allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 535 名订阅者,在 教育 类别中位列第 8 857,并在 印度 地区排名第 19 476 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 22 535 名订阅者。
根据 15 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -434,过去 24 小时变化为 -13,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 6.43%。内容发布后 24 小时内通常能获得 1.32% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 450 次浏览,首日通常累积 297 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 2。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 16 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
22 535
订阅者
-1324 小时
-887 天
-43430 天
帖子存档
22 535
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@Allcodingsolution
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22 535
string getLongestRegex(string a, string b, string c)
{
const size_t n = a.size();
int idx = -1;
for (int i = 0; i < n; i++) {
if (c[i] != a[i] && c[i] != b[i]) { idx = i; }
}
if (idx == -1) return "-1";
string res;
for (int i = 0; i < n; i++) {
if (i == idx) {
string cur = "[";
for (int j = 'A'; j <= 'Z'; j++) if (j != c[i]) cur += j;
cur += "]";
res += cur;
} else {
res += "[ABCDEFGHIJKLMNOPQRSTUVWXYZ]";
}
}
return res;
}
C++
Amazon
22 535
def minimumCost(price):
n = len(price)
price.append(0)
ans = float('inf')
last = {price[0]: 0}
for i in range(1, n):
v = price[i]
price[i] += price[i - 1]
if last.get(v) != None:
ans = min(ans, price[i] - price[last[v]] + v)
last[v] = i
return ans if ans != float('inf') else -1
n = int(input())
price = list(map(int,input().split(' ')))
print(minimumCost(price))
Python 3
Amazon
22 535
#include <bits/stdc++.h>
using namespace std;
bool checkbit(int n,int i){
return n&(1<<i);
}
bool cmp(const pair<int,int> &a,const pair<int,int>&b){
return a.second<b.second;
}
int main() {
int n;cin>>n;
int a[n];
for(int i=0;i<n;i++) cin>>a[i];
vector<pair<int,int>> v;
for(int i=0;i<n;i++){
int c=0;
for(int j=0;j<31;j++){
if(checkbit(a[i],j)) c++;
}
v.push_back({a[i],c});
}
int idx = 0;
sort(v.begin(),v.end(),cmp);
for(auto it : v){
a[idx++] = it.first;
cout<<it.second<<" ";
}
for(int i=0;i<n;i++){
cout<<a[i]<<" ";
}
return 0;
}
C++
Telegram:- @allcoding1
22 535
def cardinalitySort(nums):
return sorted(nums, key=lambda num: [bin(num).count('1'), num])
Cardinality sorting
22 535
def gameWinner(colors):
currPlayer = "wendy"
prevPlayer = ""
winner = ""
while True:
moveMade = False
if currPlayer == "wendy":
whiteIndex = colors.find("www")
if whiteIndex = -1:
# 3 consecutive whites found, remove the middle one
colorsBuilder = list(colors)
colorsBuilder.pop(whiteIndex + 1)
colors = "".join(colorsBuilder)
moveMade = True
prevPlayer = currPlayer
currPlayer = "bob"
else:
blackIndex = colors.find("bbb")
if blackIndex != -1:
# 3 consecutive blacks found, remove the middle one
colorsBuilder = list(colors)
colorsBuilder.pop(blackIndex + 1)
colors = "".join(colorsBuilder)
moveMade = True
prevPlayer = currPlayer
currPlayer = "wendy"
# if no moves possible break
if not moveMade:
winner = prevPlayer
break
return winner
print(gameWinner("wwwbb"))
Python 3
Game Winner
JP Morgan
22 535
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Job Role:- Associate Analyst
Qualification:- Any Graduate
Batch:- Any Batch
Salary/CTC:- Rs 3.5-4.5 LPA
Apply Now;- http://www.allcoding1.com
Video:- https://youtube.com/shorts/tWPfvbhtPgI?feature=share
Telegram:- @allcoding1
22 535
🎯HCL Off Campus Hiring for Freshers as Engineer Trainee | 3-5LPA
Job Role:- Engineer Trainee
Education:- Any Degree
Batch:- Any Batch
CTC/Salary:- 3-5 LPA
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1
Video👇
🅾️Instagram:- https://instagram.com/allcoding1_official?utm_source=qr&igshid=NGExMmI2YTkyZg%3D%3D
⛔YouTube :- https://youtube.com/shorts/TMaL15W0p3g?feature=share
22 535
Repost from allcoding1
import requests
import json
def getCaptialCity(country):
api_request = requests.get(''//@allcoding1 name='+country)
data = api_request.json()['data']
if(len(data[0]['capital'])==0)
return -1
return data[0]['capital']
country = input()
print(getCapitalCity(country))
Python
IBM exam Ans
Telegram:- @allcoding1
22 535
import requests
import json
def getCaptialCity(country):
api_request = requests.get(''//@allcoding1 name='+country)
data = api_request.json()['data']
if(len(data[0]['capital'])==0)
return -1
return data[0]['capital']
country = input()
print(getCapitalCity(country))
Python
Telegram:- @allcoding1_official
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