ACCENTURE EXAM SOLUTIONS
前往频道在 Telegram
🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
显示更多📈 Telegram 频道 ACCENTURE EXAM SOLUTIONS 的分析概览
频道 ACCENTURE EXAM SOLUTIONS (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 14 039 名订阅者，在 教育 类别中位列第 14 513，并在 印度 地区排名第 28 403 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 14 039 名订阅者。
根据 14 十月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -133，过去 24 小时变化为 -6，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 3.61%。内容发布后 24 小时内通常能获得 1.82% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 507 次浏览，首日通常累积 256 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
凭借高频更新（最新数据采集于 15 十月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
14 039
订阅者
-624 小时
-347 天
-13330 天
帖子存档
14 039
def max_points(chocolates,initial):
chocolates=sorted(chocolates)
points=1
l=[1]
i=0
while i < len(chocolates):
if chocolates[i]<=initial:
initial=initial-chocolates[i]
points+=1
i+=1
else:
points-=1
initial+=chocolates[-1]
chocolates.pop()
l.append(points)
return max(l)
# Example usage:
chocolates_list = list(map(int, input().split())) # Input list of chocolates
initial_chocolates = int(input()) # Initial chocolates Bittu has
result = max_points(chocolates_list, initial_chocolates)
print(result,end="")
Choclate Code
TCS CODEVITA
PYTHON3
Share fasttt @codeing_area
14 039
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int max_efficiency(vector<int>& numbers) {
sort(numbers.begin(), numbers.end());
int n = numbers.size();
int max_efficiency = 0;
for (int i = 0; i < n; ++i) {
int efficiency = 0;
for (int j = i; j < n; ++j) {
efficiency += numbers[j] * (j - i + 1);
}
max_efficiency = max(max_efficiency, efficiency);
}
return max_efficiency;
}
int main() {
// Input parsing
int n;
cin >> n;
vector<int> numbers(n);
for (int i = 0; i < n; ++i) {
cin >> numbers[i];
}
// Output
int result = max_efficiency(numbers);
cout << (result >= 0 ? result : 0) << endl;
return 0;
}
. sports codee in C+++
Fully passsd ✅✅✅✅✅
Now make it 5k
14 039
Share Channel
When 5000 Done
I will post
Fencing problem
Maximum gem
Sports day
telegram @codeing_area
14 039
def toggle(num):
result = ""
for bit in num:
if bit == "0":
result += "1"
else:
result += "0"
return result
def get_max_sum(arr, k):
max_val = max(arr)
max_index = arr.index(max_val)
left = max(0, max_index-k)
right = min(len(arr)-1, max_index+k)
selected = arr[left:max_index+1] + arr[max_index:right+1]
arr = [x for x in arr if x not in selected]
return sum(selected), arr
# Input
arr = list(map(int, input().split()))
a1, b1 = input().split()
a2, b2 = input().split()
k = int(input())
sum1, sum2 = 0, 0
while arr:
s1, arr = get_max_sum(arr, k)
sum1 += s1
if not arr:
break
s2, arr = get_max_sum(arr, k)
sum2 += s2
if sum1 > sum2:
a1 = toggle(a1)
b2 = toggle(b2)
else:
a2 = toggle(a2)
b1 = toggle(b1)
xor1 = int(a1, 2) ^ int(b1, 2)
xor2 = int(a2, 2) ^ int(b2, 2)
if xor1 > xor2:
print("Rahul",end="")
elif xor2 > xor1:
print("Rupesh",end="")
else:
print("both",end="")
WHO IS LUCKY CODE
TCS CODEVITA
PYTHON3
14 039
def mirror_reflection(digits, side):
images = {
'0': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image1.png',
'1': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image2.png',
'2': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image3.png',
'3': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image4.png',
'4': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image5.png',
'5': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image6.png',
'6': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image7.png',
'7': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image8.png',
'8': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image9.png',
'9': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image0.png',
