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allcoding1

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📈 Telegram 频道 allcoding1 的分析概览

频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 601 名订阅者,在 教育 类别中位列第 8 831,并在 印度 地区排名第 19 534

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 22 601 名订阅者。

根据 10 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -430,过去 24 小时变化为 -7,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 5.78%。内容发布后 24 小时内通常能获得 1.40% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 307 次浏览,首日通常累积 317 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 11 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

22 601
订阅者
-724 小时
-907
-43030
帖子存档
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import java.util.Scanner; public class RotateNumberArray {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);         // Input the number         System.out.println("Enter the number:");         String input = scanner.next();         int n = input.length();         // Convert the number into an array of digits         int[] arr = new int[n];         for (int i = 0; i < n; i++) {             arr[i] = Character.getNumericValue(input.charAt(i));         }         // Input the number of rotations         System.out.println("Enter the number of rotations:");         int rotations = scanner.nextInt();         // Perform the rotation         int[] rotatedArray = rotateArray(arr, rotations);         // Print the rotated array as a number         System.out.println("Rotated Number:");         for (int digit : rotatedArray) {             System.out.print(digit);         }         scanner.close();     }     public static int[] rotateArray(int[] arr, int rotations) {         int n = arr.length;         // Normalize the rotations         rotations = rotations % n;         // Create a new array to hold the rotated result         int[] result = new int[n];         // Copy the last 'rotations' elements to the beginning         for (int i = 0; i < rotations; i++) {             result[i] = arr[n - rotations + i];         }         // Copy the remaining elements         for (int i = rotations; i < n; i++) {             result[i] = arr[i - rotations];         }         return result;     } } Sample input 123456 2 Sample Output 561234 Java 19/1/25 Wipro exam

import java.util.Scanner; public class MidIndexProblem { public static void main(String[] args) { Scanner scanner = new Scann
import java.util.Scanner; public class MidIndexProblem { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); // Read the number of elements System.out.println("Enter the number of elements:"); int n = scanner.nextInt(); // Read the array elements int[] arr = new int[n]; System.out.println("Enter the elements:"); for (int i = 0; i < n; i++) { arr[i] = scanner.nextInt(); } // Find the mid-index int midIndex = n / 2; // Output the middle element System.out.println("Middle element: " + arr[midIndex]); scanner.close(); } } wipro 19/1/25 2. ans , mid-index problem Java @itjobsservices

import java.util.Scanner; public class NegativeSum { public static void main(String[] args) { int[] numbers = {2, -3, -14, 7}
import java.util.Scanner; public class NegativeSum { public static void main(String[] args) { int[] numbers = {2, -3, -14, 7}; int negativeSum = findNegativeSum(numbers); } public static int findNegativeSum(int[] arr) { int sum = 0; for (int num : arr) { if (num < 0) { sum += num; } } return sum; } } Wipro exam ans 19/1/2025 Java @itjobsservices

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