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Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

前往频道在 Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram 频道 Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer 的分析概览

频道 Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 273 名订阅者,在 教育 类别中位列第 15 343,并在 印度 地区排名第 32 337

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 13 273 名订阅者。

根据 13 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 114,过去 24 小时变化为 -6,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 2.87%。内容发布后 24 小时内通常能获得 1.19% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 381 次浏览,首日通常累积 158 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 1
  • 主题关注点: 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

凭借高频更新(最新数据采集于 14 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

13 273
订阅者
-624 小时
-347
+11430
帖子存档
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import sys def solve(N, K, A): n = N limit = 1 << n valid = [False] * limit for mask in range(limit): s = 0 for i in range(n): if (mask >> i) & 1: s += A[i] if s <= K: valid[mask] = True dp = [n+1] * limit dp[0] = 0 full = limit - 1 for mask in range(1, limit): sub = mask while sub: if valid[sub]: other = mask ^ sub if dp[other] + 1 < dp[mask]: dp[mask] = dp[other] + 1 sub = (sub - 1) & mask return dp[full] * K def main(): data = sys.stdin.read().split() it = iter(data) N = int(next(it)); K = int(next(it)) A = [int(next(it)) for _ in range(N)] print(solve(N, K, A)) if name == "main": main()

include using namespace std; int N, M; vector> A; map, bool> dp; vector> dirs = {{1, 0}, {0, 1}}; bool dfs(int ax, int ay, int bx, int by, bool turn) { auto key = make_tuple(ax, ay, bx, by, turn); if (dp.count(key)) return dp[key]; if (turn) { for (auto [dx, dy] : dirs) { int nx = ax + dx, ny = ay + dy; if (nx < N && ny < M && A[nx][ny] >= A[bx][by]) { if (dfs(nx, ny, bx, by, !turn)) return dp[key] = true; } } return dp[key] = false; } else { for (auto [dx, dy] : dirs) { int nx = bx + dx, ny = by + dy; if (nx < N && ny < M && A[nx][ny] >= A[ax][ay]) { if (!dfs(ax, ay, nx, ny, !turn)) return dp[key] = false; } } return dp[key] = true; } } int solve(int n, int m, int q, vector> grid, vector> queries) { N = n; M = m; A = grid; int res = 0; for (int i = 0; i < q; ++i) { dp.clear(); int x1 = queries[i][0] - 1; int y1 = queries[i][1] - 1; int x2 = queries[i][2] - 1; int y2 = queries[i][3] - 1; if (dfs(x1, y1, x2, y2, true)) res |= (1 << i); } return res; }

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