}
result = []
for d, s in zip(digits, side):
if s == 'L':
result.append(images[d])
else:
# For U, D, R, and S, print the seven segment display
result.append(d)
return ''.join(result)
# Input parsing
digits = input().strip()
side = input().strip()
# Output
print(mirror_reflection(digits, side))
Mirror reflection code .... python✅✅✅✅
Full passes ✅✅✅
14 039
No one sharing group everyone
Please share group ✅✅✅✅✅
I will send all code ✅✅✅
14 039
import numpy as np
def find_widest_valley(n, A, B):
def surface_equation(x):
return sum(np.sin(a*x + b) for a, b in zip(A, B))
def find_local_maxima():
maxima = []
for i in range(1, n-1):
if surface_equation(i-1) < surface_equation(i) > surface_equation(i+1):
maxima.append(i)
return maxima
def find_valley_width(left, right):
return right - left
maxima = find_local_maxima()
widest_valley_width = 0
widest_valley_index = 0
for i in range(len(maxima)-1):
left_maxima = maxima[i]
right_maxima = maxima[i+1]
current_valley_width = find_valley_width(left_maxima, right_maxima)
if current_valley_width > widest_valley_width:
widest_valley_width = current_valley_width
widest_valley_index = left_maxima + 1
return widest_valley_index
# Input parsing
n = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
# Output
print(find_widest_valley(n, A, B))
14 039
def convert(expression):
stack = []
tokens = expression.split()
for token in reversed(tokens):
if is_operand(token):
stack.append(int(token))
elif is_operator(token):
if len(stack) < 2:
return float('-inf')
operand2 = stack.pop()
operand1 = stack.pop()
if token == "+":
stack.append(operand1 + operand2)
elif token == "-":
stack.append(operand1 - operand2)
elif token == "*":
stack.append(operand1 * operand2)
elif token == "/":
stack.append(operand1 / operand2)
elif token == "^":
stack.append(operand1 ** operand2)
elif token == "%":
stack.append(operand1 % operand2)
if len(stack) != 1:
return float('-inf')
return stack.pop()
def is_operand(token):
return token.lstrip('-').isdigit()
def is_operator(token):
return token in {"+", "-", "*", "/", "^", "%"}
def main():
prefix = input()
word_map = {
"zero": "0", "one": "1", "two": "2", "three": "3", "four": "4",
"five": "5", "six": "6", "seven": "7", "eight": "8", "nine": "9",
"mul": "*", "add": "+", "sub": "-", "div": "/", "rem": "%", "pow": "^"
}
words = prefix.split()
real_prefix = ""
for word in words:
if word in word_map:
real_prefix += word_map[word] + " "
continue
small_words = word.split("c")
for s in small_words:
if s:
if s not in word_map:
print("expression evaluation stopped invalid words present")
return
real_prefix += word_map[s]
real_prefix += " "
infix = convert(real_prefix)
if infix == float('-inf'):
print("expression is not complete or invalid")
else:
print(int(infix))
if name == "main":
main()
No more suffle✅✅✅✅✅(python
All passsd ✅✅✅
Share everyone ✅✅✅
14 039
Please make it 5k fasttt everyone ✅✅✅
Then i will post all code....and fully correct ✅✅✅✅
14 039
#include <iostream>
#include <vector>
using namespace std;
int main() {
int n;
cin >> n;
vector<tuple<int, int, int>> stocks;
for (int i = 0; i < n; ++i) {
int a, b, c;
cin >> a >> b >> c;
stocks.push_back(make_tuple(a, b, c));
}
int m;
cin >> m;
int real = 0;
int unreal = 0;
vector<vector<int>> prices;
for (int i = 0; i < n; ++i) {
vector<int> arr(m);
for (int j = 0; j < m; ++j) {
cin >> arr[j];
}
prices.push_back(arr);
}
int day;
cin >> day;
for (int i = 0; i < n; ++i) {
int a, b, c;
tie(a, b, c) = stocks[i];
if (b > day) {
continue;
} else if (c > day || !c) {
unreal += a * (prices[i][day - 1] - prices[i][b - 1]);
} else {
real += a * (prices[i][c - 1] - prices[i][b - 1]);
}
}
cout << real << endl;
cout << unreal << endl;
return 0;
}
Roi code fully passsd ✅✅✅✅✅
Share @codeing_area
