allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 543 名订阅者,在 教育 类别中位列第 8 854,并在 印度 地区排名第 19 507 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 22 543 名订阅者。
根据 14 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -445,过去 24 小时变化为 -14,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 6.31%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 423 次浏览,首日通常累积 282 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 2。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 16 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
22 543
订阅者
-1424 小时
-947 天
-44530 天
帖子存档
22 543
from itertools import permutations
def unique_permutations(nums):
unique_perms = set(permutations(nums))
return [list(perm) for perm in unique_perms]
# Take input for nums
nums_input = input("Enter a list of numbers separated by spaces: ")
nums = [int(num) for num in nums_input.split()]
# Get and print unique permutations
output = unique_permutations(nums)
print(output)
22 543
Saks subarray product✅
long long solve(vector& nums, int k) {
if (k <= 1) return 0;
int n = nums.size();
long long p = 1;
int i = 0, j = 0;
long long ans = 0;
while (j < n) {
p *= nums[j];
while (i <= j && p > k) {
p /= nums[i];
i++;
}
ans += j - i + 1;
j++;
}
return ans;
}
22 543
#include <iostream>
#include <vector>
#include <unordered_map>
class Main {
public:
static long getZeroBitSubarrays(const std::vector<int>& arr) {
int n = arr.size();
long totalSubarrayCount = static_cast<long>(n) * (n + 1) / 2;
long nonzeroSubarrayCount = 0;
std::unordered_map<int, int> windowBitCounts;
int leftIdx = 0;
for (int rightIdx = 0; rightIdx < n; rightIdx++) {
int rightElement = arr[rightIdx];
if (rightElement == 0) {
windowBitCounts.clear();
leftIdx = rightIdx + 1;
continue;
}
std::vector<int> setBitIndices = getSetBitIndices(rightElement);
for (int index : setBitIndices) {
windowBitCounts[index]++;
}
while (leftIdx < rightIdx && isBitwiseAndZero(rightIdx - leftIdx + 1, windowBitCounts)) {
for (int index : getSetBitIndices(arr[leftIdx])) {
windowBitCounts[index]--;
if (windowBitCounts[index] == 0) {
windowBitCounts.erase(index);
}
}
leftIdx++;
}
nonzeroSubarrayCount += (rightIdx - leftIdx + 1);
}
return totalSubarrayCount - nonzeroSubarrayCount;
}
private:
static std::vector<int> getSetBitIndices(int x) {
std::vector<int> setBits;
int pow2 = 1;
int exponent = 0;
while (pow2 <= x) {
if ((pow2 & x) != 0) {
setBits.push_back(exponent);
}
exponent++;
pow2 *= 2;
}
return setBits;
}
static bool isBitwiseAndZero(int windowLength, const std::unordered_map<int, int>& bitCounts) {
for (const auto& entry : bitCounts) {
if (entry.second >= windowLength) {
return false;
}
}
return true;
}
};
DE Shaw ✅
C++
Telegram:- @allcoding1
22 543
🎯TCS National Qualifier Test (TCS NQT) 2024
Location: Across India
Qualification: B.E / B.Tech / M.E / M.Tech / M.Sc / MCA / Any Graduate / Under Graduate / Diploma
Batch: 2018/2019/2020/2021/2022/2023/2024
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1
22 543
package Graph;
import java.util.*;
public class Largest_Sum_Cycle
{
public static int solution(int arr[])
{
ArrayList<Integer>sum=new ArrayList<>();
for(int i=0;i<arr.length;i++)
{
ArrayList<Integer>path=new ArrayList<>();
int j=i;
int t=0;
while(arr[j]<arr.length&&arr[j]!=i&&arr[j]!=-1&&!path.contains(j))
{
path.add(j);
t+=j;
j=arr[j];
if(arr[j]==i)
{
t+=j;
break;
}
}
if(j<arr.length&&i==arr[j])
sum.add(t);
}
if(sum.isEmpty())
return -1;
return Collections.max(sum);
}
public static void main(String[] args)
{
// TODO Auto-generated method stub
Scanner sc=new Scanner(System.in);
int testcases=sc.nextInt();
for(int loop=0;loop<testcases;loop++)
{
int numofBlocks=sc.nextInt();
int arr[]=new int[numofBlocks];
int src,dest;
for(int i=0;i<numofBlocks;i++)
{
arr[i]=sc.nextInt();
}
System.out.println(solution(arr));
}
}
}
Juspay ✅
Telegram:- @allcoding1
22 543
import java.util.Scanner;
import java.util.*;
public class metting
{
public static void helperFunction()
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int[] edges = new int[n];
for (int i = 0; i < n; i++)
{
edges[i] = sc.nextInt();
}
int C1 = sc.nextInt();
int C2 = sc.nextInt();
// int ans=minimumWeight(n,edges,C1,C2);
// System.out.println(ans);
// public static int minimumWeight(int n, int[] edges, int C1, int C2) {
List<List<Integer>> list = new ArrayList<>();
for (int i = 0; i < n; i++) {
list.add(new ArrayList<Integer>());
}
for (int i = 0; i < n; i++) {
if (edges[i] != -1) {
list.get(i).add(edges[i]);
}
}
long[] array1 = new long[n];
long[] array2 = new long[n];
Arrays.fill(array1, Long.MAX_VALUE);
