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🤡TCS NQT Exam August 15th help will be done
🛑Genuine Help 100% guaranteed clearance👍 booking will start from Tomorrow 😍
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@tcs_nqt_answers_August
TCS PRA JAVA MCQ
1)grep status file1
2)Xp training
3)option C
4) option B
5)true
6)false
7) truncate
8)alter
9) option B
10) option A
11) option A
12) option C
13) option A
14)B,D
15)all of the above
16) option A
17) strong
18) option A
19) option B
20)h1
21)span
22) object
23)10
24)Go Green45
26) JDK
25)OPTION B
27)0
28) option A
29)false
30)easy to learn
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TCS PRA JAVA MCQ
1)grep status file1
2)Xp training
3)option C
4) option B
5)true
6)false
7) truncate
8)alter
9) option B
10) option A
11) option A
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Hexaware (only for 2023 batch)
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TCS IRA
1) All of the above
2)Excellence
3)IBM Watson
4)All of the above
5)Application Caching
6)A
7)Accurate and affrimative
8)Order
9)All of the above
10)C
11)wc-r
12)Option A ( to exit stauts special shell..)
13)>>symbol
14)h
15)?unix directory
16)B
17)B
18)IN
19)All the above will be printed
20)D
21)C
22)B
23)B
24)C
25)D
26)<th colspan="2">2020</th>
27)B
28)
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Maximum multiple code in python 3
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Kth max code in java
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#include <stdio.h>
int main() {
int n, reverse = 0, remainder;
scanf("%d", &n);
int p=n;
while (n != 0) {
remainder = n % 10;
reverse = reverse * 10 + remainder;
n /= 10;
}
int c=reverse -p;
int d=abs(c);
printf(" %d", d);
return 0;
}
Code in c
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#include <stdio.h>
int main()
{
char str[100];
int counter;
printf("Enter a string: ");
gets(str);
// toggle each string characters
for (counter = 0; str[counter] != NULL; counter++) {
if (str[counter] >= 'A' && str[counter] <= 'Z')
str[counter] = str[counter] + 32; //convert into lower case
else if (str[counter] >= 'a' && str[counter] <= 'z')
str[counter] = str[counter] - 32; //convert into upper case
}
printf("String after toggle each characters: %s", str);
return 0;
}
Language : C
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int diff_primes_in_ranges(int input1, int intput2)
{
int ans = 0;
int i, j, flag;
for (i = input1; i <= intput2; i++)
{
if (i == 1 || i == 0)
continue;
flag = 1;
for (j = 2; j <= i / 2; ++j)
{
if (i % j == 0)
{
flag = 0;
break;
}
}
if (flag == 1)
ans++;
}
return ans;
}
KPIT SOLUTION:- C++
int k=input1/2000;
input1=input1%2000;
k=k+input1/500;
input1=input1%500;
k=k+input1/200;
input1=input1%200;
k=k+input1/100;
input1=input1%100;
return k;
