ch
Feedback
Cognizant exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Cognizant exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

前往频道在 Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

显示更多

📈 Telegram 频道 Cognizant exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer 的分析概览

频道 Cognizant exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 290 名订阅者,在 教育 类别中位列第 15 336,并在 印度 地区排名第 32 419

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 13 290 名订阅者。

根据 10 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 108,过去 24 小时变化为 -7,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 3.12%。内容发布后 24 小时内通常能获得 1.23% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 415 次浏览,首日通常累积 163 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 1
  • 主题关注点: 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

凭借高频更新(最新数据采集于 11 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

13 290
订阅者
-724 小时
-377
+10830
帖子存档
import sys input = sys.stdin.readline def solve(N: int, C1: int, C2: int, C3: int, penalties: list) -> int: INF = 10**30 dp = [INF] * (N + 1) dp[0] = 0 for i in range(1, N + 1): dp[i] = min(dp[i], dp[i - 1] + C1 + penalties[i - 1]) if i >= 2: dp[i] = min(dp[i], dp[i - 2] + C2 + penalties[i - 2]) if i >= 3: dp[i] = min(dp[i], dp[i - 3] + C3 + penalties[i - 3]) return dp[N]

import java.util.*;

class Main {

public static int solve(int n,int k,int[] v,int[] w){

long sumA=0,sumB=0;
ArrayList<Integer> list=new ArrayList<>();

for(int i=0;i<n;i++){
if(v[i]==1)sumA+=w[i];
else sumB+=w[i];
list.add(w[i]);
}

if(sumA>sumB)return 0;

Collections.sort(list,Collections.reverseOrder());

int ops=0;

for(int x:list){
if(ops==k)break;
sumA+=x;
sumB-=x;
ops++;
if(sumA>sumB)return ops;
}

return -1;
}

public static void main(String[] args){
Scanner sc=new Scanner(System.in);

int n=sc.nextInt();
int k=sc.nextInt();

int[] v=new int[n];
for(int i=0;i<n;i++)v[i]=sc.nextInt();

int[] w=new int[n];
for(int i=0;i<n;i++)w[i]=sc.nextInt();

System.out.println(solve(n,k,v,w));
}
}

long long solve(int n,int low,int high,vector<int>& arr){ long long res=0,cur=0,MOD=1000000007; for(int i=0;i<n;i++){ if(arr[i]>=low && arr[i]<=high){ cur++; }else{ res=(res + (cur*(cur+1))/2)%MOD; cur=0; } } res=(res + (cur*(cur+1))/2)%MOD; return res; }

import sys NEG_INF = -10**18 def solve(N: int, B: int, a: list) -> int: pos = NEG_INF neg = NEG_INF for x in a: if x > 0: pos = max(pos, x, neg + x + B) else: neg = max(neg, x, pos + x + B) return max(0, pos, neg) if name == "main": data = list(map(int, sys.stdin.read().split())) N = data[0] B = data[1] a = data[2:2+N] print(solve(N, B, a))

https://t.me/coding_are Share this group with your friends and college group.. I will upload next answer in 5min

All passed ✅ import sys from collections import Counter def solve(N: int, C: int, A: list, W: list) -> int: mp = {} comp = [] for x in A: if x not in mp: mp[x] = len(mp) comp.append(mp[x]) A = comp freq = Counter(A) ans = max(W) B = 700 max_light = 1 for f in freq.values(): if f <= B and f > max_light: max_light = f max_len = min(N, 2 * max_light - 1) cnt = [0] * (len(mp) + 1) for l in range(N): total = 0 mx = 0 touched = [] end = min(N, l + max_len) for r in range(l, end): x = A[r] total += W[r] if cnt[x] == 0: touched.append(x) cnt[x] += 1 if cnt[x] > mx: mx = cnt[x] if mx * 2 > r - l + 1 and total > ans: ans = total for x in touched: cnt[x] = 0 heavy = [x for x, f in freq.items() if f > B] size = 2 * N + 5 off = N + 2 INF = 10**30 for cat in heavy: bit = [INF] * (size + 2) def update(i, val): while i <= size: if val < bit[i]: bit[i] = val i += i & -i def query(i): res = INF while i > 0: if bit[i] < res: res = bit[i] i -= i & -i return res bal = 0 pref = 0 update(off, 0) for i in range(N): pref += W[i] if A[i] == cat: bal += 1 else: bal -= 1 best = query(bal + off - 1) if best != INF: val = pref - best if val > ans: ans = val update(bal + off, pref) return ans if name == "main": data = list(map(int, sys.stdin.read().split())) idx = 0 N = data[idx]; idx += 1 C = data[idx]; idx += 1 A = data[idx:idx + N]; idx += N W = data[idx:idx + N] print(solve(N, C, A, W)) All passed ✅

import sys from collections import deque input = sys.stdin.readline def solve(N: int, F: int, MAX: int, s: list) -> int: limit = min(N, F + 1) dp = [-10**30] * limit dp[0] = s[0] dq = deque([0]) ans = dp[0] for i in range(1, limit): while dq and dq[0] < i - MAX: dq.popleft() dp[i] = s[i] + dp[dq[0]] ans = max(ans, dp[i]) while dq and dp[dq[-1]] <= dp[i]: dq.pop() dq.append(i) return ans if name == "main": data = list(map(int, sys.stdin.read().split())) idx = 0 N = data[idx]; idx += 1 F = data[idx]; idx += 1 MAX = data[idx]; idx += 1 s = data[idx:idx + N] print(solve(N, F, MAX, s))

https://t.me/coding_are Share this group with your friends and college group.. I will upload next answer in 5min

import sys sys.setrecursionlimit(2000) input = sys.stdin.read def solve(N: int, S: str, w: list) -> int: if N == 0: return 0 dp = [[0] * N for _ in range(N)] for i in range(N): dp[i][i] = w[i] for length in range(2, N + 1): for i in range(N - length + 1): j = i + length - 1 if S[i] == S[j]: if length == 2: dp[i][j] = w[i] + w[j] else: dp[i][j] = dp[i+1][j-1] + w[i] + w[j] else: dp[i][j] = max(dp[i+1][j], dp[i][j-1]) return dp[0][N-1] if name == "main": data = input().split() if data: N = int(data[0]) S = data[1] w = list(map(int, data[2:])) result = solve(N, S, w) print(result)

Lowercase import sys sys.setrecursionlimit(2000) input = sys.stdin.read def solve(N: int, S: str, w: list) -> int: if N == 0: return 0 dp = [[0] * N for _ in range(N)] for i in range(N): dp[i][i] = w[i] for length in range(2, N + 1): for i in range(N - length + 1): j = i + length - 1 if S[i] == S[j]: if length == 2: dp[i][j] = w[i] + w[j] else: dp[i][j] = dp[i+1][j-1] + w[i] + w[j] else: dp[i][j] = max(dp[i+1][j], dp[i][j-1]) return dp[0][N-1] if name == "main": data = input().split() if data: N = int(data[0]) S = data[1] w = list(map(int, data[2:])) result = solve(N, S, w) print(result)

13.3k after i will post ✅ All tests passed code will Upload again