Arrays.fill(array2, Long.MAX_VALUE);
juspay(C1, list, array1);
juspay(C2, list, array2);
int node = 0;
long dist = Long.MAX_VALUE;
for (int i = 0; i < n; i++) {
if (array1[i] == Long.MAX_VALUE || array2[i] == Long.MAX_VALUE)
continue;
if (dist > array1[i] + array2[i]) {
dist = array1[i] + array2[i];
node = i;
}
}
if (dist == Long.MAX_VALUE)
System.out.print(-1);
//return -1;
// return node;
System.out.print(node);
}
private static void juspay(int start, List<List<Integer>> graph, long[] distances)
{
PriorityQueue<Integer> pq = new PriorityQueue<>();
pq.offer(start);
distances[start] = 0;
while (!pq.isEmpty())
{
int curr = pq.poll();
for (int neighbor : graph.get(curr))
{
long distance = distances[curr] + 1;
if (distance < distances[neighbor])
{
distances[neighbor] = distance;
pq.offer(neighbor);
}
}
}
}
public static void main(String[] args) {
metting m = new metting();
metting.helperFunction();
}
}
Nearest meeting Cell
Juspay ✅
Telegram:- @allcoding1
22 543
🎯TCS National Qualifier Test (TCS NQT) 2024
Location: Across India
Qualification: B.E / B.Tech / M.E / M.Tech / M.Sc / MCA / Any Graduate / Under Graduate / Diploma
Batch: 2018/2019/2020/2021/2022/2023/2024
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1
22 543
string make_string_S_to_T(string S) {
string T=“programming”;
bool possible = false;
int M = T.length();
int N = S.length();
for (int i = 0; i <= M; i++) {
int prefix_length = i;
int suffix_length = M - i;
string prefix = S.substr(0, prefix_length);
string suffix = S.substr(N - suffix_length, suffix_length);
if (prefix + suffix == T) {
possible = true;
break;
}
}
if (possible)
return "YES";
else
return "NO";
}
Deleting substring ✅
Zeta
Telegram:- @allcoding1
22 543
#include <bits/stdc++.h>
using namespace std;
vector<int> solution(vector<int> a, int n, int k) {
vector<int> v;
deque<int> dq;
for (int i = 0; i < n; i++) {
while (!dq.empty() && dq.front() <= i - k)
dq.pop_front();
while (!dq.empty() && a[dq.back()] <= a[i])
dq.pop_back();
dq.push_back(i);
if (i >= k - 1)
v.push_back(a[dq.front()]);
}
return v;
}
int main() {
int n, k;
cin >> n >> k;
vector<int> a(n);
for (int i = 0; i < n; i++)
cin >> a[i];
vector<int> result = solution(a, n, k);
for (int i = 0; i < result.size(); i++)
cout << result[i] << " ";
return 0;
}.
//cricket match ✅
Zeta
Telegram:- @allcoding1
22 543
class Solution {
public:
void bfs(vector<vector<int>>&vis,vector<vector<char>>&grid,int i,int j,int n,int m)
{
vis[i][j]=1;
queue<pair<int,int>>q;
q.push({i,j});
while(!q.empty())
{
int row=q.front().first;
int col=q.front().second;
q.pop();
int delrow[4]={1,0,-1,0};
int delcol[4]={0,1,0,-1};
for(int k=0;k<=3;k++){
int nrow=row+delrow[k];
int ncol=col+delcol[k];
if(nrow>=0 and nrow<n and ncol>=0 and ncol<m and grid[nrow][ncol]=='1' and !vis[nrow][ncol])
{
vis[nrow][ncol]=1;
q.push({nrow,ncol});
}
}
}
}
int numIslands(vector<vector<char>>& grid) {
int n=grid.size();
int m=grid[0].size();
vector<vector<int>>vis(n,vector<int>(m,0));
int cnt=0;
for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
{
if(!vis[i][j] and grid[i][j]=='1')
{
cnt++;
bfs(vis,grid,i,j,n,m);
}
}
}
return cnt;
}
};
Zeta ✅
Telegram:- @allcoding1
22 543
class Solution {
public:
void bfs(vector<vector<int>>&vis,vector<vector<char>>&grid,int i,int j,int n,int m)
{
vis[i][j]=1;
queue<pair<int,int>>q;
q.push({i,j});
while(!q.empty())
{
int row=q.front().first;
int col=q.front().second;
q.pop();
int delrow[4]={1,0,-1,0};
int delcol[4]={0,1,0,-1};
for(int k=0;k<=3;k++){
int nrow=row+delrow[k];
int ncol=col+delcol[k];
if(nrow>=0 and nrow<n and ncol>=0 and ncol<m and grid[nrow][ncol]=='1' and !vis[nrow][ncol])
{
vis[nrow][ncol]=1;
q.push({nrow,ncol});
}
}
}
}
int numIslands(vector<vector<char>>& grid) {
int n=grid.size();
int m=grid[0].size();
vector<vector<int>>vis(n,vector<int>(m,0));
int cnt=0;
for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
{
if(!vis[i][j] and grid[i][j]=='1')
{
cnt++;
bfs(vis,grid,i,j,n,m);
}
}
}
return cnt;
}
};
Zeta ✅
Telegram:- @allcoding1
22 543
KPMG Off Campus Drive Hiring 2024 | Front End Developer | 4 LPA+
Job Title : Front End Developer
Qualification : B.E / B.Tech
Batch : Any Batch
Package : 4 LPA+
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1
22 543
SELECT
category,
title,
total_stock
FROM (
SELECT
p.category,
p.title,
SUM(w.quantity) AS total_stock
FROM
products p
JOIN
warehouse w ON p.product_id = w.product_id
GROUP BY
p.category, p.title
HAVING
total_stock > 10
) AS filtered_data
ORDER BY
category ASC, title ASC, total_stock DESC;
IBM✅
Telegram:- @allcoding1
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
