现已上线！2025 年 Telegram 研究 — 年度关键洞察 
allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 543 名订阅者，在 教育 类别中位列第 8 854，并在 印度 地区排名第 19 507 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 22 543 名订阅者。
根据 14 六月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -445，过去 24 小时变化为 -14，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 6.31%。内容发布后 24 小时内通常能获得 1.25% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 1 423 次浏览，首日通常累积 282 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新（最新数据采集于 16 六月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
22 543
订阅者
-1424 小时
-947 天
-44530 天
帖子存档
22 543
🎯Thryve Digital Off Campus Drive Hiring Any Graduate Freshers
Job Role Trainee – Process Analyst
Qualification Any degree
Experience Freshers
Job Location Chennai
CTC 3-5 LPA
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1
22 543
Repost from allcoding1
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
₹300
Contact:- @meterials_available
22 543
Guys❤
👉 I am doing promotions (real Or fake) I don't know
👉I'm not forcing you. Your decision
👉I am not a responsible to you
👉 I need money that why I'm doing promotions try understand
22 543
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
₹300
Contact:- @meterials_available
22 543
🎯Philips is Hiring
Role: Intern
Batch: 2024, 2025
Apply Now:-
https://philips.wd3.myworkdayjobs.com/jobs-and-careers/job/Bangalore/Intern_504512/
Telegram:- @allcoding1
22 543
🎯ICICI Bank Recruitment 2024 For Phone Banking Officer
Location: Chennai / Hyderabad / Thane / Guwahati / Indore
Qualification: Any Graduate
Work Experience : 0 – 6 Years
Apply Now:-
https://www.icicicareers.com/website/Jobs/Hot-Jobs/2031018.html?utm_source=jobscoupe.com
Telegram:- @allcoding1
22 543
🎯HSBC Recruitment 2024 For Data Analyst
Location: Bangalore
Qualification: Bachelor’s / Master’s Degree
Work Experience: Freshers / Experience
Apply now:-
https://mycareer.hsbc.com/en_GB/external/PipelineDetail/Analyst-Data-Governance-GSC-S/216031?source=jobscoupe.com
Telegram:- @allcoding1
22 543
🎯Tech Mahindra off Campus Hiring As Associate Software Engineer | Rs.3.25 LPA & 5.5LPA
Designation : Associate Software Engineer
Eligibility : Engineering / MCA
Salary CTC : Rs.3.25 LPA & 5.5LPA (for super coders)
Apply Now:-
https://registration.techmahindra.com/Candidate/RegDefault.aspx
Telegram:- @allcoding1
22 543
Company Name: Zoho
Role: Software Developer
Batch eligible: 2022, 2023 and 2024 passouts
Apply: https://careers.zohocorp.com/forms/fcc89b5ebd373d598e0224d10f2199d1a8839a1914d1ba3a141e0b0ddcfcfc32
Telegram:- @allcoding1
22 543
🎯Harmonic Off Campus Drive 2024 for Associate Software Engineer | 4 LPA
Job Role : Associate Software Engineer
Qualification : B.E/B.Tech
Batch : 2023
Salary : 4 LPA*
Apply now
https://jobs.jobvite.com/harmonic/job/okzUqfwX?nl=1&fr=true
Telegram:- @allcoding1
22 543
💻IT company's
👉Previous exams question papers and answers
👉Not books
👉courses and certificates
💰300
Contact:- @meterials_available
22 543
Meesho extended there exam date
And calling students to virtual interview based on there exam dates
Company name : MEESHO Role: BUSINESS ANALYST
Apply Now:- https://docs.google.com/forms/d/e/1FAIpQLSc3DvqJDjZeYjFZX2OgVPwm5shjCX4a0APzYBaTBoPzTf4khg/viewform?pli=1
While applying make sure in your CV mention python and sql.
Telegram:- @allcoding1
22 543
def PowerLimit(a, b):
current_resource, max_seconds = 1, 0
while a > 0 and b > 0:
if a > b:
current_resource, a, b = 1, a - 2, b + 1
else:
current_resource, b, a = 2, b - 2, a + 1
max_seconds += 1
max_seconds += a // 2 if current_resource == 1 else b // 2
return max_seconds
power limit ✅
Telegram:- @allcoding1
22 543
long long OneBlock(int N, vector<int> Arr) {
vector<int> one_indices;
for (int i = 0; i < N; ++i) {
if (Arr[i] == 1) {
one_indices.push_back(i);
}
}
if (one_indices.size() <= 1) {
return 1;
}
long long ways = 1;
for (int i = 1; i < one_indices.size(); ++i) {
int zeros_between_ones = one_indices[i] - one_indices[i - 1] - 1;
ways *= (zeros_between_ones + 1);
}
return ways;
}
//one block
C++
Telegram:- @allcoding1_official
22 543
+1https://youtube.com/@TechHelp-kn9fb?si=ZrRasvSTTjfAn-o8
Report this channel 👆👆👆
#Scammer
9929302889
Be safe
