsp;&nbs
int solve(vector<vector<int>> arr) {     int n = arr.size();     vector<vector<int>> dp(n, vector<int>(n));     int maxi = 0;     for(int i = 0; i < n; i++) {         for(int j = 0; j < n; j++) {             if(i == 0 || j == 0) {                 dp[i][j] = arr[i][j];             } else if(arr[i][j] == 1) {                 dp[i][j] = min({dp[i-1][j], dp[i][j-1], dp[i-1][j-1]}) + 1;             }             maxi = max(maxi, dp[i][j]);         }     }     return maxi; } IBM C++ Telegram:- @allcoding1

allcoding1 - Telegram 频道 @allcoding1 的统计与分析