. ࣪⋆ STUDY ZONE ⋆ ࣪. 🇵🇸

4. Rajah 7 menunjukkan sebuah bulatan JKLQ. PQR ialah tangen kepada bulatan di Q. Diagram 7 shows a circle JKLQ. PQR is a tangent to the circle at the point Q. Cari nilai x Find value of x (disebabkan ada yang request, min bagi. kalau ramai jawab, min bagi lagi)

part c - 3(b)

part c - 3(a) formula penting! : TOA, SOH, CAH tan = opposite/adjecent sin = opposite/hypothenus cos = adjecent/hypothenus

part c - 2(b) nilai labur awal/the cost of investment = RM400 000 keuntungan modal/capital gain = harga jualan/sale price - modal - duti setem/stamp duty - komisen agen/agen's commission - kos guaman/legal fees = RM580 000 - RM400 000 - RM3 000 - RM4 900 - RM7 500 = RM164 600 jumlah pulangan /total return = keuntungan modal/capital gain + sewa/rent = RM164 600 + (RM1850 x 12 x 7) = RM320 000 nilai pulangan pelaburan/return on investment = jumlah pulangan/total return ÷ nilai pelaburan awal/the cost of investment = RM320 000 / RM400 000 x 100% = 80%

part c - 2(a) faedah bulan pertama/first month interest = rate x 1/12 x P = 4/100 x 1/12 x RM15 000 = RM50 baki selepas bayar ansuran bulan pertama/ balance after first instalment = P + faedah bulan pertama/first month interest - bayaran ansuran bulanan/monthly instalment = RM15 000 + RM50 - RM200 = RM14 850 faedah bulan kedua/second month interest = 4/100 x 1/12 x RM14 850 = RM49.50 baki selepas bayar ansuran bulan kedua/balance after second instalment = RM14 850 + RM49.50 - RM200 = RM14 699.50 jumlah faedah pada bulan pertama/amount of interest in the first two months = faedah bulan pertama + faedah bulan kedua = RM50 + RM49.50 = RM99.50

part c - 1(b)

part c - 1(a) (i) 2^6 = [ 64 ] (ii) [ 6^4 ] = 1296 (iii) (2/5)^3 = [ 8/125 ] (iv) [ (-3)^5 ] = -243

part b - 5 y = mx + c y = -2x + 3 2y + 4x = 6 2y = -4x + 6 y = (-4x + 6) 1/2 y = -2x + 3 -4y - 8x = 12 -4y = 8x + 12 y = (8x + 12) (-1/4) y = -2x - 3 m = -2

part b (4) (i) jumlah pinjaman / total loan = principal - down payment/ bayaran pendahuluan so, down payment / wang pendahuluan = 10/100 x RM65 000 = RM58 500 (ii) faedah pinjaman/loan interest = Prt (Principal x rate/kadar x time/tempoh = Prt = RM58 500 x 0.034 x 9 = RM17 901 (iii) jumlah bayar balik/total repayment = P + Prt = P + Prt = RM58 500 + RM17 901 (ambil je dari atas) = RM76 401 (iv) bayaran ansuran bulanan/ monthly instalment payment = P + Prt / t x 12 = P + Prt / t x 12 = RM76 401 / 9 x 12 = RM707.42

part b (3) btw utk ni , perasan tak lukisan berskala / scale drawing tu ada nilai/value 1? so the easiest way, use it instead of 2:6 . but if you are not confident or wanna show the way to get answer, okay je . so, skala/scale = 1 : 3

jawapan part b soalan 2 (sorry tulisan buruk haha)

jawapan part b soalan 1

yang salah, jangan give up. try jawab lagii mana tau betul. yang tak jawab lagi , cubalah jawab. biar salah asalkan buat. anggap la ni sebahagian daripada latihan untuk UASA. kalau korang tak jawab, min dah taknak buat la.

okay korang, min akan tunjuk cara nak dapatkan jawapan bagi setiap soalan. ke tak nak?

3. (b) Dalam Rajah 5, PQR ialah garis lurus dan PQ = QR. In Diagram 5, PQR is a straight line and PQ = QR. Cari nilai bagi, Find the value of, (i) kos/cos n (ii) tan m (iii) nilai m, dalam darjah dan minit (4 markah/marks)

3. (a) Rajah 4 menunjukkan dua segi tiga bersudut tegak ABC dan CDE. Diberi panjang AE = 12 cm dan panjang EC = 5 cm. Diagram 4 shows two right-angled triangles ABC and CDE. Given the length of AE = 12 cm and the length of EC = 5 cm. Nyatakan nisbah trigonometri bagi State the trigonometric ratio of (i) tan q (ii) sin p (iii) kos/cos r (iv) tan s (4 markah/marks)

2. (b) Encik Zairi menerima wang persaraan bernilai RM40 000. Encik Zairi menggunakan semua wang itu untuk membeli sebuah rumah. Selepas 7 tahun, Encik Zairi berhasrat untuk menjual rumahnya dengan harga RM580 000. Sepanjang tempoh itu, Encik Zairi telah menerima sewa sebanyak RM1 850 sebulan. Pernyataan di bawah menunjukkan perbelanjaan yang terlibat. Mr Zairi received a gratuity worth RM400 000. Mr Zairi used all the money to buy a house. After 7 years, Mr Zairi intends to sell his house for RM580 000. During that period, Mr Zairi received a rental of RM1 850 per month. Statement below shows the expenses involved. Duti setem / Stamp duty - RM3 000 Komisen agen / Agent's commission - RM4 900 Kos guaman / Legal fees - RM7 500 Hitung nilai pulangan pelaburan Encik Zairi. Calculate the return on investment for Mr Zairi. (3 markah / marks) tunjuk jalan kira / show the way you got the answer

2. (a) Encik Kamal membuat pinjaman peribadi sebanyak RM15 000 dari sebuah bank dengan kadar faedah 4% setahun. Dia membayar RM200 secara ansuran setiap bulan dalam tempoh 7 tahun. Berapakah jumlah faedah yang perlu dibayar oleh Encik Kamal pada dua bulan pertama? Mr Kamal took a personal loan of RM15 000 from a bank with an interest rate of 4% per annum. He pays RM200 in monthly instalments over a period of 7 years. What is the amount of interest Mr Kamal has to pay in the first two months? (4 markah / marks) Sila tunjuk jalan kira. / please show the way you got the answer.

1. (a) Isi tempat kosong dengan jawapan yang betul. Fill in the blanks with the correct answer. (i) 2^6 = [ ] (ii) [ ] = 1296 (iii) (2/5)^3 = [ ] (iv) [ ] = -243 (4 markah/marks) (b) Permudahkan setiap yang berikut. Simplify each of the following. (i) 5h^2 × 6h^3 = (ii) p^10 ÷ p^6 ÷ p^-1 = (iii) (8^3 × 2^2)^2 = (3 markah / marks)