现已上线！2025 年 Telegram 研究 — 年度关键洞察 
ACCENTURE EXAM HELP ! CISCO EXAM !
前往频道在 Telegram
🔥Guys plz Stop fearing for daily exams 📝 👨💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk
显示更多📈 Telegram 频道 ACCENTURE EXAM HELP ! CISCO EXAM ! 的分析概览
频道 ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 200 名订阅者，在 教育 类别中位列第 15 244，并在 印度 地区排名第 31 462 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 13 200 名订阅者。
根据 29 六月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -155，过去 24 小时变化为 -4，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 3.03%。内容发布后 24 小时内通常能获得 1.29% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 400 次浏览，首日通常累积 170 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“🔥Guys plz Stop fearing for daily exams 📝
👨💻 @srksvk is here to help you all at lowest cost possible.💪
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company
🔥Effort from our side = 💯
📱Main Channel: @coding_are
📱Tel I'd : @srks...”
凭借高频更新（最新数据采集于 30 六月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
13 200
订阅者
-424 小时
-177 天
-15530 天
帖子存档
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#include<bits/stdc++.h>
using namespace std;
int longestPalinSub(string st) {
int N = st.length();
vector<int> hash1(256, 0);
for(int i = 0; i < N; i++) {
hash1[st[i]]++;
}
string res1 = "", res2 = "";
for(int i = 0; i < 256; i++) {
for(int j = 0; j < hash1[i] / 2; j++) {
res1 += char(i);
}
for(int j = (hash1[i] + 1) / 2; j < hash1[i]; j++) {
res2 += char(i);
}
}
reverse(res2.begin(), res2.end());
bool f = false;
for(int i = 0; i < 256; i++) {
if(hash1[i] % 2) {
if(!f) {
res1 += char(i);
f = true;
}
}
}
return (res1.size() + res2.size());
}
A longest palindromic subsequence ✅
Google Step
#include<bits/stdc++.h>
using namespace std;
int longestPalinSub(string st) {
int N = st.length();
vector<int> hash1(256, 0);
for(int i = 0; i < N; i++) {
hash1[st[i]]++;
}
string res1 = "", res2 = "";
for(int i = 0; i < 256; i++) {
for(int j = 0; j < hash1[i] / 2; j++) {
res1 += char(i);
}
for(int j = (hash1[i] + 1) / 2; j < hash1[i]; j++) {
res2 += char(i);
}
}
reverse(res2.begin(), res2.end());
bool f = false;
for(int i = 0; i < 256; i++) {
if(hash1[i] % 2) {
if(!f) {
res1 += char(i);
f = true;
}
}
}
return (res1.size() + res2.size());
}
A longest palindromic subsequence ✅
Google Step
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Slot 13
#include<bits/stdc++.h>
using namespace std;
vector<string> solve(vector<string> s) {
map<int, string> mp;
for(string st : s) {
int o = st[0] - '0';
string p = st.substr(1);
mp[o] = p;
}
int n = mp.begin()->second.size();
vector<string> p(n, "");
for(auto it : mp) {
for(int i = 0; i < n; i++) {
p[i] += it.second[i];
}
}
return p;
}
void retrievePasscodes(vector<string> strips) {
vector<string> passcodes = solve(strips);
for(string passcode : passcodes) {
cout << passcode << endl;
}
}
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