ACCENTURE EXAM SOLUTIONS

前往频道在 Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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印度28 067 教育14 102...

📈 Telegram 频道 ACCENTURE EXAM SOLUTIONS 的分析概览

频道 ACCENTURE EXAM SOLUTIONS (@coding_are) 英语语言赛道中的是活跃参与者。目前社区聚集了 14 118 名订阅者，在教育类别中位列第 14 102，并在印度地区排名第 28 067 位。

📊 受众指标与增长动态

自 невідомо 创建以来，项目保持高速增长，吸引了 14 118 名订阅者。

根据 28 九月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -105，过去 24 小时变化为 -4，整体触达仍然可观。

认证状态： 未认证
互动率 (ER)： 平均受众互动率为 3.68%。内容发布后 24 小时内通常能获得 1.57% 的反应，占订阅者总量。
帖子覆盖： 每篇帖子平均可获得 520 次浏览，首日通常累积 222 次浏览。
互动与反馈： 受众积极参与，单帖平均反应数为 2。
主题关注点： 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台：
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

凭借高频更新（最新数据采集于 29 九月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为教育类别中的关键影响点。

14 125

订阅者

-424 小时

-127 天

-10530 天

520

帖子浏览量

~ 22224 小时

~ 29448 小时

3.68%

参与率

~ 4

每日帖子数

Ads index

beta

帖子存档

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public int maxPeakSum(int input1, int[] input2) { int maxSum = 0; for (int i = 1; i < input1 - 1; i++) { if (input2[i] > input2[i - 1] && input2[i] > input2[i + 1]) { int sum = input2[i]; int left = i - 1; int right = i + 1; while (left > 0 && input2[left] > input2[left - 1]) { sum += input2[left]; left--; } sum += input2[left]; while (right < input1 - 1 && input2[right] > input2[right + 1]) { sum += input2[right]; right++; } sum += input2[right]; maxSum = Math.max(maxSum, sum); } } return maxSum;

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public int asciiMod(String input1) { int modSum = 0; for (char ch = 'a'; ch <= 'z'; ch++) { int count = 0; for (int i = 0; i < input1.length(); i++) { if (input1.charAt(i) == ch) { count++; } } if (count > 0) { int asciiValue = (int) ch; int total = asciiValue * count; int modValue = total % 5; if (modValue != 0) { modSum += modValue; } } } return modSum; }

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Python 3 2nd code

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Sql

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Code passed

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