allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 21 578 名订阅者,在 教育 类别中位列第 9 062,并在 印度 地区排名第 19 025 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 21 578 名订阅者。
根据 29 八月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -360,过去 24 小时变化为 -8,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 5.78%。内容发布后 24 小时内通常能获得 1.10% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 247 次浏览,首日通常累积 238 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 0。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 30 八月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
21 578
订阅者
-824 小时
-787 天
-36030 天
帖子存档
21 564
+8
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Telegram:- @allcoding1
Juspay
=int(input())
dic={}
def addnode(u,v):
dic[u].append(v)
for i in range(N):
n1=int(input())
dic[n1]=[]
edge=int(input())
for i in range(edge):
u,v=map(int,input().split())
addnode(u,v)
start=int(input())
end=int(input())
tr=[]
tr.append(start)
def traverse(dic,start):
for i in dic[start]:
if(i==end):
return
if(len(dic[start])==0):
return
else:
tr.append(i)
traverse(dic,i)
traverse(dic,start)
tr=sorted(tr)
for i in tr:
print(i,end=" ")
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import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int[] left = new int[n];
int[] right = new int[n];
for (int i = 0; i < n; i++) {
left[i] = scanner.nextInt();
right[i] = scanner.nextInt();
}
int sumLeft = 0;
int sumRight = 0;
for (int i = 0; i < n; i++) {
sumLeft += left[i];
sumRight += right[i];
}
if (sumLeft % 2 == 0 && sumRight % 2 == 0) {
System.out.println(0);
return;
}
boolean possible = false;
for (int i = 0; i < n; i++) {
int newSumLeft = sumLeft - left[i] + right[i];
int newSumRight = sumRight - right[i] + left[i];
if (newSumLeft % 2 == 0 && newSumRight % 2 == 0) {
possible = true;
break;
}
}
if (possible) {
System.out.println(1);
} else {
System.out.println(-1);
}
}
}
21 564
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AP election results
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🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
