అర్థమేటిక్ & రీజనింగ్ గ్రూప్

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a, a+1, a+2, a+3, a+4 be consecutive numbers a+2=21, a=19 Greatest number=19+4=23☑️

Bathikinchav

Here, whether it is (4th term -3rd term) or (3rd term -2nd term), is doubtful

D

650

Tq

B

Solution bro

36

B---F A---E C---D Opposite