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不要被骗子欺骗!Telemetrio 会找到并标记这些频道 👉 如果想查看标记,请订阅

ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

前往频道在 Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram 频道 ACCENTURE EXAM SOLUTIONS 的分析概览

频道 ACCENTURE EXAM SOLUTIONS (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 961 名订阅者,在 教育 类别中位列第 14 633,并在 印度 地区排名第 28 223 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 13 961 名订阅者。

根据 31 十月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -145,过去 24 小时变化为 -9,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 3.54%。内容发布后 24 小时内通常能获得 1.43% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 494 次浏览,首日通常累积 200 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2。
  • 主题关注点: 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

凭借高频更新(最新数据采集于 01 十一月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

13 961
订阅者
-924 小时
-417 天
-14530 天
帖子存档
Share screenshots to larger groups guys!! I'll share remaining answers 🙂 Those who share screenshots give😍

No one share group

If one person share 10 times we will reach 2k subscribers

Tcs first code

photo content

#include using namespace std; int find(int n1, int n2) {     int count = 0;     for (int i = n1
#include<bits/stdc++.h> using namespace std; int find(int n1, int n2) {     int count = 0;     for (int i = n1 ; i <= n2 ; i++) {         int num = i;         vector<bool> visited;         visited.assign(10, false);         while (num > 0) {             if (visited[num % 10] == true)                 break;             visited[num % 10] = true;             num /= 10;         }         if (num == 0)             count++;     }     return count; } int main() {     int n1 = 101, n2 = 200;     cout << find(n1, n2); } 1st code in c++ Passed all test cases ✅✅

C++ Raju (TCS 1st Qsn)
C++ Raju (TCS 1st Qsn)

I will send code answer

If one person share 10 times we will reach 2k subscribers

I will upload code bro

Done with Advanced Reasoning guys 😍 Show some ♥️♥️♥️

Advanced Reasoning answers 1. No 2. 2200 3. 172 4. Together not sufficient 5. Rishab votes 6. R 7. 63 8. 4th to right of Virat 9. None follows 10. AHJ:EJN

Advanced Reasoning answers 1. No 2. 2200 3. 172 4. Together not sufficient 5. Rishab votes 6. R 7. 63 8. 4th to right of Virat 9. None follows

Advanced Reasoning answers 1. No 2. 2200 3. 172 4. Together not sufficient 5. Rishab votes 6. R 7. 63 8. 4th to right of Virat

Share guys!!🤩🤩

Share screenshots to larger groups guys!! I'll share remaining answers 🙂 Those who share screenshots give😍

7) 55

6-R

A
A

Guys!! No one is sharing 😑 Share screenshots to larger groups to get remaining answers 😎 Share! Share!! Share!!!