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Repost from مكتبة القمم
حصراً لدى ❗️❗️❗️❗️❗️
متوفر الان
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| 2 | 🔸 Q: What is the effect of the force FB2 on the movement of the rod when applying the right-hand rule?
🔹A: We find that the force FB2 affects perpendicularly on the rod and towards the left, opposite to the direction of velocity (v) of the rod, therefore, this force obstruct the movement of the rod, it causes deceleration of the rod. | 509 |
| 3 | 🔸 Q: In order to keep the rod's velocity constant under these conditions, what is required?
🔹A: An external pulling force Fpull must be imposed toward the right, as follows: Fpull= FB2 | 462 |
| 4 | 🔸 Q: What is the direction of the induced current in the circuit if we apply the right-hand rule to a positive charge?
🔹A: The direction of the induced current in the circuit is counter clockwise. | 428 |
| 5 | 🔸 Q: What indicates the flow of current in the circuit when the rod is moved on the track?
🔹A: Glow of lamp, which is connected to the track in series combination. | 397 |
| 6 | 🔸 Q: What happens if a uniform magnetic field with a magnetic flux density (B) is exerted in a perpendicular direction to the plane of that circuit during the movement of the rod?
A: These positive charges in the rod will be affected by a magnetic force pushing it towards one end of the rod, while the negative charges are pushed to the other end. In this case, it will be
FB1 = qvB. Since this circuit is closed, charges will keep moving and don't gather at the ends of the rod, therefore, a current flows in the circuit, it is called Induced current. | 411 |
| 7 | 🔸 Reason: An external pulling force {Fpull} must be imposed to keep the rod moving at a constant velocity {v} inside the magnetic field?
A: This force obstructs the movement of the rod, it causes deceleration of the rod, which appears as a result of the flow of induced current and affects in a direction opposite to the direction of velocity. | 357 |
| 8 | 🔸 Reason: The lamp connected in series in the track circuit glows when the conducting rod is moved with a velocity perpendicularly to the magnetic field?
🔹A: As a result of the flow of current in the circuit, called induced current. | 377 |
| 9 | 🔸 Q: How can the rod be kept moving with a constant velocity (v) despite the presence of the opposing force {FB2}?
🔹A: In order to keep this rod's velocity constant under these conditions, an external pulling force {Fpull} must be imposed toward the right, as follows: Fpull = FB2. | 387 |
| 10 | 🔸 Q: How is the direction of the induced current in the circuit determined?
🔹A: If the right-hand rule is applied to a positive charge, the direction of the induced current in the circuit is counter clockwise. | 387 |
| 11 | Q: What happens to the positive and negative charges inside the rod when it moves perpendicularly to a uniform magnetic field with a magnetic flux density ({B})?
A: positive charges in the rod will be affected by a magnetic force pushing it towards one end of the rod, while the negative charges are pushed to the other end ({FB1 = qvB}). Since this circuit is closed, charges will keep moving and don't gather at the ends of the rod, therefore, a current flows in the circuit, it is called Induced current. Current flow in the circuit indicates the glow of lamp. | 482 |
| 12 | 🔸 is the practical procedure taken to flow an induced current in the moving rod inside a magnetic field?
🔹 rod is placed in a closed electric circuit, this process is made by sliding the rod at certain velocity (v) to the right along a conducting track U-shaped and connected to a lamp in series combination, this track is placed on a table, In this order, the rod, the track and the lamp becomes a closed electric circuit. | 489 |
| 13 | اليوم الاسئلة راح تكون لمنهج المتميزين 🤍 | 536 |
| 14 | مساء الخير 🤍 | 540 |
| 15 | https://www.instagram.com/reel/Dcy8t5xRVxl/?igsi=N2xrMm1xZ282bnB2
جولة من داخل أحد محاضرات الفيزياء للأستاذ
معتز الوادي لدفعة 2027🤩 | 687 |
| 16 |  جولة من داخل أحد محاضرات الفيزياء للأستاذ
معتز الوادي لدفعة 2027🤩 | 1 |
| 17 | 🔹 ما تأثر القوة FB2 في حركة الساق عند تطبيق قاعدة الكف اليمنى؟
🔸 نجد ان القوة FB2 توثر باتجاه عمودي على الساق ونحو اليسار اي باتجاه معاكس لاتجاه السرعة V التي تتحرك بها الساق، لذا فإن هذه القوة تعمل على عرقلة حركة الساق، فتتسبب في تباطؤ حركة الساق، | 730 |
| 18 | 🔹 لكي نجعل الساق تتحرك بسرعة ثابتة تحت هذه الظروف، ماذا يتطلب؟
🔸 يتطلب تسليط قوة خارجية Flull تسحب الساق نحو اليمين ومقدارها يساوي FB2 | 705 |
| 19 | 🔹 كيف يكون اتجاه التيار المحتث في الدائرة لو طبقنا قاعدة الكف اليمنى على الشحنة الموجبة؟
🔸 يكون اتجاه التيار المحتث في الدائرة معاكساً لاتجاه دوران عقارب الساعة. | 677 |
| 20 | 🔹 ما الذي يدل على إنسياب التيار في الدائرة عند تحريك الساق على السكة؟
🔸 توهج المصباح المربوط على التوالي مع السكة. | 644 |
