ACCENTURE EXAM SOLUTIONS
前往频道在 Telegram
🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
显示更多📈 Telegram 频道 ACCENTURE EXAM SOLUTIONS 的分析概览
频道 ACCENTURE EXAM SOLUTIONS (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 954 名订阅者，在 教育 类别中位列第 14 642，并在 印度 地区排名第 28 153 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 13 954 名订阅者。
根据 03 十一月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -151，过去 24 小时变化为 -6，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 3.70%。内容发布后 24 小时内通常能获得 1.38% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 516 次浏览，首日通常累积 193 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
凭借高频更新（最新数据采集于 04 十一月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
13 954
订阅者
-624 小时
-377 天
-15130 天
帖子存档
13 954
def variantsCount(n, s0, k, b, m, a):
if n <=0:
return 0
sum_array = [s0]
for i in range(1,n):
s_i = ((k * sum_array[i - 1] + b) % m) + 1 + sum_array[i - 1]
sum_array.append(s_i)
# two pointer to calculate the count
left = 0
right = len(sum_array) -1
count = 0
while left <= right:
area = sum_array[left] * sum_array[right]
if area <= a:
count += 2*(right - left) + 1
left +=1
elif area > a:
right -=1
return count
Paint the ceiling code
Python3
13 954
#include <bits/stdc++.h>
using namespace std;
vector<int> batonPass(int n, long t){
vector<int> ans;
int oddEven = 1,count=0;
while(true){
if(oddEven & 1){
if(count==0){
for(int i=0 ; i<n ; i++){
count++;
if(t == count){
if(i!=n-1){
// cout << i+1 << " " << i+2;
ans.push_back(i+1);
ans.push_back(i+2);
return ans;
}else{
ans.push_back(i+1);
ans.push_back(i);
return ans;
}
}
}
}else{
for(int i=1 ; i<n ; i++){
count++;
if(t == count){
if(i!=n-1){
ans.push_back(i+1);
ans.push_back(i+2);
return ans;
}else{
ans.push_back(i+1);
ans.push_back(i);
return ans;
}
}
}
}
oddEven++;
}else{
for(int i = n-2 ; i>=0 ; i--){
count++;
if(t == count){
if(i!=0){
ans.push_back(i+1);
ans.push_back(i);
return ans;
}else{
ans.push_back(i);
ans.push_back(i+1);
return ans;
}
}
}
oddEven++;
}
}
}
int main()
{
int friends,timee;
cin >> friends >> timee;
vector<int> ans = batonPass(friends,timee);
for(auto it : ans) cout << it << " ";
return 0;
}
Pass the baton code 👆👆
C++14
13 954
vector<int> batonPass(int friends, long time) {
vector<int> f;
int k = 1;
bool r = false;
long i = 1;
while (i <= time) {
if (!r) {
if (k <= friends)
k++;
else {
r = true;
}
} else {
if (k >= 2) {
k--;
} else {
r = false;
}
}
i++;
}
if (r) {
f.push_back(k);
f.push_back(k - 1);
} else {
f.push_back(k - 1);
f.push_back(k);
}
return f;
}
Pass the baton code- c++14
13 954
#include <bits/stdc++.h>
using namespace std;
vector<int> batonPass(int n, long t){
vector<int> ans;
int oddEven = 1,count=0;
while(true){
if(oddEven & 1){
if(count==0){
for(int i=0 ; i<n ; i++){
count++;
if(t == count){
if(i!=n-1){
// cout << i+1 << " " << i+2;
ans.push_back(i+1);
ans.push_back(i+2);
return ans;
}else{
ans.push_back(i+1);
ans.push_back(i);
return ans;
}
}
}
}else{
for(int i=1 ; i<n ; i++){
count++;
if(t == count){
if(i!=n-1){
ans.push_back(i+1);
ans.push_back(i+2);
return ans;
}else{
ans.push_back(i+1);
ans.push_back(i);
return ans;
}
}
}
}
oddEven++;
}else{
for(int i = n-2 ; i>=0 ; i--){
count++;
if(t == count){
if(i!=0){
ans.push_back(i+1);
ans.push_back(i);
return ans;
}else{
ans.push_back(i);
ans.push_back(i+1);
return ans;
}
}
}
oddEven++;
}
}
}
int main()
{
int friends,timee;
cin >> friends >> timee;
vector<int> ans = batonPass(friends,timee);
for(auto it : ans) cout << it << " ";
return 0;
}
1st code -c++
13 954
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13 954
Atlassian free code help 🔥🔥
Join here guys
Join this group guys for free code
Atlassian code free 🤘 free
h:https://t.me/rituyr
https://t.me/rituyr
https://t.me/rituyr
share ✅share✅ share ✅
13 954
def FindRemainingBalls(direction, strength):
asteroids = []
for i in range(0, len(direction)):
if direction[i] < 0:
asteroids.append(strength[i]*-1)
else:
asteroids.append(strength[i])
stack = []
collided = False
for asteroid in asteroids:
while stack and asteroid < 0 < stack[-1]:
defending_asteroid = stack.pop()
if defending_asteroid != abs(asteroid):
asteroid = asteroid if abs(asteroid) > defending_asteroid else defending_asteroid
else:
asteroid = 0
if asteroid != 0:
stack.append(asteroid)
return stack
Ball collision-python
13 954
Atlassian free code help 🔥🔥
Join here guys
Join this group guys for free code
Atlassian code free 🤘 free
h:https://t.me/rituyr
https://t.me/rituyr
https://t.me/rituyr
share ✅share✅ share ✅
13 954
int mex(vectorarr,int K)
{
int n=arr.size();
unordered_map mp;
for (int i = 0; i < n; i++) {
mp[arr[i] % K]++;
}
for (int i = 0; i < n; i++) {
if (mp.find(i % K) == mp.end()) {
return i;
}
mp[i % K]--;
if (mp[i % K] == 0)
mp.erase(i % K);
}
return n;
}
Mex problem guys ✅✅
Note -type as it is it will work
C++
13 954
def FindRemainingBalls(direction, strength):
asteroids = []
for i in range(0, len(direction)):
if direction[i] < 0:
asteroids.append(strength[i]*-1)
else:
asteroids.append(strength[i])
stack = []
collided = False
for asteroid in asteroids:
while stack and asteroid < 0 < stack[-1]:
defending_asteroid = stack.pop()
if defending_asteroid != abs(asteroid):
asteroid = asteroid if abs(asteroid) > defending_asteroid else defending_asteroid
else:
asteroid = 0
if asteroid != 0:
stack.append(asteroid)
return stack
Ball collision -Python
