CODING SOLUTION - Placement Jobs & Materials
前往频道在 Telegram
🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “ Contact Admin: Mail me for collab offcampusjobsindiaadmin@gmail.com instagram.com/offcampusjobsindia_it Our Website : www.offcampusjobsindia.com
显示更多📈 Telegram 频道 CODING SOLUTION - Placement Jobs & Materials 的分析概览
频道 CODING SOLUTION - Placement Jobs & Materials (@codingsolution_it) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 128 532 名订阅者，在 职业 类别中位列第 157，并在 印度 地区排名第 1 673 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 128 532 名订阅者。
根据 04 十一月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -1 671，过去 24 小时变化为 -57，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 1.58%。内容发布后 24 小时内通常能获得 0.43% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 2 030 次浏览，首日通常累积 553 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 0。
- 主题关注点： 内容集中在 t.me/codingsolution_it, vector, codevita, string, graduate 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “
Contact Admin:
Mail me for collab
offcampusjobsindiaadmin@gmail.com
instagram.com/offcampusjobsindia_it
Our Website :
www.offcampusjobsindia.com”
凭借高频更新（最新数据采集于 05 十一月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 职业 类别中的关键影响点。
128 532
订阅者
-5724 小时
-4647 天
-1 67130 天
帖子存档
QBURST EXAM SOLUTION GROUP:
telegram.me/codingsolution_IT
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QBURST EXAM SOLUTION GROUP:
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QBURST EXAM SOLUTION GROUP:
telegram.me/codingsolution_IT
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QBURST EXAM SOLUTION GROUP:
telegram.me/codingsolution_IT
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QBURST EXAM SOLUTION GROUP:
telegram.me/codingsolution_IT
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QBURST EXAM SOLUTION GROUP:
telegram.me/codingsolution_IT
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CAPGEMINI EXAM 5PM SOLUTION GROUP:
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JMAN, CAPGEMINI & QBURST EXAM SOLUTION GROUP:
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JMAN, CAPGEMINI & QBURST EXAM SOLUTION GROUP:
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2) telegram.me/+wxfAMtYpHoMxZjNl
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Mindtree & Wingify Off Campus
🎖 Batch - 2023 2022 2021 2020 2019
https://youtu.be/s_28zU3JDuM
Telegram - t.me/engineerjobsindiaPython Most Asked Interview Qns & Ans:
Telegram - t.me/studymaterial_IT
⚠️ ALL SLOTS SOLUTION GROUP: ⚠️
ATOS - t.me/atos_syntel_exam_discusion
CAPGEMINI - t.me/capgemini_exam_discussion_group
QSPIDERS - t.me/qspiders_exam_discussion_group
QUANTIPHI - t.me/quantiphi_exam_discussion_group
t.me/codingsolution_IT
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Getting shortlisted for Interviews is an altogether different ball game from just being good in DSA.
Here is how you can increase your chances of getting Interview Calls by upto 5x 🔥.
Attend AlgoUniversity's Flagship event AlgoTalks to learn, How to get up to 5x 🚀 more Interview Calls 💯 directly from the Founder & COO of AlgoUniversity Swapnil Daga who’s previously worked in Google-London & Apple.
These are the 5 topics to be covered in Thursday's session:
1️⃣ How can you get upto 5x more Interview Calls?
2️⃣ How can you apply & crack International Offers?
3️⃣ Roadmap to learn DSA effectively?
4️⃣ Framework to select which DSA problems to solve?
5️⃣ How to maintain consistency in prep along with a full-time job?
This is going to be an invite-only session.
🗓️ Date & Time: Thursday, 3rd November @ 8.30 PM ( IST )
Registration link ⏩ https://bit.ly/3sN2oOy
Make sure you don’t miss this opportunity to learn from a few of the best folks in India 🇮🇳.
#InterviewHacks
(Playlist)
Latest TCS Interview Experience
📌Link: https://bit.ly/3QzYCS6
Telegram - telegram.me/studymaterial_IT⚠️ ALL SLOTS SOLUTION GROUP: ⚠️
ATOS - t.me/atos_syntel_exam_discusion
CAPGEMINI - t.me/capgemini_exam_discussion_group
QSPIDERS - t.me/qspiders_exam_discussion_group
QUANTIPHI - t.me/quantiphi_exam_discussion_group
t.me/codingsolution_IT
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ATOS EXAM SOLUTION GROUP:
telegram.me/codingsolution_IT
t.me/atos_syntel_exam_discusion
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TCS NQT EXAM 6PM SOLUTION GROUP:
telegram.me/codingsolution_IT
1) t.me/+J8xn_MBM7fkxODNl
2) telegram.me/+V7_OuuZWqTAwZWZl
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📌I Hope TCS Exam Over for Everyone?
📝 My Instagram ID:
Instagram.com/offcampusjobindia
⚠️Notice - Follow Me There I'm Posting Interview Question & Many More. I Will Guide you how you can Crack Interview.
Python
Vishal (TCS 2nd Qsn)
Telegram - t.me/codingsolution_IT
#include<bits/stdc++.h>
using namespace std;
int find(int n1, int n2) {
int count = 0;
for (int i = n1 ; i <= n2 ; i++) {
int num = i;
vector<bool> visited;
visited.assign(10, false);
while (num > 0) {
if (visited[num % 10] == true)
break;
visited[num % 10] = true;
num /= 10;
}
if (num == 0)
count++;
}
return count;
}
int main()
{
int n1 = 101, n2 = 200;
cout << find(n1, n2);
}
C++ ✅✅
Raju code
Telegram - t.me/codingsolution_IT
